To conclude: About the linear correlationbetween the numbers of enrolled students and numbers of burglaries.

Question

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Answer 1

Question

Chapter 10, Problem 1CQQ

To determine

To conclude: About the linear correlationbetween the numbers of enrolled students and numbers of burglaries.

Expert Solution & Answer

Answer to Problem 1CQQ

There is no sufficient evidence to support the claim that there is a linear correlation between the numbers of enrolled students and numbers of burglaries.

Explanation of Solution

Given info:

The data shows that the numbers of enrolled students (in thousands) and the numbers of burglaries. The correlation value is 0.499, the critical values at 0.05 level of significance for r is ±0.878 and P-value for r is 0.393.

Calculation:

The hypotheses are given below:

Null hypothesis:

H0:ρ=0

That is, there is no linear correlation betweenthe numbers of enrolled students and the numbers of burglaries.

Alternative hypothesis:

H1:ρ≠0

That is, there is a linear correlation between the numbers of enrolled students and the numbers of burglaries.

Conclusion:

The P-value is 0.393 and the level of significance is 0.05.

Here, the P-value is greater than the level of significance.

Hence, the null hypothesis isnot rejected. That is, there is no linear correlation betweenthe numbers of enrolled students and the numbers of burglaries.

The critical value is ±0.878.

Here, the correlation value is 0.499 which lies between the critical values.

Hence, the null hypothesis isnot rejected.

Thus, there is nosufficient evidence to support the claim that there is a linear correlation betweenthe numbers of enrolled students and the numbers of burglaries.

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Answer 2

Question

Chapter 10, Problem 1CQQ

To determine

To conclude: About the linear correlationbetween the numbers of enrolled students and numbers of burglaries.

Expert Solution & Answer

Answer to Problem 1CQQ

There is no sufficient evidence to support the claim that there is a linear correlation between the numbers of enrolled students and numbers of burglaries.

Explanation of Solution

Given info:

The data shows that the numbers of enrolled students (in thousands) and the numbers of burglaries. The correlation value is 0.499, the critical values at 0.05 level of significance for r is ±0.878 and P-value for r is 0.393.

Calculation:

The hypotheses are given below:

Null hypothesis:

H0:ρ=0

That is, there is no linear correlation betweenthe numbers of enrolled students and the numbers of burglaries.

Alternative hypothesis:

H1:ρ≠0

That is, there is a linear correlation between the numbers of enrolled students and the numbers of burglaries.

Conclusion:

The P-value is 0.393 and the level of significance is 0.05.

Here, the P-value is greater than the level of significance.

Hence, the null hypothesis isnot rejected. That is, there is no linear correlation betweenthe numbers of enrolled students and the numbers of burglaries.

The critical value is ±0.878.

Here, the correlation value is 0.499 which lies between the critical values.

Hence, the null hypothesis isnot rejected.

Thus, there is nosufficient evidence to support the claim that there is a linear correlation betweenthe numbers of enrolled students and the numbers of burglaries.

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Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 3

Question

Chapter 10, Problem 1CQQ

To determine

To conclude: About the linear correlationbetween the numbers of enrolled students and numbers of burglaries.

Expert Solution & Answer

Answer to Problem 1CQQ

There is no sufficient evidence to support the claim that there is a linear correlation between the numbers of enrolled students and numbers of burglaries.

Explanation of Solution

Given info:

The data shows that the numbers of enrolled students (in thousands) and the numbers of burglaries. The correlation value is 0.499, the critical values at 0.05 level of significance for r is ±0.878 and P-value for r is 0.393.

Calculation:

The hypotheses are given below:

Null hypothesis:

H0:ρ=0

That is, there is no linear correlation betweenthe numbers of enrolled students and the numbers of burglaries.

Alternative hypothesis:

H1:ρ≠0

That is, there is a linear correlation between the numbers of enrolled students and the numbers of burglaries.

Conclusion:

The P-value is 0.393 and the level of significance is 0.05.

Here, the P-value is greater than the level of significance.

Hence, the null hypothesis isnot rejected. That is, there is no linear correlation betweenthe numbers of enrolled students and the numbers of burglaries.

The critical value is ±0.878.

Here, the correlation value is 0.499 which lies between the critical values.

Hence, the null hypothesis isnot rejected.

Thus, there is nosufficient evidence to support the claim that there is a linear correlation betweenthe numbers of enrolled students and the numbers of burglaries.

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Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 4

Question

Chapter 10, Problem 1CQQ

To determine

To conclude: About the linear correlationbetween the numbers of enrolled students and numbers of burglaries.

Expert Solution & Answer

Answer to Problem 1CQQ

There is no sufficient evidence to support the claim that there is a linear correlation between the numbers of enrolled students and numbers of burglaries.

Explanation of Solution

Given info:

The data shows that the numbers of enrolled students (in thousands) and the numbers of burglaries. The correlation value is 0.499, the critical values at 0.05 level of significance for r is ±0.878 and P-value for r is 0.393.

Calculation:

The hypotheses are given below:

Null hypothesis:

H0:ρ=0

That is, there is no linear correlation betweenthe numbers of enrolled students and the numbers of burglaries.

