Chapter 1, Problem 46EAP

To determine

To find the ratio, the basic formula altered as,$\begin{array}{l}\text{(diameter of Milky Way:diameter of Saturn's rings)ratio}\Rightarrow \frac{\text{diameter of Milky Way}}{\text{diameter of Saturn's rings}}\\ \text{ratio=}\frac{\text{9}{\text{.46×10}}^{\text{17}}\text{km}}{\text{2}{\text{.7×10}}^{\text{5}}\text{km}}\\ \text{=3}{\text{.5×10}}^{\text{12}}\end{array}$

Therefore, the therefore diameter of Milky Way is $\boxed{3.5\times {10}^{12}}$ times greater than diameter of Saturn’s rings