Chapter 10, Problem 10.GE

Interpretation Introduction

Interpretation:

The isoionic $\text{pH}$ of given lysine solution has to be calculated.

Concept introduction:

Isoionic $\text{pH}$:

The $\text{pH}$ of a pure solution of a neutral, polyprotic molecule.  The only ions present are ${\text{H}}^{\text{+}}{\text{, OH}}^{\text{-}}$ and those derived from the polyprotic species is called isoionic $\text{pH}$.

$\left[\text{H+}\right]\text{=}\sqrt{\frac{{\text{K}}_{\text{2}}{\text{K}}_{\text{3}}{\text{F+K}}_{\text{2}}{\text{K}}_{\text{w}}}{{\text{K}}_{\text{2}}\text{+F}}}$

Where F is the formal concentration

The above equation used to calculate the isoionic $\text{pH}$