EBK A GUIDE TO SQL
9th Edition
ISBN: 8220103671682
Author: Last
Publisher: CENGAGE L
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Chapter 1, Problem 5SPTC
To determine
Provide last name, first name and city of every patient who has balance greater than $1000.
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Taylor Series Approximation Example- H.W
More terms used implies better approximation
f(x)+
f(x)
Zero order
First order
1.0
0.5
x-0
Second order
True
f(x) f(x)
• flx;+ 1) = f(x) + fƒ '\x;}h
√(x,+ 1) = f(x) + f (x)h + "(x) 2
f(x1)
X+1-1
f(x) 0.1x 0.15x³-0.5x²-0.25x+1.2
Taylor Series Approximation H.w:
Smaller step size implies smaller error
Errors
100+
F(x)
Zero order
First order
Second order
0.5
Reduced step size
0
x, 0
f(x+1)f(x,) + ƒ\x,}h
51
f(x + 1) − f(x) + (x)+2
((x1)
+1-1
Using Taylor Series Expansion estimate f(1.35) with x0 =0.75 with 5
iterations (or & s= 5%) for
f(x) 0.1x 0.15x³-0.5x2- 0.25x+1.2
マ
52
Home Work
Use Taylor's series expansion to Compute the true and approximate percent relative
errors & and εa for x = π/6, use 6 iterations for the series.
sin(x)
== x-
Taylor Series Approximation Example- H.W
More terms used implies better approximation
f(x) 4
f(x)
Zero order
f(x + 1) = f(x;)
First order
f(x; + 1) = f(x;) + f'(x;)h
1.0
Second order
0.5
True
f(x + 1) =
f(x) + f'(x)h +
ƒ"(x;)
h2
2!
f(x+1)
0
x; = 0
x+1 = 1
x
h
f(x)=0.1x4-0.15x³- 0.5x2 -0.25x + 1.2
51
Taylor Series Approximation H.w:
Smaller step size implies smaller error
Errors
f(x) +
f(x,)
Zero order
f(x,+ 1) = f(x)
First order
1.0
0.5
Reduced step size
Second order
True
f(x + 1) = f(x) + f'(x)h
f(x; + 1) = f(x) + f'(x)h + "(xi) h2
f(x,+1)
O
x₁ = 0
x+1=1
Using Taylor Series Expansion estimate f(1.35) with x0 =0.75 with 5
iterations (or & s= 5%) for
f(x)=0.1x 0.15x³-0.5x²- 0.25x + 1.2
52
Chapter 1 Solutions
EBK A GUIDE TO SQL
Ch. 1 - Prob. 1RQCh. 1 - Prob. 2RQCh. 1 - Prob. 3RQCh. 1 - Prob. 4RQCh. 1 - Prob. 5RQCh. 1 - Prob. 6RQCh. 1 - Prob. 7RQCh. 1 - Prob. 8RQCh. 1 - Prob. 9RQCh. 1 - Prob. 10RQ
Ch. 1 - Prob. 11RQCh. 1 - Prob. 12RQCh. 1 - Prob. 13RQCh. 1 - Prob. 14RQCh. 1 - Prob. 15RQCh. 1 - Prob. 16RQCh. 1 - Prob. 17RQCh. 1 - Prob. 18RQCh. 1 - Prob. 19RQCh. 1 - Prob. 20RQCh. 1 - Prob. 21RQCh. 1 - Prob. 22RQCh. 1 - Prob. 23RQCh. 1 - Prob. 24RQCh. 1 - Prob. 1BCECh. 1 - Prob. 2BCECh. 1 - Prob. 3BCECh. 1 - Prob. 4BCECh. 1 - Prob. 5BCECh. 1 - Prob. 6BCECh. 1 - Prob. 7BCECh. 1 - Prob. 8BCECh. 1 - Prob. 9BCECh. 1 - Prob. 10BCECh. 1 - Prob. 11BCECh. 1 - Prob. 12BCECh. 1 - Prob. 13BCECh. 1 - Prob. 1CATCCh. 1 - Prob. 2CATCCh. 1 - Prob. 3CATCCh. 1 - Prob. 4CATCCh. 1 - Prob. 5CATCCh. 1 - Prob. 6CATCCh. 1 - Prob. 7CATCCh. 1 - Prob. 8CATCCh. 1 - Prob. 9CATCCh. 1 - Prob. 10CATCCh. 1 - Prob. 11CATCCh. 1 - Prob. 12CATCCh. 1 - Prob. 13CATCCh. 1 - Prob. 14CATCCh. 1 - Prob. 15CATCCh. 1 - Prob. 16CATCCh. 1 - Prob. 17CATCCh. 1 - Prob. 1SPTCCh. 1 - Prob. 2SPTCCh. 1 - Prob. 3SPTCCh. 1 - Prob. 4SPTCCh. 1 - Prob. 5SPTCCh. 1 - Prob. 6SPTCCh. 1 - Prob. 7SPTCCh. 1 - Prob. 8SPTCCh. 1 - Prob. 9SPTCCh. 1 - Prob. 10SPTCCh. 1 - Prob. 11SPTC
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