LINUX+ GUIDE TO LINUX CERTIFICATION
4th Edition
ISBN: 9780357005194
Author: ECKERT
Publisher: CENGAGE L
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Chapter 1, Problem 6RQ
Program Description Answer
Production kernel includes minor number as even.
Hence, correct answer is option “D”.
Expert Solution & Answer
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Students have asked these similar questions
1. Write a program to implement LRU page replacement algorithm
2. Write a program to implement FIFO page replacement algorithm
Instruction for lab work:
+ Students will be allocated any one / choose anyone question to answer.
+ Kindly use suitable Kali Linux tools to solve these assignment problems.
+ You have to write the step-by-step commands to solve each problem as well as screenshots
at each step.
Students can work in teams
+ Viva will be conducted by course teachers. Students will have to share their screen with
the course teacher and practically demonstrate the lab work as per the report submitted.
Submit assignment on or before the deadline on Blackboard portal.
Late assignment submission will not be allowed.
Students should not copy and paste assignments directly from other students. Assignments
will also be evaluated based on plagiarism and marks will be deducted if plagiarism found.
To obtain better memory utilization, dynamic loading is used. With dynamic loading, a routine is not loaded until it is called. For implementing dynamic loading ____________a) special support from operating system is essentialb) special support from hardware is requiredc) user programs can implement dynamic loading without any special support from hardware or operating systemd) special support from both hardware and operating system is essential
The original Linux developers built a non-preemptible kernel for whatever reason.What good does it do to have a non-preemptible kernel in a single-processor computer? However, with a system with several processors, why does this benefit decrease?
Chapter 1 Solutions
LINUX+ GUIDE TO LINUX CERTIFICATION
Ch. 1 - Every computer consists of physical components and...Ch. 1 - The operating system software is necessary for a...Ch. 1 - Prob. 3RQCh. 1 - Prob. 4RQCh. 1 - Prob. 5RQCh. 1 - Prob. 6RQCh. 1 - Prob. 7RQCh. 1 - Prob. 8RQCh. 1 - To which license does Linux adhere? a. open...Ch. 1 - Prob. 10RQ
Ch. 1 - Prob. 11RQCh. 1 - Which two people are credited with creating the...Ch. 1 - Who formed the Free Software Foundation to promote...Ch. 1 - Which culture embraced the term “GNU” (GNU’s Not...Ch. 1 - Prob. 15RQCh. 1 - Prob. 16RQCh. 1 - Prob. 17RQCh. 1 - Prob. 18RQCh. 1 - Prob. 19RQCh. 1 - Prob. 20RQ
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Similar questions
- Linux creators opted for a non-preemptible kernel from the outset because...Can you explain the benefits of a non-preemptible kernel on a single-processor computer? Why does the benefit decrease as the number of processors used increases?arrow_forwardThe ALU is the component of the CPU where __________ and ________. a.programs are decoded; instructions are fetched b.data is stored; instructions are interpreted c.data is held temporarily; calculations are made d.calculations take place; instructions are interpretedarrow_forwardWhat are the differences between a microkernel and monolithic kernel? Please type out in text as handwriting is difficult to read.arrow_forward
- Description:The project I am working on needs to demonstrate how two processes (parent and child) can communicatethrough a shared memory region, with the child process writing a value to the shared memoryand the parent process reading that value. This is my code and I wont run. Can you help: #include <stdio.h>#include <stdlib.h>#include <sys/types.h>#include <sys/ipc.h>#include <sys/shm.h>#include <unistd.h> #define SHM_SIZE 1024 /* shared memory size */ void error_exit(const char *msg) { perror(msg); exit(EXIT_FAILURE);} int main() { key_t key; int shmid; char *data; // Create a unique key for shared memory if ((key = ftok("shared_memory.c", 'R')) == -1) { error_exit("ftok"); } // Create the shared memory segment if ((shmid = shmget(key, SHM_SIZE, 0644 | IPC_CREAT)) == -1) { error_exit("shmget"); } // Attach the shared memory segment to our data space data = shmat(shmid, (void *)0, 0); if…arrow_forward12. When many users accesses mainframes, this approach is called as a. resource allocation b. word processors c. dedicated resources d. interfacearrow_forwardWhy did the original developers of Linux chose a kernel that did not support preemptive multitasking?What are the advantages of using a non-preemptible kernel in a system that only has one processor? However, why is the value diminished when using a machine with several processors?arrow_forward
- Multithreading: Select all of the following statements that are true. User threads must be mapped onto available kernel threads in order to be scheduled to be assigned to the CPU. A lightweight process (LWP) is a communication interface between different user threads of an application. The Many-to-One multithreading model allows the splitting of processes and threads across multiple CPUs. In the Many-to-Many multithreading model, a process always blocks whenever one of its threads blocks. A context switch between threads can be performed much faster than between processes. One advantage of multithreading is responsiveness, which means that one thread may respond instantly while other threads are blocked or busy doing calculations.arrow_forwardWhy did the original developers of Linux chose a kernel that did not support preemptive multitasking?What are the advantages of using a non-preemptible kernel in a system that only has one processor? Yet, why is the value diminished when using a machine with several processors?arrow_forwardMCQ: ___________module of the kernel performs context switching a. Short Term Scheduler b. Dispatcher c. Long Term Scheduler d. Memory Managerarrow_forward
- Why did the original architects of Linux decide to create a kernel that does not support preemptive processing?In a computer system with just one CPU, why would you want to use a non-preemptible kernel? On the other hand, why does having several processors in a system make the benefit less significant?arrow_forwardQUESTION 8 emulator: noname.exe file math debug view external virtual devices virtual drive help step back ID single step Load reload run step delay ms: 100 registers 0722:0000 0722:0000 L 07220: 9A 154 ül 07221: 23 035 # 07222: 76 118 v 07223: 34 052 4| 07224: 12 018 ± 07225: B8 184 © 07226: 00 000 NI CALL 01234h:07623h MOV AX, 04CO0h INT 021h NOP NOP NOP AX 00 00 BX 00 00 01 2A DX 00 00 CS 0722 IP 0000 debug stack flags screen source reset aux vars A712 Based on the above screenshot, answer the following questions: (1) How many bytes of the machine code of the CALL 1234H:7623H instruction? (2) After the CALL 1234H:7623H instruction is executed, what are the new values of IP & CS? (3) After the CALL 1234H:7623H instruction is executed, what data are saved onto stack?arrow_forwardWhy did the original developers of Linux choose a kernel that did not support preemptive multitasking? What are the advantages of using a non-preemptible kernel in a system that only has one processor? Yet, why is the value diminished when using a machine with several processors?arrow_forward
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