EBK PHYSICS FOR SCIENTISTS AND ENGINEER
EBK PHYSICS FOR SCIENTISTS AND ENGINEER
6th Edition
ISBN: 9781319321710
Author: Mosca
Publisher: VST
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Chapter 1, Problem 69P

(a)

To determine

To write: The number of parsec in 1AU .

(a)

Expert Solution
Check Mark

Answer to Problem 69P

  1AU is equal to 4.848×106pc .

Explanation of Solution

Given:

The arc length is equal to 1AU .

The angle of arc covered is 1s .

Formula used:

Write the expression for arc.

  a=r×θ

Rearrange the above expression in terms of r .

  r=aθ   .............. (1)

Here, r is the radius, a is the arc and θ is the angle covered.

Calculation:

Substitute 1AU for a and 1s for θ in equation (1).

  r=1AU1s( 1° 3600s )( ( π 180 ) 1° )=206264.81AU

The radius of circle is 206264.81AU that is equal to 1pc.

Calculate the number of parsec in 1AU .

  d=1AU( 1pc 206264.81AU)=4.8481×106pc

Conclusion:

Thus, 1AU is equal to 4.8481×106pc .

(b)

To determine

To write: The number of meter in 1pc .

(b)

Expert Solution
Check Mark

Answer to Problem 69P

  1pc is equal to 3.086×1016m .

Explanation of Solution

Given:

  1AU is equal to 1.496×1011m .

Formula used:

Write the conversion for parsec into astronomical units as follows:

  1 Pa=206264.81AU

Calculation:

Calculate the number of meters in 1pc .

  d=1pc( 206264.81AU 1pc)( 1.496× 10 11 m 1AU)=3.086×1016m

Conclusion:

Thus, 1pc is equal to 3.086×1016m .

(c)

To determine

To write: The number of meters in a light-year.

(c)

Expert Solution
Check Mark

Answer to Problem 69P

A light-year is equal to 9.46×1015m .

Explanation of Solution

Given:

  1AU is equal to 1.496×1011m .

Formula used:

Write the expression for distance covered.

  d=v×t   .............. (2)

Here, d is the distance covered, v is the speed of object and t is the time taken.

Calculation:

Substitute 3×108m/s for v and 1y for t in equation (2).

  d=(3× 108m/s)(1y)( 365days 1y)( 86400s 1day)=9.46×1015m

Conclusion:

Thus, a light-year is equal to 9.46×1015m .

(d)

To determine

To write: The number of AU in a light-year.

(d)

Expert Solution
Check Mark

Answer to Problem 69P

A light-year is equal to 6.324×104AU .

Explanation of Solution

Given:

  1AU is equal to 1.496×1011m .

Formula used:

Write the conversion for light years into meter as follows:

  1 ly=9.46×1015m

Calculation:

Calculate the number of AU in a light-year.

  d=1ly( 9.46× 10 15 m 1ly)( 1AU 1.496× 10 11 m)=6.324×104AU

Conclusion:

Thus, a light-year is equal to 6.324×104AU .

(e)

To determine

To write: The number of light-year in a parsec.

(e)

Expert Solution
Check Mark

Answer to Problem 69P

  1pc is equal to 3.262 ly .

Explanation of Solution

Given:

  1AU is equal to 1.496×1011m .

Formula used:

Write the conversion for parsec into meter as follows:

  1 pc=3.086×1016m

Calculation:

Calculate the number of light-year in a parsec.

  d=1pc( 3.086× 10 16 m 1pc)( 1ly 9.46× 10 15 m)=3.262 ly

Conclusion:

Thus, 1pc is equal to 3.262 ly .

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