INFORMATION TECH.PROJECT...-W/MINDTAP
INFORMATION TECH.PROJECT...-W/MINDTAP
9th Edition
ISBN: 9781337586801
Author: SCHWALBE
Publisher: CENGAGE L
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Chapter 1, Problem 2DQ

Explanation of Solution

Project:

  • A project is actually a temporary endeavor for creating a unique product, service or result.
  • A project is a temporary social system which is constituted by teams to accomplish specific tasks under specified time.
  • Project is a set of interrelated tasks which is to be executed over a fixed period of time and within certain cost and within other limitations.
  • A project or a program can be treated as an undertaking that involves research or design and is planned for achieving a particular goal.

Main attributes of a project:

The main attributes of a software project include the following.

  • A project needs a well-defined objective
    • The main objective of project can be defined in terms of scope, schedule and cost...

Explanation of Solution

Difference of project from day to day jobs:

ProjectDay to day job
The project activities will be completed only when the project is stopped.Day to day work will continue on an ongoing basis and is required even after the project finishes...

Explanation of Solution

Triple constraint:

  • In terms of scope, time and cost goals, every project is constrained in different ways. In project management, these limitations are termed as triple constraint.
  • Triple constraint is also termed as project management triangle or iron triangle...

Explanation of Solution

Factors affecting a project:

  • Deadline:
    • Deadline is one of the factors that determine how a project will be handled.
    • Missing a deadline will create a bad impression on the team.
  • Budget:
    • Budget is another factor that determines project’s progress and management.
    • The number of days for completing the project and the number of resources will be more if there is high budget.
  • Stakeholders:
    • Depending on the kind of stakeholders for the project, techniques for managing a project will vary...

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The next problem concerns the following C code: /copy input string x to buf */ void foo (char *x) { char buf [8]; strcpy((char *) buf, x); } void callfoo() { } foo("ZYXWVUTSRQPONMLKJIHGFEDCBA"); Here is the corresponding machine code on a Linux/x86 machine: 0000000000400530 : 400530: 48 83 ec 18 sub $0x18,%rsp 400534: 48 89 fe mov %rdi, %rsi 400537: 48 89 e7 mov %rsp,%rdi 40053a: e8 di fe ff ff callq 400410 40053f: 48 83 c4 18 add $0x18,%rsp 400543: c3 retq 400544: 0000000000400544 : 48 83 ec 08 sub $0x8,%rsp 400548: bf 00 06 40 00 mov $0x400600,%edi 40054d: e8 de ff ff ff callq 400530 400552: 48 83 c4 08 add $0x8,%rsp 400556: c3 This problem tests your understanding of the program stack. Here are some notes to help you work the problem: ⚫ strcpy(char *dst, char *src) copies the string at address src (including the terminating '\0' character) to address dst. It does not check the size of the destination buffer. • You will need to know the hex values of the following characters:
1234 3. Which line prevents compiler optimization? Circle one: 1234 Suggested solution: Store strlen(str) in a variable before the if statement. ⚫ Remove the if statement. Replace index 0 && index < strlen(str)) { 5 } } = str [index] = val;
Character Hex value | Character Hex value Character Hex value 'A' 0x41 'J' Ox4a 'S' 0x53 'B' 0x42 'K' 0x4b "T" 0x54 0x43 'L' Ox4c 'U' 0x55 0x44 'M' 0x4d 'V' 0x56 0x45 'N' Ox4e 'W' 0x57 0x46 '0' Ox4f 'X' 0x58 0x47 'P' 0x50 'Y' 0x59 0x48 'Q' 0x51 'Z' Ox5a 'T' 0x49 'R' 0x52 '\0' 0x00 Now consider what happens on a Linux/x86 machine when callfoo calls foo with the input string "ZYXWVUTSRQPONMLKJIHGFEDCBA". A. On the left draw the state of the stack just before the execution of the instruction at address Ox40053a; make sure to show the frames for callfoo and foo and the exact return address, in Hex at the bottom of the callfoo frame. Then, on the right, draw the state of the stack just after the instruction got executed; make sure to show where the string "ZYXWVUTSRQPONMLKJIHGFEDCBA" is placed and what part, if any, of the above return address has been overwritten. B. Immediately after the ret instruction at address 0x400543 executes, what is the value of the program counter register %rip?…
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