Free-Falling Object In Exercises 37 and 38. use the position function s ( t ) = − 4.9 t 2 + 250 which gives the height (in meters) of an object that has fallen for t seconds from a height of 250 meters. The velocity at time t = a seconds is given by lim t → a s ( a ) − s ( t ) a − t Find the velocity of the object when t = 4 .
Free-Falling Object In Exercises 37 and 38. use the position function s ( t ) = − 4.9 t 2 + 250 which gives the height (in meters) of an object that has fallen for t seconds from a height of 250 meters. The velocity at time t = a seconds is given by lim t → a s ( a ) − s ( t ) a − t Find the velocity of the object when t = 4 .
Free-Falling Object In Exercises 37 and 38. use the position function
s
(
t
)
=
−
4.9
t
2
+
250
which gives the height (in meters) of an object that has fallen for t seconds from a height of 250 meters. The velocity at time
t
=
a
seconds is given by
For the system consisting of the lines:
and
71 = (-8,5,6) + t(4, −5,3)
72 = (0, −24,9) + u(−1, 6, −3)
a) State whether the two lines are parallel or not and justify your answer.
b) Find the point of intersection, if possible, and classify the system based on the
number of points of intersection and how the lines are related. Show a complete
solution process.
3. [-/2 Points]
DETAILS
MY NOTES
SESSCALCET2 7.4.013.
Find the exact length of the curve.
y = In(sec x), 0 ≤ x ≤ π/4
H.w
WI
M
Wz
A
Sindax
Sind dy max
Утах
at 0.75m from A
w=6KN/M L=2
W2=9 KN/m
P= 10 KN
B
Make the solution handwritten and not
artificial intelligence because I will
give a bad rating if you solve it with
artificial intelligence
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