EBK ENHANCED DISCOVERING COMPUTERS & MI
1st Edition
ISBN: 9780100606920
Author: Vermaat
Publisher: YUZU
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Expert Solution & Answer
Chapter 10, Problem 13SG
Explanation of Solution
Network Standard:
- Standard refers to the quality of the products or services i.e it defines the rules for creating and maintaining the products or services for different vendors to utilize based on the quality of their products.
- Network standard is the set of defined rules or guidelines for data communication in network.
- Many standards are used for maintaining a network like, for wireless data communication 802.11a is used and for wired data communication Ethernet, Gigabit Ethernet is used.
- Each standard has a specific purpose.
Protocols:
- When transferring information from one end to another end, the user must need a data format or template at each end so that the end user can understand it.
- Protocols define the format for sending the information as well as for receiving the information at another end...
Explanation of Solution
Justification:
- Network standards and protocols work together to transfer the data from one end to another through network.
- Standards specify how the network is arranged physically and defines the guidelines that the user agrees to follow and protocols specify how the data traverse over the network...
Expert Solution & Answer
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Exercise 1 Function and Structure [30 pts]
Please debug the following program and answer the following questions. There is a cycle in a linked
list if some node in the list can be reached again by continuously following the next pointer.
#include
typedef struct node {
int value;
struct node *next;
} node;
int 11_has_cycle (node *first)
if (first
==
node *head
{
NULL) return 0;B
= first;
while (head->next != NULL) {
if (head == first) {
return 1; }
head
head->next;
}
return 0;
void test_11_has_cycle() {
int i;
node nodes [6];
for (i = 0; i < 6; i++)
nodes [i] .next = NULL;
nodes [i].value
i;
}
nodes [0] .next
=
&nodes [1];
nodes [1] .next = &nodes [2];
nodes [2] .next
=
&nodes [3];
nodes [3] .next = & nodes [4];
nodes [4] .next
=
NULL;
nodes [5] .next = &nodes [0];
printf("1. Checking first list for cycles. \n Function 11_has_cycle says it
hass cycle\n\n", 11_has_cycle (&nodes [0]) ?"a":"no");
printf("2. Checking length-zero list for cycles. \n Function 11_has_cycle
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Chapter 10 Solutions
EBK ENHANCED DISCOVERING COMPUTERS & MI
Ch. 10 - Prob. 1SGCh. 10 - Prob. 2SGCh. 10 - Prob. 3SGCh. 10 - Prob. 4SGCh. 10 - Prob. 5SGCh. 10 - Prob. 6SGCh. 10 - Prob. 7SGCh. 10 - Prob. 8SGCh. 10 - Prob. 9SGCh. 10 - Prob. 10SG
Ch. 10 - Prob. 11SGCh. 10 - Prob. 12SGCh. 10 - Prob. 13SGCh. 10 - Prob. 14SGCh. 10 - Prob. 15SGCh. 10 - Prob. 16SGCh. 10 - Prob. 17SGCh. 10 - Prob. 18SGCh. 10 - Prob. 19SGCh. 10 - Prob. 20SGCh. 10 - Prob. 21SGCh. 10 - Prob. 22SGCh. 10 - Prob. 23SGCh. 10 - Prob. 24SGCh. 10 - Prob. 25SGCh. 10 - Prob. 26SGCh. 10 - Prob. 27SGCh. 10 - Prob. 28SGCh. 10 - Prob. 29SGCh. 10 - Prob. 30SGCh. 10 - Prob. 31SGCh. 10 - Prob. 32SGCh. 10 - Prob. 33SGCh. 10 - Prob. 34SGCh. 10 - Prob. 35SGCh. 10 - Prob. 36SGCh. 10 - Prob. 37SGCh. 10 - Prob. 38SGCh. 10 - Prob. 39SGCh. 10 - Prob. 40SGCh. 10 - Prob. 41SGCh. 10 - Prob. 42SGCh. 10 - Prob. 43SGCh. 10 - Prob. 44SGCh. 10 - Prob. 45SGCh. 10 - Prob. 46SGCh. 10 - Prob. 47SGCh. 10 - Prob. 48SGCh. 10 - Prob. 49SGCh. 10 - Prob. 1TFCh. 10 - Prob. 2TFCh. 10 - Prob. 3TFCh. 10 - Prob. 4TFCh. 10 - Prob. 5TFCh. 10 - Prob. 6TFCh. 10 - Prob. 7TFCh. 10 - Prob. 8TFCh. 10 - Prob. 9TFCh. 10 - Prob. 10TFCh. 10 - Prob. 11TFCh. 10 - Prob. 12TFCh. 10 - Prob. 1MCCh. 10 - Prob. 2MCCh. 10 - Prob. 3MCCh. 10 - Prob. 4MCCh. 10 - Prob. 5MCCh. 10 - Prob. 6MCCh. 10 - Prob. 7MCCh. 10 - Prob. 8MCCh. 10 - Prob. 1MCh. 10 - Prob. 2MCh. 10 - Prob. 3MCh. 10 - Prob. 4MCh. 10 - Prob. 5MCh. 10 - Prob. 6MCh. 10 - Prob. 7MCh. 10 - Prob. 8MCh. 10 - Prob. 9MCh. 10 - Prob. 10MCh. 10 - Prob. 2CTCh. 10 - Prob. 3CTCh. 10 - Prob. 4CTCh. 10 - Prob. 5CTCh. 10 - Prob. 6CTCh. 10 - Prob. 7CTCh. 10 - Prob. 8CTCh. 10 - Prob. 9CTCh. 10 - Prob. 10CTCh. 10 - Prob. 11CTCh. 10 - Prob. 12CTCh. 10 - Prob. 13CTCh. 10 - Prob. 14CTCh. 10 - Prob. 15CTCh. 10 - Prob. 16CTCh. 10 - Prob. 17CTCh. 10 - Prob. 18CTCh. 10 - Prob. 19CTCh. 10 - Prob. 20CTCh. 10 - Prob. 21CTCh. 10 - Prob. 22CTCh. 10 - Prob. 23CTCh. 10 - Prob. 24CTCh. 10 - Prob. 25CTCh. 10 - Prob. 26CTCh. 10 - Prob. 27CTCh. 10 - Prob. 1PSCh. 10 - Prob. 2PSCh. 10 - Prob. 3PSCh. 10 - Prob. 4PSCh. 10 - Prob. 5PSCh. 10 - Prob. 6PSCh. 10 - Prob. 7PSCh. 10 - Prob. 8PSCh. 10 - Prob. 9PSCh. 10 - Prob. 10PSCh. 10 - Prob. 11PSCh. 10 - Prob. 1.1ECh. 10 - Prob. 1.2ECh. 10 - Prob. 1.3ECh. 10 - Prob. 2.1ECh. 10 - Prob. 2.2ECh. 10 - Prob. 2.3ECh. 10 - Prob. 3.1ECh. 10 - Prob. 3.2ECh. 10 - Prob. 3.3ECh. 10 - Prob. 4.1ECh. 10 - Prob. 4.2ECh. 10 - Prob. 4.3ECh. 10 - Prob. 1IRCh. 10 - Prob. 2IRCh. 10 - Prob. 3IRCh. 10 - Prob. 4IRCh. 10 - Prob. 5IRCh. 10 - Prob. 1CTQCh. 10 - Prob. 2CTQCh. 10 - Prob. 3CTQCh. 10 - Prob. 4CTQ
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