COLLEGE PHYSICS
COLLEGE PHYSICS
2nd Edition
ISBN: 9781464196393
Author: Freedman
Publisher: MAC HIGHER
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Chapter 1, Problem 31QAP
To determine

(A)

The value of 125 cm into m.

Expert Solution
Check Mark

Answer to Problem 31QAP

The numerical value for 125 cm is  1.25 m

Explanation of Solution

Given data:

The given value is 125 cm.

Formula used:

For numerical value convert cm into m,

  cm100 m

Calculation:

Conversion of cm into m,

  125100 m1.25 m

Conclusion:

Thus, numerical value for 125 cm is  1.25 m.

To determine

(B)

The value of 233 g into kg.

Expert Solution
Check Mark

Answer to Problem 31QAP

The numerical value for 233 g is  0.233 Kg

Explanation of Solution

Given data:

The given value is 233 g

Formula used:

For numerical value convert g into kg,

  g1000 kg

Calculation:

Conversion of g into kg,

  2331000 kg0.233 kg

Conclusion:

Thus, numerical value for 233 g is  0.233 kg

To determine

(C)

The value of 786 ms into s.

Expert Solution
Check Mark

Answer to Problem 31QAP

The numerical value for 786 ms is  0.786 s

Explanation of Solution

Given data:

The given value is 786 ms

Formula used:

For numerical value convert ms into s,

  ms1000s

Calculation:

Conversion of ms into s,

  7861000 s0.786 s

Conclusion:

Thus, numerical value for 786 ms is  0.786 s

To determine

(D)

The value of 454 kg into mg.

Expert Solution
Check Mark

Answer to Problem 31QAP

The numerical value for 454 kg is  454000000 mg

Explanation of Solution

Given data:

The given value is 454 kg

Formula used:

For numerical value convert kg into mg,

  kg×1000000 mg

Calculation:

Conversion of kg into mg,

  454×106 mg454000000 mg

Conclusion:

Thus, numerical value for 454 kg is  454000000 mg

To determine

(E)

The value of  208 cm2 into  m2.

Expert Solution
Check Mark

Answer to Problem 31QAP

The numerical value for  208 cm2 is  0.0208 m2

Explanation of Solution

Given data:

The given value is  208 cm2

Formula used:

For numerical value convert  cm2 into  m2,

    cm210000  m2

Calculation:

Conversion of cm2 into m2,

  20810000  m20.0208  m2

Conclusion:

Thus, numerical value for  208 cm2 is  0.0208 m2

To determine

(F)

The value of  444 m2 into  cm2.

Expert Solution
Check Mark

Answer to Problem 31QAP

The numerical value for  444 m2 is  4440000 cm2

Explanation of Solution

Given data:

The given value is  444 m2

Formula used:

For numerical value convert  m2 into  cm2,

   m2×10000 cm2

Calculation:

Conversion of m2 into cm2,

  444×10000  cm24440000  cm2

Conclusion:

Thus, numerical value for  444 m2 is  4440000 cm2

To determine

(G)

The value of  12.5 cm3 into  m3.

Expert Solution
Check Mark

Answer to Problem 31QAP

The numerical value for  12.5 cm3 is  12.5×106 m3

Explanation of Solution

Given data:

The given value is  12.5 cm3

Formula used:

For numerical value convert cm3 into m3,

  cm31000000 m3

Calculation:

Conversion of cm3 into m3,

  12.51000000 m312.5×10-6 m3

Conclusion:

Thus, numerical value for  12.5 cm3 is  12.5×106 m3

To determine

(H)

The value of  144 m3 into  cm3.

Expert Solution
Check Mark

Answer to Problem 31QAP

The numerical value for  144 m3 is  144×106 cm3

Explanation of Solution

Given data:

The given value is  144 m3

Formula used:

For numerical value convert  m3 into cm3,

  m3×1000000 cm3

Calculation:

Conversion of  m3 into cm3,

  144×100000 cm3144×106 cm3

Conclusion:

Thus, numerical value for  144 m3 is  144×106 cm3

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