Concept explainers
(a)
The strain in the cable.
(a)
Answer to Problem 101P
The strain in the cable is
Explanation of Solution
Consider the segment of the rope between the fixed end and the walker’s position. A right triangle can be constructed with the non-stretched segment and stretched segment of the cable as shown in Figure 1.
Write the expression for the strain in the cable.
Here,
Write the expression for
Use equation (II) in (I).
Conclusion:
Substitute
Therefore, the strain in the cable is
(b)
The tension in the cable when the walker is at the middle of the rope.
(b)
Answer to Problem 101P
The tension in the cable when the walker is at the middle of the rope is
Explanation of Solution
The free-body diagram of the walker is given in Figure 2.
Write the equilibrium conditions on the forces in
Apply the condition in equation (I) to the free-body diagram.
Here,
Solve equation (V) for
Conclusion:
Substitute
Therefore, the tension in the cable when the walker is at the middle of the rope is
(c)
The cross sectional area of the cable.
(c)
Answer to Problem 101P
The cross sectional area of the cable is
Explanation of Solution
Equation (VI) gives the tension in the cable.
Divide equation (VI) by the cross sectional area of the cable
Write the expression of Hooke’s law when force equal to the tension
Here,
Use equation (I) in (VIII).
Equate the right hand sides of the equations (VII) and (IX) and solve for
Conclusion:
Substitute
Therefore, the cross sectional area of the cable is
(d)
Whether the cable stretched beyond its elastic limit.
(d)
Answer to Problem 101P
The cable did not stretched beyond its elastic limit.
Explanation of Solution
Write the expression for the stress in terms of the tension in the cable.
Conclusion:
Substitute
Therefore, the cable did not stretched beyond its elastic limit.
Want to see more full solutions like this?
Chapter 10 Solutions
PHYSICS
- 19:39 · C Chegg 1 69% ✓ The compound beam is fixed at Ę and supported by rollers at A and B. There are pins at C and D. Take F=1700 lb. (Figure 1) Figure 800 lb ||-5- F 600 lb بتا D E C BO 10 ft 5 ft 4 ft-—— 6 ft — 5 ft- Solved Part A The compound beam is fixed at E and... Hình ảnh có thể có bản quyền. Tìm hiểu thêm Problem A-12 % Chia sẻ kip 800 lb Truy cập ) D Lưu of C 600 lb |-sa+ 10ft 5ft 4ft6ft D E 5 ft- Trying Cheaa Những kết quả này có hữu ích không? There are pins at C and D To F-1200 Egue!) Chegg Solved The compound b... Có Không ☑ ||| Chegg 10 וחarrow_forwardNo chatgpt pls will upvotearrow_forwardNo chatgpt pls will upvotearrow_forward
- No chatgpt pls will upvotearrow_forwardair is pushed steadily though a forced air pipe at a steady speed of 4.0 m/s. the pipe measures 56 cm by 22 cm. how fast will air move though a narrower portion of the pipe that is also rectangular and measures 32 cm by 22 cmarrow_forwardNo chatgpt pls will upvotearrow_forward
- 13.87 ... Interplanetary Navigation. The most efficient way to send a spacecraft from the earth to another planet is by using a Hohmann transfer orbit (Fig. P13.87). If the orbits of the departure and destination planets are circular, the Hohmann transfer orbit is an elliptical orbit whose perihelion and aphelion are tangent to the orbits of the two planets. The rockets are fired briefly at the depar- ture planet to put the spacecraft into the transfer orbit; the spacecraft then coasts until it reaches the destination planet. The rockets are then fired again to put the spacecraft into the same orbit about the sun as the destination planet. (a) For a flight from earth to Mars, in what direction must the rockets be fired at the earth and at Mars: in the direction of motion, or opposite the direction of motion? What about for a flight from Mars to the earth? (b) How long does a one- way trip from the the earth to Mars take, between the firings of the rockets? (c) To reach Mars from the…arrow_forwardNo chatgpt pls will upvotearrow_forwarda cubic foot of argon at 20 degrees celsius is isentropically compressed from 1 atm to 425 KPa. What is the new temperature and density?arrow_forward
- Calculate the variance of the calculated accelerations. The free fall height was 1753 mm. The measured release and catch times were: 222.22 800.00 61.11 641.67 0.00 588.89 11.11 588.89 8.33 588.89 11.11 588.89 5.56 586.11 2.78 583.33 Give in the answer window the calculated repeated experiment variance in m/s2.arrow_forwardNo chatgpt pls will upvotearrow_forwardCan you help me solve the questions pleasearrow_forward
- College PhysicsPhysicsISBN:9781305952300Author:Raymond A. Serway, Chris VuillePublisher:Cengage LearningUniversity Physics (14th Edition)PhysicsISBN:9780133969290Author:Hugh D. Young, Roger A. FreedmanPublisher:PEARSONIntroduction To Quantum MechanicsPhysicsISBN:9781107189638Author:Griffiths, David J., Schroeter, Darrell F.Publisher:Cambridge University Press
- Physics for Scientists and EngineersPhysicsISBN:9781337553278Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningLecture- Tutorials for Introductory AstronomyPhysicsISBN:9780321820464Author:Edward E. Prather, Tim P. Slater, Jeff P. Adams, Gina BrissendenPublisher:Addison-WesleyCollege Physics: A Strategic Approach (4th Editio...PhysicsISBN:9780134609034Author:Randall D. Knight (Professor Emeritus), Brian Jones, Stuart FieldPublisher:PEARSON