
Concept explainers
Answers to all problems are at the end of this book. Detailed solutions are available in the Student Solutions Manual, Study Guide, and Problems Book.
The Structure and Ionization Properties of

Interpretation: The principal ionic species of
Concept introduction: A nucleotide refers to a basic DNA building block and structural unit. It contains a five-sided sugar, a phosphate group and a nitrogenous base. The nucleotides join together to form a chain of DNA. The nucleotides of DNA and RNA are linked covalently by bridges of the phosphate group. A phosphodiester linkage joins the
Answer to Problem 1P
The principal ionic species of
Explanation of Solution
In the polar backbone of DNA and RNA, the phosphate groups are completely ionizable and negatively charged at
Figure 1
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Chapter 10 Solutions
EBK BIOCHEMISTRY
- The following data were recorded for the enzyme catalyzed conversion of S -> P. Question: Estimate the Vmax and Km. What would be the rate at 2.5 and 5.0 x 10-5 M [S] ?arrow_forwardPlease helparrow_forwardThe following data were recorded for the enzyme catalyzed conversion of S -> P Question: what would the rate be at 5.0 x 10-5 M [S] and the enzyme concentration was doubled? Also, the rate given in the table is from product accumulation after 10 minuets of reaction time. Verify these rates represent a true initial rate (less than 5% turnover). Please helparrow_forward
- The following data was obtained on isocitrate lyase from an algal species. Identify the reaction catalyzed by this enzyme, deduce the KM and Vmax , and determine the nature of the inhibition by oxaloacetate. Please helparrow_forwardIn the table below, there are sketches of four crystals made of positively-charged cations and negatively-charged anions. Rank these crystals in decreasing order of stability (or equivalently increasing order of energy). That is, select "1" below the most stable (lowest energy) crystal. Select "2" below the next most stable (next lowest energy) crystal, and so forth. A B 鹽 (Choose one) +2 C +2 +2 (Choose one) D 鹽雞 (Choose one) (Choose one)arrow_forward1. Draw the structures for the fats A. 16:2: w-3 and B. 18:3:49,12,15 2. Name each of the molecules below (image attached)arrow_forward
- draw the structures for the fats A. 16:2:w-3 B 18:3:9,12,15arrow_forward1. Below is a template strand of DNA. Show the mRNA and protein that would result. label the ends of the molecules ( refer to attached image)arrow_forwardAttach the followina labels to the diagram below: helicase, single stranded binding proteins, lagging strand, leading strand, DNA polymerase, primase, 5' ends (3), 3' ends (3) (image attached)arrow_forward
- 1. How much energy in terms of ATP can be obtained from tristearin (stearate is 18:0) Show steps pleasearrow_forwardMultiple choice urgent!!arrow_forward1. Write the transamination reaction for alanine. Indicate what happens next to each of the molecules in the reaction, and under what conditions it happens. 2.arrow_forward
- BiochemistryBiochemistryISBN:9781305577206Author:Reginald H. Garrett, Charles M. GrishamPublisher:Cengage Learning
