Universe
11th Edition
ISBN: 9781319039448
Author: Robert Geller, Roger Freedman, William J. Kaufmann
Publisher: W. H. Freeman
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Chapter 1, Problem 38Q
To determine
The misinformation in the statement made by Han Solo in the movie ‘Star Wars’ that “It’s the ship has made the Kessel run in less than 12 parsecs”.
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Students have asked these similar questions
I attempted to answer this question and I'm not sure what I am doing wrong. My formula says A.S. = 206265 (separation/distance from observer)
I know to convert to the same units, so I ended up with 80 Million Km being 8 x 10 ^ -6 LY
Could you please explain each step especially for the part that I got wrong for both A and B?
A light-year is the distance that light can travel in one year. Similarly, we can define a light-second, light-day, etc. as the distance that light can travel in other time intervals. Calculate the distance represented by each of the following: (Assume that the speed of light is 3 x 10^8m/s)
5 light-minutes
6 light-days
6 light-days, but this time answer in miles (enter just the number with no units)
mathematician Archimedes, responding to a claim that the number of grains of sand was infinite,
calculated that the number of grains of sand needed to fill the universe was on the order of 1063. Our
understanding of the size of the universe has changed since then, and we now know that the
observable universe alone is a sphere with a radius of 1026 m. Estimating the size of a grain of sand,
A) Approximately how many grains of sand would fill the observable universe?
B) How many times larger or smaller is this number than Archimedes' result?
Chapter 1 Solutions
Universe
Ch. 1 - Prob. 1CCCh. 1 - Prob. 2CCCh. 1 - Prob. 3CCCh. 1 - Prob. 1QCh. 1 - Prob. 2QCh. 1 - Prob. 3QCh. 1 - Prob. 4QCh. 1 - Prob. 5QCh. 1 - Prob. 6QCh. 1 - Prob. 7Q
Ch. 1 - Prob. 8QCh. 1 - Prob. 9QCh. 1 - Prob. 10QCh. 1 - Prob. 11QCh. 1 - Prob. 12QCh. 1 - Prob. 13QCh. 1 - Prob. 14QCh. 1 - Prob. 15QCh. 1 - Prob. 16QCh. 1 - Prob. 17QCh. 1 - Prob. 18QCh. 1 - Prob. 19QCh. 1 - Prob. 20QCh. 1 - Prob. 21QCh. 1 - Prob. 22QCh. 1 - Prob. 23QCh. 1 - Prob. 24QCh. 1 - Prob. 25QCh. 1 - Prob. 26QCh. 1 - Prob. 27QCh. 1 - Prob. 28QCh. 1 - Prob. 29QCh. 1 - Prob. 30QCh. 1 - Prob. 31QCh. 1 - Prob. 32QCh. 1 - Prob. 33QCh. 1 - Prob. 34QCh. 1 - Prob. 35QCh. 1 - Prob. 36QCh. 1 - Prob. 37QCh. 1 - Prob. 38QCh. 1 - Prob. 39QCh. 1 - Prob. 40QCh. 1 - Prob. 41QCh. 1 - Prob. 42QCh. 1 - Prob. 43QCh. 1 - Prob. 44Q
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- given: a (distance to center of galaxy in AU) = 1,717,914,439 AU P (suns orbital period in years) = 203,782,828.3 years M (mass of milky way galaxy in solar masses) = 1.22 x 10^11 Msun Question: Assume the Milky Way Galaxy is made up entirely of stars like the Sun, i.e. on average each star has the mass of 1 MSun. Under this assumption, approximately how many stars are there in our galaxy? Express this answer in billions of stars (1 billion = 109).arrow_forwardCan someone help with this?arrow_forwardIf Jim could drive a Jetson's flying car at a constant speed of 330 km/hr across oceans and space, approximately how long (in millions of years, in 106 years) would he take to drive to a nearby star that is 8.7 light-years away? Use 9.461 × 1012 km/light-year and 8766 hours per year (365.25 days).arrow_forward
- Recent findings in astrophysics suggest that the observable universe can be modeled as a sphere of radius R=13.7x109 light-years=13.0 x 1025m with an average total mass density of about 1x10-26 kg/m3 Only about 4% of total mass is due to “ordinary” matter (such as protons, neutrons, and electrons). Estimate how much ordinary matter (in kg) there is in the observable universe. (For the light-year, see Problem 19.)arrow_forwardG:06)arrow_forwardThe Tully-Fischer method relies on being able to relate the mass of a galaxy to its rotation velocity. Stars in the outer-most regions of the Milky Way galaxy, located at a distance of 50 kpc from the galactic centre, are observed to orbit at a speed vrot = 250 km s−1. Using Kepler’s 3rd Law, determine the mass in the Milky Way that lies interior to 50 kpc. Express your answer in units of the Solar mass.arrow_forward
- Instruction: Complete the Venn Diagram by providing the similarities and differences of the Ptolemaic, Copernican and Tychonic model of the universe. lutalud (etnioq a S) (enioc a) bogotleog henoit200 falog 00) sbbiobua e boa (etriog 01 sbbtobijspe 1ele batdu beeb ert Ptolemaic Model mit n cku2 Copernican Model イm a.v Wilsutonu Vetniog Ot) (eniog (einioq 0t) (anicg a.c) oria callon aissage teerda Joerie sen ai 1sene tos leegCs Vlsienagstsiogiooni bns, wivits (etnioq s vhooqTuy bongieab isuelV enpiati eldsbee. bns- of mese jon 2sob l etno tromeiqmoo of mese ob aesU beau albejco sbbtobysre Inol gniesigllisuaiVanpizeb pniniviisuetv elds vese bne pritivG eol vese bns bsa of slsn as 2saU emelomo (stnioa dT8) baeu eldo sbbiobusre (einic ) (ainiog es r) d bebriemmo09i bos beweivebeben vd bisge)9 vd bevordA Isqionh Tychonic Modelarrow_forwardPhysics 17 & 19 please.arrow_forwardAccording to the tiny world experiment, there are only 5.2 intermediates between any two people on Earth (thus 6-degree of separation). This is a remark that has been made for well over half a century. The Internet may be useful in this regard. Let's pretend that everyone on Earth doubles their friend count on Facebook, Twitter, and every other social network they participate in (2x). Calculate the relative distance between us now. What do you think it is?arrow_forward
- Using our example from the previous unit, let's try to determine the Hubble time for this example universe. You were given that a good representative galaxy receded at a speed of 4000 km/s and was found to be 20 Mpc away. With that in mind, what would the age of that universe be in years (aka what is that universe's Hubble time)? Go ahead and take the number of kilometers per Mpc to be approximately 3.1*10^19 km/Mpc. While this problem may look scary at first, this is really just bringing you full circle to one of the unit conversion problems you encountered at the beginning of this course.arrow_forwardI answer is not 100, I also tried 21. I need help! Thank you!arrow_forwardLet us imagine that the spectrum of a star is collected and we find the absorption line of Hydrogen-Alpha (the deepest absorption line of hydrogen in the visible part of the electromagnetic spectrum) to be observed at 656.5 nm instead of 656.3 nm as measured in a lab here on Earth. What is the velocity of this star in m/s? (Hint: speed of light is 3*10^8 m/s; leave the units off of your answer)arrow_forward
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