Principles of Foundation Engineering
9th Edition
ISBN: 9780357684832
Author: Das
Publisher: Cengage Learning US
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Chapter 10, Problem 10.8P
To determine
Find the consolidation settlement under the corner of the mat foundation,
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Consider a pool of saturated water at atmospheric pressure. The base of the pool is made of thick
polished copper square plate of length 1 m. To generate steam, exhaust gas is flowing underneath
and parallel to the base plate with velocity 3 m/s and average temperate of 1090°C. The bottom
surface the plate is at constant temperature of 110°. Use the properties of air for exhaust gas.
a) Determine the boiling heat transfer rate.
b) Determine the temperature of the top surface of the plate. Comment on the results.
c) Examine the impact of your assumptions on your solutions. (what will change if any of
the assumptions is not valid?)
-The axial deflection pipe in inches. -The lateral deflection of the beam in inches -The total deflection of the beam like structure in inches ?
all to 4 sig figs AI did not help. as i input what i get im not sure if its a rounding error or what.
1. For the foundation shown below:
Qapp = 60 kips
(Load obtained from
structural engineer)
1.5 ft
G.W.T.
3 ft
Poorly Graded Sand (SP):
Ym
115 pcf (above G.W.T.)
Ysat 125 pcf (below G.W.T.)
c' = 0, ' = 35°
K
Square footing, 4' x 4'
Foundation Dimension Information:
1-ft x 1-ft square concrete column.
1-ft thick "foot" flanges.
Yconc=150 pcf
*Assume weight of reinforcing steel
included in unit weight of concrete.
*Assume compacted backfill
weighs the same as in-situ soil.
Assume this foundation is being designed for a warehouse that had a thorough preliminary soil
exploration. Using the general bearing capacity equation:
a. Calculate the gross applied bearing pressure, the gross ultimate bearing pressure, and
determine if the foundation system is safe using a gross bearing capacity ASD
approach. Please include the weight of the foundation, the weight of the backfill soil,
and the effect of the uplift pressure caused by the presence of the water table in your
bearing capacity…
Chapter 10 Solutions
Principles of Foundation Engineering
Ch. 10 - Refer to the rectangular combined footing in...Ch. 10 - Prob. 10.2PCh. 10 - Prob. 10.3PCh. 10 - Prob. 10.4PCh. 10 - Prob. 10.5PCh. 10 - Prob. 10.6PCh. 10 - Prob. 10.7PCh. 10 - Prob. 10.8PCh. 10 - A plate loading test was carried out on a medium...Ch. 10 - A 300 mm 450 mm plate was used in carrying out a...
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.Similar questions
- ٢٥ ٠٥:٤٠١٠ 2025 ChatGPT VivaCut Onet Puzzle مسلم X Excel JPG I❤> PDF Copilot Chat Bot PDF2IMG iLovePDF NokoPrint O.O StudyX ☑ W CapCut Candy Crush DeepSeek Word ☐ Saga 啡 AcadAl ل TikTokarrow_forwardRefer to the figure below. Given: L = 7 m, y = 16.7 kN/m², and ø' = 30°. L L3 ση Sand γ $' D T LA L σε σε IN P Sand 1. Calculate the theoretical depth of penetration, D. (Enter your answer to three significant figures.) D= m 2. Calculate the maximum moment. (Enter your answer to three significant figures.) Mmax kN-m/marrow_forwardWhy is it important for construction project managers to be flexible when dealing with the many variable factors that pop up in a project?arrow_forward
- What are some reasons for why a company would accelerate a construction project?arrow_forwardFor the design of a shallow foundation, given the following: Soil: ' = 20° c' = 52 kN/m² Unit weight, y = 15 kN/m³ Modulus of elasticity, E, = 1400 kN/m² Poisson's ratio, μs = 0.35 Foundation: L=2m B=1m Df = 1 m Calculate the ultimate bearing capacity. Use the equation: 1 - qu = c' NcFcs Fcd Fcc +qNqFqsFqdFqc + ½√BN√Fãs F√dƑxc 2 For '=20°, Nc = 14.83, N₁ = 6.4, and N₁ = 5.39. (Enter your answer to three significant figures.) qu = kN/m²arrow_forwardA 2.0 m wide strip foundation carries a wall load of 350 kN/m in a clayey soil where y = 15 kN/m³, c' = 5.0 kN/m² and ' = 23°. The foundation depth is 1.5 m. For ' = 23°: Nc = 18.05; N₁ = 8.66; Ny = = = 8.20. Determine the factor of safety using the equation below. qu= c' NcFcs FcdFci+qNqFqsFq 1 F + gd. 'qi 2 ·BN√· FF γί Ysyd F (Enter your answer to three significant figures.) FS =arrow_forward
- 2P -1.8 m- -1.8 m- -B Wo P -1.8 m- Carrow_forwardPart F: Progressive activity week 7 Q.F1 Pick the rural location of a project site in Victoria, and its catchment area-not bigger than 25 sqkm, and given the below information, determine the rainfall intensity for ARI 5, 50, 100 year storm event. Show all the details of the procedure. Each student must propose different length of streams and elevations. Use fig below as a sample only. Pt. E-nt 950 200 P: D-40, PC-92.0 300m 300m 000m PL.-02.0 500m HI-MAGO PLA-M 91.00 To be deemed satisfactory the solution must include: Q.F1.1.Choice of catchment location Q.F1.2. A sketch displaying length of stream and elevation Q.F1.3. Catchment's IFD obtained from the Buro of Metheorology for specified ARI Q.F1.4.Calculation of the time of concentration-this must include a detailed determination of the equivalent slope. Q.F1.5.Use must be made of the Bransby-Williams method for the determination of the equivalent slope. Q.F1.6.The graphical display of the estimation of intensities for ARI 5,50, 100…arrow_forwardI need help finding: -The axial deflection pipe in inches. -The lateral deflection of the beam in inches -The total deflection of the beam like structure in inches ?arrow_forward
- A 2.0 m wide strip foundation carries a wall load of 350 kN/m in a clayey soil where y = 17 kN/m³, c' = 5.0 kN/m² and 23°. The foundation depth is 1.5 m. For o' = 23°: Nc = 18.05; N = 8.66; N = 8.20. Determine the factor of safety using the equation below. 1 qu = c' NcFcs Fed Fci +qNqFqs FqdFqi + ½ BN F√s 1 2 (Enter your answer to three significant figures.) s Fyd Fi FS =arrow_forward1.2 m BX B 70 kN.m y = 16 kN/m³ c' = 0 6'-30° Water table Ysat 19 kN/m³ c' 0 &' = 30° A square foundation is shown in the figure above. Use FS = 6, and determine the size of the foundation. Use the Prakash and Saran theory (see equation and figures below). Suppose that F = 450 kN. Qu = BL BL[c′Nc(e)Fcs(e) + qNg(e)Fcs(e) + · 1 YBN(e) F 2 7(e) Fra(e)] (Enter your answer to two significant figures.) B: m Na(e) 60 40- 20- e/B=0 0.1 0.2 0.3 .0.4 0 0 10 20 30 40 Friction angle, ' (deg) Figure 1 Variation of Na(e) with o' Ny(e) 60 40 20 e/B=0 0.3 0.1 0.2 0.4 0 0 10 20 30 40 Friction angle, ' (deg) Figure 2 Variation of Nye) with o'arrow_forwardK/S 46. (O المهمات الجديدة 0 المنتهية 12 المغـ ۱۱:۰۹ search ليس لديك اي مهمات ☐ ○ ☑arrow_forward
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