Connect for Chemistry
13th Edition
ISBN: 9781260161854
Author: Raymond Chang, Jason Overby
Publisher: Mcgraw-hill Higher Education (us)
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Chapter 10, Problem 10.121QP
The geometries discussed in this chapter all lend themselves to fairly straightforward elucidation of bond angles. The exception is the tetrahedron, because its bond angles are hard to visualize. Consider the CCl4 molecule, which has a tetrahedral geometry and is nonpolar. By equating the bond moment of a particular C─Cl bond to the resultant bond moments of the other three C─Cl bonds in opposite directions, show that the bond angles are all equal to 109.5°.
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Students have asked these similar questions
Draw the Lewis dot structure for acetic acid (HC2H3O2, CH3COOH). Determine the optimum formal charge structure. Determine the VSEPR domain and molecular geometries for the central carbon atoms. Determine the hybridization of the carbons and oxygens. Determine the polarity of the molecule; show the polarity arrows and partial charges for the molecule. (Electronegativities: H 2.1,C 2.5, O 3.5)
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[0=C=N] [0=C—N:
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The two structures are not resonance contributors because they have different arrangements of atoms.
X
Ś
Molecules can be polar because of the unsymmetrical distribution of electrons. The dipole moment, μ Q r
μ=Q×r
The SI unit of dipole moment is the coulomb-meter (C⋅m), but another common unit is the debye (D). The two are related as
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%ionic character=measured dipole/if electrons transferred×100%
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Express your answer as a percent to three significant figures.
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Chapter 10 Solutions
Connect for Chemistry
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