Show the output of the following code:
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Introduction to Programming with C++
- Nonearrow_forward#include using namespace std; void some_action_1(int); int main() { cout<arrow_forwardNonearrow_forwardVoid Do1 (int: &, a. int &b) { a = 5; a = a + b; b = a + 2; } Int main() { Int x = 10; Do1 (x,x); Cout << x << endl; } The output of this program isarrow_forwardDETERMINE THE OUTPUT OF THE CODE: #include using namespace std; int main() { int i; for (i = 0; i > 10; i++){ %D {cout << i <<" "; } } return 0; }arrow_forward#include<iostream>using namespace std;void main(){double pi = 0, denominator = 1;int counter = 999999;for (int x = 0; x < counter; x++){if (x % 2 != 0){pi = pi - (1 / denominator);}else{pi = pi + (1 / denominator);}denominator = denominator + 2;}pi = pi * 4;cout << " So the computed value of a PI is = " << pi << endl;cout << " ";//return 0;system("pause");} Note: This a program called ComputePI to compute the value of π Tutor just have to Modify This program to use nested-if (if ... else if ... else if ... else) instead. Explain by applying a double line commentarrow_forward1#include 2 #include #include 4 #include 3 5 sem_t fork[3]; 6 7 void eat (int phil) { 8 printf("Philosopher %d is eating\n", phil); sleep (2); //time eating 9 10} 11 void philosopher (void * num) { int phil-*(int *)num; 12 13 printf("Philosopher %d wants to eat\n", phil); 14 sem_wait (&fork[phil]); 15 sem_wait (&fork [(phil+1)]); 16 eat (phil); 17 18 printf("Philosopher %d has finished eating\n",phil); sem_post(&fork [(phil+1)]); sem_post(&fork[phil]); 19 20} 21 int main(){ 22 int i, a[3]; 23 pthread_t tid[3]; for(i=0;i<3; i++) 24 25 sem_init(&fork[i],0,1); 26 for(i=0;i<3; i++){ 27 a[i]=i; 28 pthread_create(&tid[i], NULL, philosopher, (void *)&a[i]); 29 } 30 for(i=0;i<3;i++) 31 pthread_join(tid[i],NULL); 32} Fig.1 Figure 1 shows a program that tries to solve the dining philosophers' problem given that it only includes 3 philosophers who want to eat, where only 3 forks are available and each philosopher needs two forks. The outputs after running the program are given in Figure 2. In the…arrow_forwardstate whether the program base on the output is CORRECT or INCORRECT.arrow_forwardThis assignment is not graded, I just need to understand how to do it. Please help, thank you! Language: C++ Given: Main.cpp #include #include "Shape.h" using namespace std; void main() { /////// Untouchable Block #1 ////////// Shape* shape; /////// End of Untouchable Block #1 ////////// /////// Untouchable Block #2 ////////// if (shape == nullptr) { cout << "What shape is this?! Good bye!"; return; } cout << "The perimeter of your " << shape->getShapeName() << ": " << shape->getPerimeter() << endl; cout << "The area of your " << shape->getShapeName() << ": " << shape->getArea() << endl; /////// End of Untouchable Block #2 //////////} Shape.cpp string Shape::getShapeName() { switch (mShapeType) { case ShapeType::CIRCLE: return "circle"; case ShapeType::SQUARE: return "square"; case ShapeType::RECTANGLE: return "rectangle"; case…arrow_forwardusing System; using System.Linq; using System.Text; namespace Games; { class Program { staticvoid Main(string[] args) { int choice,games_choice; cout<<"What are your favorite games - outdoor or indoor"<<endl; cout<<"Press 1 for 'outdoor' or Press 2 for 'indoor'"<<endl; cin>>choice; if(choice==1) { cout<<"What is your favorite outdoor game"<<endl; cout<<"Press 1 for Tennis"<<endl; cout<<"Press 2 for Football"<<endl; cout<<"Press 3 for Cricket"<<endl; cin>>games_choice; if(games_choice==1) cout<<"I also like Tennis"<<endl; elseif(games_choice==2) cout<<"I also like Football"<<endl; elseif(games_choice==3) cout<<"I also like Cricket"<<endl; } elseif(choice==2) { cout<<"What is your favorite indoor game"<<endl; cout<<"Press 1 for Ludo"<<endl; cout<<"Press 2 for Chess"<<endl; cout<<"Press 3 for Cards"<<endl;…arrow_forward#include using namespace std3; int main() { int x-6; int y=103; int z=0; int q=1; Z+= X-- -ys q*=++z+y; cout<arrow_forwardFill in the blanksarrow_forwardarrow_back_iosSEE MORE QUESTIONSarrow_forward_iosRecommended textbooks for you
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