Computer Science Illuminated
6th Edition
ISBN: 9781284055917
Author: Nell Dale, John Lewis
Publisher: Jones & Bartlett Learning
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Expert Solution & Answer
Chapter 1, Problem 43E
Explanation of Solution
First prediction:
The first prediction is acceptable. Because,
- It was predicted at the earlier days of computer.
- Thomas Watson predicted that he will get only five orders for the new kind of computer.
- He went across the country around 20 concerns and he got 18 orders.
- So Thomas Watson’s prediction on the computer failed.
Second prediction:
The second prediction is acceptable. Because,
- After ANIAC there are many kind of computers developed with idea of vacuum tubes.
- Some of the computers might have contained 1000 vacuum tubes.
Third prediction:
The third prediction is completely wrong. Because,
- It says data processing will not last for a year. Data processing is very vital in now days.
- It helps to generate organized information which will be easy to understand.
Fourth prediction:
Fourth prediction was wrong. Because,
- Microchips is the main hardware used in every electronic device.
- This prediction was done at the earlier days of computer. But microchips were used at that time also...
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Methods (Ch6) - Review
1. (The MyRoot method) Below is a manual implementation of the Math.sqrt() method in Java.
There are two methods, method #1 which calculates the square root for positive integers, and
method #2, which calculates the square root of positive doubles (also works for integers).
public class SquareRoot {
public static void main(String[] args) {
}
// implement a loop of your choice here
// Method that calculates the square root of integer variables
public static double myRoot(int number) {
double root;
root=number/2;
double root old;
do {
root old root;
root (root_old+number/root_old)/2;
} while (Math.abs(root_old-root)>1.8E-6);
return root;
}
// Method that calculates the square root of double variables
public static double myRoot(double number) {
double root;
root number/2;
double root_old;
do {
root old root;
root (root_old+number/root_old)/2;
while (Math.abs (root_old-root)>1.0E-6);
return root;
}
}
Program-it-Yourself: In the main method, create a program that…
I would like to know the main features about the following 3 key concepts:1. Backup Domain Controller (BDC)2. Access Control List (ACL)3. Dynamic Memory
Chapter 1 Solutions
Computer Science Illuminated
Ch. 1 - Prob. 1ECh. 1 - Prob. 2ECh. 1 - Prob. 3ECh. 1 - Prob. 4ECh. 1 - Prob. 5ECh. 1 - Prob. 6ECh. 1 - Prob. 7ECh. 1 - Prob. 8ECh. 1 - Prob. 9ECh. 1 - Prob. 10E
Ch. 1 - Prob. 11ECh. 1 - Prob. 12ECh. 1 - Prob. 13ECh. 1 - Prob. 14ECh. 1 - Prob. 15ECh. 1 - Prob. 16ECh. 1 - Prob. 17ECh. 1 - Prob. 18ECh. 1 - Prob. 19ECh. 1 - Prob. 20ECh. 1 - Prob. 21ECh. 1 - Prob. 22ECh. 1 - Prob. 23ECh. 1 - Prob. 24ECh. 1 - Prob. 25ECh. 1 - Prob. 26ECh. 1 - Prob. 27ECh. 1 - Prob. 28ECh. 1 - Prob. 29ECh. 1 - Prob. 30ECh. 1 - Prob. 31ECh. 1 - Prob. 32ECh. 1 - Prob. 33ECh. 1 - Prob. 34ECh. 1 - Prob. 35ECh. 1 - Prob. 36ECh. 1 - Prob. 37ECh. 1 - Prob. 38ECh. 1 - Prob. 39ECh. 1 - Prob. 40ECh. 1 - Prob. 41ECh. 1 - Prob. 42ECh. 1 - Prob. 43ECh. 1 - Prob. 44ECh. 1 - Prob. 45ECh. 1 - Prob. 46ECh. 1 - Prob. 47ECh. 1 - Prob. 48ECh. 1 - Prob. 50ECh. 1 - Prob. 51ECh. 1 - Prob. 52ECh. 1 - Prob. 53ECh. 1 - Prob. 54ECh. 1 - Prob. 55ECh. 1 - Prob. 56ECh. 1 - Prob. 57ECh. 1 - Prob. 58ECh. 1 - Prob. 59ECh. 1 - Prob. 1TQCh. 1 - Prob. 2TQCh. 1 - Prob. 3TQCh. 1 - Prob. 4TQ
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