Explanation Given The stated reaction is, C 2 H 5 OH ( l ) + 3 O 2 ( g ) → 2 CO 2 ( g ) + 3 H 2 O ( l ) The standard enthalpy of formation of one mole of CO 2 is − 393.5 kJ . The standard enthalpy of formation of one mole of H 2 O is − 285.83 kJ . The standard enthalpy of formation of one mole of C 2 H 5 OH is − 277.7 kJ . The standard enthalpy of formation of one mole of O 2 is 0 kJ . The enthalpy change of the reaction is calculated by the formula,] Δ H r e a c t i o n ° = ∑ n Δ H f ° ( products ) − ∑ m Δ H f ° ( reactancts ) = [ 2 Δ H f ° ( CO 2 ) + 3 Δ H f ° ( H 2 O ) ] − [ Δ H f ° ( C 2 H 5 OH ) + 3 Δ H f ° ( O 2 ) ] Where, Δ H r e a c t i o n ° is the enthalpy change of the reaction

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Chapter 1, Problem 32E

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The enthalpy change for the given combustion reaction.

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The enthalpy change for the given combustion reaction.

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To determine: The enthalpy change for the given combustion reaction.

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To determine:

The enthalpy change for the given combustion reaction.