
EBK COMPUTING ESSENTIALS 2019
27th Edition
ISBN: 8220106797457
Author: O'LEARY
Publisher: YUZU
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Chapter 10, Problem 13CC
Program Plan Intro
The purpose of the decision support system.
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Exercise 1 Function and Structure [30 pts]
Please debug the following program and answer the following questions. There is a cycle in a linked
list if some node in the list can be reached again by continuously following the next pointer.
#include
typedef struct node {
int value;
struct node *next;
} node;
int 11_has_cycle (node *first)
if (first
==
node *head =
{
NULL) return 0;
first;
while (head->next != NULL) {
}
if (head
first) {
return 1; }
head = head->next;
return 0;
void test ll_has_cycle () {
int i;
node nodes [6];
for (i = 0; i < 6; i++) {
nodes [i] .next = NULL;
nodes [i].value = i;
}
nodes [0] .next
=
&nodes [1];
nodes [1] .next
=
&nodes [2];
nodes [2] .next
=
&nodes [3];
nodes [3] .next
nodes [4] .next
&nodes [4];
NULL;
nodes [5] .next = &nodes [0];
printf("1. Checking first list for cycles. \n Function 11_has_cycle says it
has s cycle\n\n", 11_has_cycle (&nodes [0])?"a":"no");
printf("2. Checking length-zero list for cycles. \n Function 11_has_cycle
says it has %s…
how to read log logs
Discrete Mathematics for Computer Engineering
Chapter 10 Solutions
EBK COMPUTING ESSENTIALS 2019
Ch. 10 - Prob. 1CCCh. 10 - Prob. 2CCCh. 10 - Prob. 3CCCh. 10 - Prob. 4CCCh. 10 - Prob. 5CCCh. 10 - What is an executive support system? Who uses it?...Ch. 10 - Prob. 7CCCh. 10 - Prob. 8CCCh. 10 - Prob. 9CCCh. 10 - Prob. 10CC
Ch. 10 - Prob. 11CCCh. 10 - Prob. 12CCCh. 10 - Prob. 13CCCh. 10 - Prob. 14CCCh. 10 - Prob. 15CCCh. 10 - Prob. 16CCCh. 10 - Prob. 17CCCh. 10 - Prob. 18CCCh. 10 - Prob. 19CCCh. 10 - Prob. 20CCCh. 10 - Prob. 21CCCh. 10 - Prob. 22CCCh. 10 - Prob. 1MCCh. 10 - Prob. 2MCCh. 10 - Prob. 3MCCh. 10 - Prob. 4MCCh. 10 - Prob. 5MCCh. 10 - Prob. 6MCCh. 10 - Prob. 7MCCh. 10 - Prob. 8MCCh. 10 - Prob. 9MCCh. 10 - Prob. 10MCCh. 10 - Prob. 1MCh. 10 - Prob. 1OECh. 10 - Prob. 2OECh. 10 - Prob. 3OECh. 10 - Prob. 4OECh. 10 - Prob. 5OECh. 10 - Prob. 1DCh. 10 - Prob. 2D
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