The student body at Eureka High School is having an election for Homecoming Queen. The candidates are Alicia, Brandy, Cleo, and Dionne ( A , B , C , and D for short ). Table 1-26 shows the preference schedule for the election. Table 1-26 N u m b e r o f v o t e r s 202 160 153 145 125 110 108 102 55 1st B C A D D C B A A 2nd D B C B A A C B D 3rd A A B A C D A D C 4th C D D C B B D C B a. How many students voted in this election? b. How many first-place votes are needed for a majority? c. Which candidate had the fewest last-place votes?
The student body at Eureka High School is having an election for Homecoming Queen. The candidates are Alicia, Brandy, Cleo, and Dionne ( A , B , C , and D for short ). Table 1-26 shows the preference schedule for the election. Table 1-26 N u m b e r o f v o t e r s 202 160 153 145 125 110 108 102 55 1st B C A D D C B A A 2nd D B C B A A C B D 3rd A A B A C D A D C 4th C D D C B B D C B a. How many students voted in this election? b. How many first-place votes are needed for a majority? c. Which candidate had the fewest last-place votes?
The student body at Eureka High School is having an election for Homecoming Queen. The candidates are Alicia, Brandy, Cleo, and Dionne (
A
,
B
,
C
,
and
D
for short
). Table 1-26 shows the preference schedule for the election.
Table 1-26
N
u
m
b
e
r
o
f
v
o
t
e
r
s
202
160
153
145
125
110
108
102
55
1st
B
C
A
D
D
C
B
A
A
2nd
D
B
C
B
A
A
C
B
D
3rd
A
A
B
A
C
D
A
D
C
4th
C
D
D
C
B
B
D
C
B
a. How many students voted in this election?
b. How many first-place votes are needed for a majority?
c. Which candidate had the fewest last-place votes?
A factorization A = PDP 1 is not unique. For A=
7 2
-4 1
1
1
5 0
2
1
one factorization is P =
D=
and P-1
30
=
Use this information with D₁
=
to find a matrix P₁ such that
-
-1 -2
0 3
1
-
- 1
05
A-P,D,P
P1
(Type an integer or simplified fraction for each matrix element.)
Matrix A is factored in the form PDP 1. Use the Diagonalization Theorem to find the eigenvalues of A and a basis for each eigenspace.
30 -1
-
1 0 -1
400
0
0 1
A=
3 4 3
0 1 3
040
3 1 3
0 0
4
1
0
0
003
-1 0 -1
Select the correct choice below and fill in the answer boxes to complete your choice.
(Use a comma to separate vectors as needed.)
A basis for the corresponding eigenspace is {
A. There is one distinct eigenvalue, λ =
B. In ascending order, the two distinct eigenvalues are λ₁
...
=
and 2
=
Bases for the corresponding eigenspaces are {
and ( ), respectively.
C. In ascending order, the three distinct eigenvalues are λ₁ =
=
12/2
=
and 3 = Bases for the corresponding eigenspaces are
{}, }, and {
respectively.
University Calculus: Early Transcendentals (4th Edition)
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