Assume that you fancy polynomial splines, while you actually need ƒ(t) = e²/3 – 1 for t€ [−1, 1].
See the figure for a plot of f(t).
Your goal is to approximate f(t) with an inter-
polating polynomial spline of degree d that is
given as sa(t)
=
•
Σk=0 Pd,k bd,k(t) so that
sd(tk) = = Pd,k for tk = −1 + 2 (given d > 0)
with basis functions bd,k(t) = Σi±0 Cd,k,i
=
•
The special case of d 0 is trivial: the only
basis function b0,0 (t) is constant 1 and so(t) is
thus constant po,0 for all t = [−1, 1].
...9
The d+1 basis functions bd,k (t) form a ba-
sis Bd {ba,o(t), ba,1(t), bd,d(t)} of the
function space of all possible sα (t) functions.
Clearly, you wish to find out, which of them
given a particular maximal degree d is the
best-possible approximation of f(t) in the least-
squares sense.
_
1
0.9
0.8
0.7
0.6
0.5
0.4
0.3
0.2
0.1
0
-0.1
-0.2
-0.3
-0.4
-0.5
-0.6
-0.7
-0.8
-0.9
-1
function f(t) = exp((2t)/3) - 1 to project
-1 -0.9 -0.8 -0.7 -0.6 -0.5 -0.4 -0.3 -0.2 -0.1
0
0.1 0.2 0.3 0.4 0.5…
An image processor considered a 750×750 pixels large subset of an image and converted it into gray-scale,
resulting in matrix gIn - a false-color visualization of gIn is shown in the top-left below. He prepared a
two-dim. box filter f1 as a 25×25 matrix with only the 5×5 values in the middle being non-zero – this filter
is shown in the top-middle position below. He then convolved £1 with itself to get £2, before convolving £2
with itself to get f3. In both of the steps, he maintained the 25×25 size.
Next, he convolved gIn with £3 to get gl. Which of the six panels below shows g1? Argue by explaining
all the steps, so far: What did the image processor do when preparing ₤3? What image processing operation
(from gin to g1) did he prepare and what's the effect that can be seen?
Next, he convolved the rows of f3 with filter 1/2 (-1, 8, 0, -8, 1) to get f4 - you find a visualization of
filter f 4 below. He then convolved gIn with f4 to get g2 and you can find the result shown below. What…
3ur
Colors are enchanting and elusive. A multitude of color systems has been proposed
over a three-digits number of years - maybe more than the number of purposes that
they serve...
-
Everyone knows the additive RGB color system – we usually serve light-emitting IT
components like monitors with colors in that system. Here, we use c = (r, g, b) RGB
with r, g, bЄ [0,1] to describe a color c.
=
T
For printing, however, we usually use the subtractive CMY color system. The same
color c becomes c = (c, m, y) CMY (1-c, 1-m, 1-y) RGB Note how we
use subscripts to indicate with coordinate system the coordinates correspond to.
Explain, why it is not possible to find a linear transformation between RGB and CMY
coordinates.
Farbenlehr c
von Goethe
Erster Band.
Roſt einen Defte mit fergen up
Tübingen,
is et 3. Cotta'fden Babarblung.
ISIO
Homogeneous coordinates give us a work-around: If we specify colors in 4D, instead, with the 4th coordinate
being the homogeneous coordinate h so that every actual…
A Problem Solving Approach To Mathematics For Elementary School Teachers (13th Edition)
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, algebra and related others by exploring similar questions and additional content below.