(a) Explanation Given info: The mass of the textbook kept in horizontally on a frictionless surface is 2.00 kg , the diameter of the pulley is 0.150 m , the mass of the hanging book is 3.00 kg and the books are move 1.20 m in 0.800 s . The following diagram shows the free body diagram of the book on horizontal surface and the hanging book: Figure-(I) Formula to calculate tension on the book kept in horizontal surface from Newton’s second law is: T 1 = m 1 a (I) T 1 is the tension on the book kept in horizontal surface. m 1 is the mass of the book kept in horizontal surface. a is the acceleration of the book. Formula to calculate the acceleration of the book from the kinematics equation is: y = v o t + 1 2 a t 2 y is the final displacement of the book. v o is the initial velocity of the book. a is the acceleration of the book. t is the time duration. Substitute 1.20 m for y , 0 m/s for v o and 0.800 s for t in the above equation to find a : 1.20 m = ( 0 m/s ) ( 0.800 s ) + 1 2 a ( 0.800 s ) 2 a = 3.75 m/s 2 Thus, the acceleration of the book is 3.75 m/s 2 . Substitute 3 (b) To determine The moment of inertia of the pulleys about its rotation axis.

University Physics with Modern Physics, Volume 1 (Chs. 1-20) and Mastering Physics with Pearson eText & ValuePack Access Card (14th Edition)

14th Edition

ISBN: 9780134209586

Author: Hugh D. Young

Publisher: PEARSON

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Question

Chapter 10, Problem 10.13E

(a)

To determine

The tension on the each part of the cord.

(b)

To determine

The moment of inertia of the pulleys about its rotation axis.

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Chapter 10, Problem 10.12E

Chapter 10, Problem 10.14E

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