Chapter 10, Problem 10.27P

(a)

Interpretation Introduction

Interpretation:

Fraction of $10.231\text{ g}$ window cleaner present in $\text{4}\text{.373 g}$ sample analyzed has to be calculated.

Concept Introduction:

Molarity is quantitatively defined as moles of solute in one liter of solution. For example $\text{0}{\text{.070 M AlCl}}_3$ indicates that in $1\text{ L}$ the moles of ${\text{AlCl}}_3$ is $\text{0}\text{.070 mol}$.

Formula to calculate molar mass from number of moles is given as follows:

  $\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Formula to calculate moles from volume is as follows:

  $n=MV$

Here,

$V$ denotes volume.

$M$ denotes molarity.

$n$ denotes moles.

(b)

Interpretation Introduction

Interpretation:

Mass of ${\text{NH}}_{\text{3}}$ present in $\text{4}\text{.373 g}$ sample analyzed has to be calculated.

Concept Introduction:

Refer to part (a).

(c)

Interpretation Introduction

Interpretation:

Weight percent of ${\text{NH}}_{\text{3}}$ in window cleaner has to be calculated.

Concept Introduction:

Refer to part (a).