New Perspectives On Html5, Css3, And Javascript, Loose-leaf Version
6th Edition
ISBN: 9781337685764
Author: Patrick M. Carey
Publisher: Cengage Learning
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Question
Chapter 1, Problem 6CP2
Program Plan Intro
(a)
To mark the given heading as H1.
Program Plan Intro
(b)
To mark three paragraphs of article element with p element.
Program Plan Intro
(c)
To mark the given names as strong text and the phrase "800 different books and papers" as emphasized text in the first paragraph.
Program Plan Intro
(d)
To mark the given works as citations and insert the given character using character reference in second paragraph.
Program Plan Intro
(e)
To mark the given mathematical symbols using var element and insert pi using π in third paragraph.
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(OnlineGDB)
#include <stdio.h>int main(void) {int a;char *s;int v0 = 4, v1 = 5, v2 = 6, v3 = 1, v4 = 2;printf("Exercise 1:\n====================\n");switch(v0) {case 0: printf("Hello October\n"); break;case 1: printf("Go Kean!\n"); break;case 2: printf("Academic Building Center \n"); break;case 3: printf("UNION \n"); break;case 4: printf("Go ");case 5: printf("Kean! \n");default: printf("Have a great semester! \n"); break;}for(a=5; a<v1; a++) {printf("Kean");}printf("\n");if (v2 == 6) {s = "Go";}else {s = "Hello";}if(v3 != v4) {printf("%s Kean!\n",s);} else {printf("%s Computer Science!\n",s);}return 0;}
Assume the following codes are added between line 36 (}) and line 38 (return 0;) v0>0 ? ++v1, ++v2 : --v3; Please give the values of v0, v1, v2, v3, and v4 after this line and explain the reason. You can test the program to verify your answer if you like.
Chapter 1 Solutions
New Perspectives On Html5, Css3, And Javascript, Loose-leaf Version
Ch. 1.1 - Prob. 1QCCh. 1.1 - Prob. 2QCCh. 1.1 - Prob. 3QCCh. 1.1 - Prob. 4QCCh. 1.1 - What is incorrect about the following code?...Ch. 1.1 - Prob. 6QCCh. 1.1 - Prob. 7QCCh. 1.1 - Prob. 8QCCh. 1.1 - Prob. 9QCCh. 1.2 - Prob. 1QC
Ch. 1.2 - Prob. 2QCCh. 1.2 - Prob. 3QCCh. 1.2 - Prob. 4QCCh. 1.2 - Prob. 5QCCh. 1.2 - Prob. 6QCCh. 1.2 - Prob. 7QCCh. 1.2 - Prob. 8QCCh. 1.2 - Prob. 9QCCh. 1.3 - Prob. 1QCCh. 1.3 - Prob. 2QCCh. 1.3 - Prob. 3QCCh. 1.3 - Prob. 4QCCh. 1.3 - Prob. 5QCCh. 1.3 - Prob. 6QCCh. 1.3 - Prob. 7QCCh. 1.3 - Prob. 8QCCh. 1.3 - Prob. 9QCCh. 1 - Prob. 1RACh. 1 - Prob. 2RACh. 1 - Prob. 3RACh. 1 - Prob. 4RACh. 1 - Prob. 5RACh. 1 - Prob. 6RACh. 1 - Prob. 7RACh. 1 - Prob. 8RACh. 1 - Prob. 9RACh. 1 - Prob. 10RACh. 1 - Prob. 11RACh. 1 - Prob. 12RACh. 1 - Prob. 13RACh. 1 - Prob. 14RACh. 1 - Prob. 15RACh. 1 - Prob. 16RACh. 1 - Prob. 17RACh. 1 - Prob. 18RACh. 1 - Prob. 19RACh. 1 - Prob. 20RACh. 1 - Prob. 21RACh. 1 - Prob. 22RACh. 1 - Prob. 23RACh. 1 - Prob. 1CP1Ch. 1 - Prob. 2CP1Ch. 1 - Prob. 3CP1Ch. 1 - Prob. 4CP1Ch. 1 - Prob. 5CP1Ch. 1 - Prob. 6CP1Ch. 1 - Prob. 7CP1Ch. 1 - Prob. 8CP1Ch. 1 - Prob. 9CP1Ch. 1 - Prob. 10CP1Ch. 1 - Prob. 11CP1Ch. 1 - Prob. 12CP1Ch. 1 - Prob. 13CP1Ch. 1 - Prob. 14CP1Ch. 1 - Prob. 15CP1Ch. 1 - Prob. 16CP1Ch. 1 - Prob. 1CP2Ch. 1 - Prob. 2CP2Ch. 1 - Prob. 3CP2Ch. 1 - Prob. 4CP2Ch. 1 - Prob. 5CP2Ch. 1 - Prob. 6CP2Ch. 1 - Prob. 7CP2Ch. 1 - Prob. 8CP2Ch. 1 - Prob. 9CP2Ch. 1 - Prob. 10CP2Ch. 1 - Prob. 11CP2Ch. 1 - Prob. 12CP2Ch. 1 - Prob. 1CP3Ch. 1 - Prob. 2CP3Ch. 1 - Prob. 3CP3Ch. 1 - Prob. 4CP3Ch. 1 - Prob. 5CP3Ch. 1 - Prob. 6CP3Ch. 1 - Prob. 7CP3Ch. 1 - Prob. 8CP3Ch. 1 - Prob. 9CP3Ch. 1 - Prob. 10CP3Ch. 1 - Prob. 11CP3Ch. 1 - Prob. 12CP3Ch. 1 - Prob. 13CP3Ch. 1 - Prob. 14CP3Ch. 1 - Prob. 15CP3Ch. 1 - Prob. 16CP3Ch. 1 - Prob. 17CP3Ch. 1 - Prob. 18CP3Ch. 1 - Prob. 19CP3Ch. 1 - Prob. 20CP3Ch. 1 - Prob. 21CP3Ch. 1 - Prob. 22CP3Ch. 1 - Prob. 23CP3Ch. 1 - Prob. 24CP3Ch. 1 - Prob. 25CP3Ch. 1 - Prob. 26CP3Ch. 1 - Prob. 1CP4Ch. 1 - Prob. 2CP4Ch. 1 - Prob. 3CP4Ch. 1 - Prob. 4CP4Ch. 1 - Prob. 5CP4Ch. 1 - Prob. 6CP4Ch. 1 - Prob. 7CP4
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