Explanation a. 2 H 2 g + O 2 → 2 H 2 O 1 Standard enthalpy of formation of H 2 = 0 kJ/mol Standard enthalpy of formation of O 2 (g) = 0 kJ/mol Standard enthalpy of formation of H 2 O(l) = −285.8kJ/mol. standard enthalpy of combustion of hydrogen = 2(−285.80)=−571.6kJ As, 2 g/mole of hydrogen having = - 571 . 6 kJ mol calorific content = - 571 . 6 2 = 285 . 8 kJ g b. 2 C H 3 OH l + 3 O 2 → 2 CO 2 g + 4 H 2 O 1 standard enthalpy of formation of methane = −238.61 kJ/mol Standard enthalpy of formation of CO2(g) = âˆ’393.509 kJ/mol standard enthalpy of combustion of methane = 2 - 393 . 509 + 4 - 285 . 80 - - 477 . 2 + 0 = - 1453 . 018 kJ As, 32 g/mol of methane having =−1453...

1st Edition

ISBN: 9780321834683

Author: Nivaldo J. Tro

Publisher: PEARSON

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Chapter 10, Problem 106E

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Balanced equation for the complete combustion of hydrogen and methanol. Calculate the standard enthalpy of combustion. Which chemical substance contains more calories/ gram?

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Chapter 10, Problem 105E

Chapter 10, Problem 107E

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Balanced equation for the complete combustion of hydrogen and methanol. Calculate the standard enthalpy of combustion. Which chemical substance contains more calories/ gram?

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To determine: Balanced equation for the complete combustion of hydrogen and methanol. Calculate the standard enthalpy of combustion. Which chemical substance contains more calories/ gram?

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Chapter 10 Solutions

To determine:

Balanced equation for the complete combustion of hydrogen and methanol. Calculate the standard enthalpy of combustion. Which chemical substance contains more calories/ gram?