EBK NEW PERSPECTIVES ON HTML5, CSS3, AN
6th Edition
ISBN: 9781337516358
Author: Carey
Publisher: CENGAGE LEARNING - CONSIGNMENT
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Question
Chapter 10, Problem 12CP1
a.
Program Plan Intro
To create a for loop that loops through the item array in tc_cart.js.
b.
Program Plan Intro
To add the given HTML code to the cartHtml variable that displays the description, price and quantity ordered in tc_cart.js.
c.
Program Plan Intro
To declare a variable named itemCost which is equal to the price multiplied by the quantity for the current item in tc_cart.js.
d.
Program Plan Intro
To add the given HTML code to the cartHtml variable that displays the cost for the item in tc_cart.js.
e.
Program Plan Intro
To add the value of itemCost to the orderTotal variable to keep a running total of the total cost of the customer order in tc_cart.js.
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I need help to solve a simple problem using Grover’s algorithm, where the solution is not necessarily known beforehand. The problem is a 2×2 binary sudoku with two rules:
• No column may contain the same value twice.
• No row may contain the same value twice.
Each square in the sudoku is assigned to a variable as follows:
We want to design a quantum circuit that outputs a valid solution to this sudoku. While using Grover’s algorithm for this task is not necessarily practical, the goal is to demonstrate how classical decision problems can be converted into oracles for Grover’s algorithm.
Turning the Problem into a Circuit
To solve this, an oracle needs to be created that helps identify valid solutions. The first step is to construct a classical function within a quantum circuit that checks whether a given state satisfies the sudoku rules.
Since we need to check both columns and rows, there are four conditions to verify:
v0 ≠ v1 # Check top row
v2 ≠ v3 # Check bottom row…
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Chapter 10 Solutions
EBK NEW PERSPECTIVES ON HTML5, CSS3, AN
Ch. 10.1 - Prob. 2QCCh. 10 - Prob. 1RACh. 10 - Prob. 2RACh. 10 - Prob. 3RACh. 10 - Prob. 4RACh. 10 - Prob. 5RACh. 10 - Prob. 6RACh. 10 - Prob. 7RACh. 10 - Prob. 8RACh. 10 - Prob. 9RA
Ch. 10 - Prob. 10RACh. 10 - Prob. 11RACh. 10 - Prob. 12RACh. 10 - Prob. 1CP1Ch. 10 - Prob. 2CP1Ch. 10 - Prob. 3CP1Ch. 10 - Prob. 4CP1Ch. 10 - Prob. 5CP1Ch. 10 - Prob. 6CP1Ch. 10 - Prob. 7CP1Ch. 10 - Prob. 8CP1Ch. 10 - Prob. 10CP1Ch. 10 - Prob. 11CP1Ch. 10 - Prob. 12CP1Ch. 10 - Prob. 13CP1Ch. 10 - Prob. 14CP1Ch. 10 - Prob. 15CP1Ch. 10 - Prob. 1CP2Ch. 10 - Prob. 2CP2Ch. 10 - Prob. 3CP2Ch. 10 - Prob. 4CP2Ch. 10 - Prob. 5CP2Ch. 10 - Prob. 6CP2Ch. 10 - Prob. 7CP2Ch. 10 - Prob. 8CP2Ch. 10 - Prob. 9CP2Ch. 10 - Prob. 10CP2Ch. 10 - Prob. 11CP2Ch. 10 - Prob. 12CP2Ch. 10 - Prob. 13CP2Ch. 10 - Prob. 14CP2Ch. 10 - Prob. 2CP3Ch. 10 - Prob. 3CP3Ch. 10 - Prob. 4CP3Ch. 10 - Prob. 5CP3Ch. 10 - Prob. 6CP3Ch. 10 - Prob. 7CP3Ch. 10 - Prob. 8CP3Ch. 10 - Prob. 9CP3Ch. 10 - Prob. 10CP3Ch. 10 - Prob. 11CP3Ch. 10 - Prob. 12CP3Ch. 10 - Prob. 13CP3Ch. 10 - Prob. 14CP3Ch. 10 - Prob. 15CP3Ch. 10 - Prob. 16CP3Ch. 10 - Prob. 17CP3Ch. 10 - Prob. 1CP4Ch. 10 - Prob. 2CP4Ch. 10 - Prob. 3CP4Ch. 10 - Prob. 4CP4Ch. 10 - Prob. 5CP4Ch. 10 - Prob. 6CP4Ch. 10 - Prob. 7CP4Ch. 10 - Prob. 8CP4Ch. 10 - Prob. 9CP4Ch. 10 - Prob. 10CP4Ch. 10 - Prob. 11CP4Ch. 10 - Prob. 12CP4Ch. 10 - Prob. 13CP4Ch. 10 - Prob. 14CP4
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