Alternative hypothesis:

H1:ρ≠0

That is, there is a linear correlation between the numbers of enrolled students and the numbers of burglaries.

Conclusion:

The P-value is 0.393 and the level of significance is 0.05.

Here, the P-value is greater than the level of significance.

Hence, the null hypothesis isnot rejected. That is, there is no linear correlation betweenthe numbers of enrolled students and the numbers of burglaries.

The critical value is ±0.878.

Here, the correlation value is 0.499 which lies between the critical values.

Hence, the null hypothesis isnot rejected.

Thus, there is nosufficient evidence to support the claim that there is a linear correlation betweenthe numbers of enrolled students and the numbers of burglaries.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 5

Chapter 10, Problem 1CQQ

To determine

To conclude: About the linear correlationbetween the numbers of enrolled students and numbers of burglaries.

Expert Solution & Answer

Answer to Problem 1CQQ

There is no sufficient evidence to support the claim that there is a linear correlation between the numbers of enrolled students and numbers of burglaries.

Explanation of Solution

Given info:

The data shows that the numbers of enrolled students (in thousands) and the numbers of burglaries. The correlation value is 0.499, the critical values at 0.05 level of significance for r is ±0.878 and P-value for r is 0.393.

Calculation:

The hypotheses are given below:

Null hypothesis:

H0:ρ=0

That is, there is no linear correlation betweenthe numbers of enrolled students and the numbers of burglaries.

Alternative hypothesis:

H1:ρ≠0

That is, there is a linear correlation between the numbers of enrolled students and the numbers of burglaries.

Conclusion:

The P-value is 0.393 and the level of significance is 0.05.

Here, the P-value is greater than the level of significance.

Hence, the null hypothesis isnot rejected. That is, there is no linear correlation betweenthe numbers of enrolled students and the numbers of burglaries.

The critical value is ±0.878.

Here, the correlation value is 0.499 which lies between the critical values.

Hence, the null hypothesis isnot rejected.

Thus, there is nosufficient evidence to support the claim that there is a linear correlation betweenthe numbers of enrolled students and the numbers of burglaries.

Answer 6

Chapter 10, Problem 1CQQ

To determine

To conclude: About the linear correlationbetween the numbers of enrolled students and numbers of burglaries.

Expert Solution & Answer

Answer to Problem 1CQQ

There is no sufficient evidence to support the claim that there is a linear correlation between the numbers of enrolled students and numbers of burglaries.

Explanation of Solution

Given info:

The data shows that the numbers of enrolled students (in thousands) and the numbers of burglaries. The correlation value is 0.499, the critical values at 0.05 level of significance for r is ±0.878 and P-value for r is 0.393.

Calculation:

The hypotheses are given below:

Null hypothesis:

H0:ρ=0

That is, there is no linear correlation betweenthe numbers of enrolled students and the numbers of burglaries.

Alternative hypothesis:

H1:ρ≠0

That is, there is a linear correlation between the numbers of enrolled students and the numbers of burglaries.

Conclusion:

The P-value is 0.393 and the level of significance is 0.05.

Here, the P-value is greater than the level of significance.

Hence, the null hypothesis isnot rejected. That is, there is no linear correlation betweenthe numbers of enrolled students and the numbers of burglaries.

The critical value is ±0.878.

Here, the correlation value is 0.499 which lies between the critical values.

Hence, the null hypothesis isnot rejected.

Thus, there is nosufficient evidence to support the claim that there is a linear correlation betweenthe numbers of enrolled students and the numbers of burglaries.

Answer 7

Chapter 10, Problem 1CQQ

To determine

To conclude: About the linear correlationbetween the numbers of enrolled students and numbers of burglaries.

Answer 8

Expert Solution & Answer

Answer to Problem 1CQQ

There is no sufficient evidence to support the claim that there is a linear correlation between the numbers of enrolled students and numbers of burglaries.

Answer 9

Expert Solution & Answer

Answer 10

Expert Solution & Answer

Answer 11

Explanation of Solution

Given info:

The data shows that the numbers of enrolled students (in thousands) and the numbers of burglaries. The correlation value is 0.499, the critical values at 0.05 level of significance for r is ±0.878 and P-value for r is 0.393.

Calculation:

The hypotheses are given below:

Null hypothesis:

H0:ρ=0

That is, there is no linear correlation betweenthe numbers of enrolled students and the numbers of burglaries.

Alternative hypothesis:

H1:ρ≠0

That is, there is a linear correlation between the numbers of enrolled students and the numbers of burglaries.

Conclusion:

The P-value is 0.393 and the level of significance is 0.05.

Here, the P-value is greater than the level of significance.

Hence, the null hypothesis isnot rejected. That is, there is no linear correlation betweenthe numbers of enrolled students and the numbers of burglaries.

The critical value is ±0.878.

Here, the correlation value is 0.499 which lies between the critical values.

Hence, the null hypothesis isnot rejected.

Thus, there is nosufficient evidence to support the claim that there is a linear correlation betweenthe numbers of enrolled students and the numbers of burglaries.