For the drilled shaft described in Problem 19.7, estimate the total elastic settlement at working load. Use Eqs. (18.45), (18.47), and (18.48). Assume that Ep = 20 106 kN/m2, s = 0.3, Es = 12 103 kN/m2, = 0.65 and Cp = 0.03. Assume 80% mobilization of skin resistance at working load. (See Part c of Problem 19.7) 19.7 Figure 19.16 shows a drilled shaft without a bell. Here, L1 = 6 m, L2 = 7 m, Ds = 1.5 m, cu(1) = 50 kN/m2, and cu(2) = 75 kN/m2. Find these values: a. The net ultimate point bearing capacity. Use Eqs. (19.23) and (19.24) b. The ultimate skin resistance. Use Eqs. (19.26) and (19.28) c. The working load, Qw (FS = 3) FIG. 19.16

Earth Sciences Downward force is 4000 kg and rotational force is 3000 kg. Contact surface area (cross sectional area) is 100 cm2. Also, the rock sample (diameter: 20 cm) is tested by a uniaxial compressive strength machine and the sample was cracked at 30000 kg. Answer the following questions:a. Find the resultant force acting on the rock formation.b. Find the bearing strength of the rock drilled.c. Can we drill under these circumstances?

Please help me solve. This is not a graded question.

6 decimal places for the solution

Hint: The problem is 10.10 taken from the book " introductory to mining engineering " written by "Howard L.Hartman" A single rectangular opening 10 ft in height is driven in rock having strengths of fc=18000 lb/in2 and ft= 1500 lb/in2. Rock specific gravity is 2.3. The opening is located at a depth of 2000 ft in a stress field of no lateral pressure and has a fillet ratio of 1/6. (a). Determine if the opening will fail when its width is 20 ft ? (b). What is the maximum safe width of the opening?.A single rectangular opening 10 ft (3.0 m) in height is driven in rock having strengths of fc = 18,000 lb/in2 (124 MPa) and ft=1500 lb/in2. (10.3 MPa).Rock specific gravity is 2.3.The opening is located at depth of 2000 ft (610 m) in a stress field of no lateral pressure and has a fillet ratio of 1/6 .a. Determine if the opening will fail when its width is 20 ft (6.1 m).b. Is there any benefit to reducing the width to 10 ft (3.0 m)? To 5 ft (1.5 m)?c. What is the maximum safe width of opening?

Rock mechanics class appreciate your help and explanation

2: An embankment shown in the figure is constructed. compute the vertical stress increment under Points A. B. and C at z = 10 m Use vertical stress Increment under an embankment loads? 10 m 12 m 10 m Y₁-192 kN/m² Take value of 15 from chart s6v=9[s

For the drilled shaft described in Problem 10.1, what skin resistance would develop in the top 6 m, which are in clay ?

A 3 ft diameter straight drilled shaft is shown in Figure P13.7. Determine the load-carrying capacity of the drilled shaft with FS = 3. Take / as 0.8 for the sand.