COLLEGE PHYSICS-ACHIEVE AC (1-TERM)
COLLEGE PHYSICS-ACHIEVE AC (1-TERM)
3rd Edition
ISBN: 9781319453916
Author: Freedman
Publisher: MAC HIGHER
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Chapter 1, Problem 28QAP
To determine

(A)

The number 4.42× 103 in decimal notation.

Expert Solution
Check Mark

Answer to Problem 28QAP

The number 4.42× 103 in decimal notation is 0.00442

Explanation of Solution

Given data:

The given number is 4.42× 103

Formula used:

For decimal notation,

  z= m10n

Calculation:

Decimal notation,

  z= 4.42103z=0.00442 

Conclusion:

Thus, number 4.42× 103 in decimal notation is 0.00442.

To determine

(B)

The number 7.09× 106 in decimal notation.

Expert Solution
Check Mark

Answer to Problem 28QAP

The number 7.09× 106 in decimal notation is 0.00000709.

Explanation of Solution

Given data:

The given number is 7.09× 106.

Formula used:

For decimal notation,

  z= m10n

Calculation:

Decimal notation,

  z= 7.09106z=0.00000709 

Conclusion:

Thus, number 7.09× 106 in decimal notation is 0.00000709.

To determine

(C)

The number 8.28× 102 in decimal notation.

Expert Solution
Check Mark

Answer to Problem 28QAP

The number 8.28× 102 in decimal notation is 828.0

Explanation of Solution

Given data:

The given number is 8.28× 102.

Formula used:

For decimal notation,

  z= m×10n

Calculation:

Decimal notation,

  z= 8.28× 102z=828.0 

Conclusion:

Thus, number 8.28× 102 in decimal notation is 828.0

To determine

(D)

The number 6.02× 106 in decimal notation.

Expert Solution
Check Mark

Answer to Problem 28QAP

The number 6.02× 106 in decimal notation is 6020000.0

Explanation of Solution

Given data:

The given number is 6.02× 106.

Formula used:

For decimal notation,

  z= m×10n

Calculation:

Decimal notation,

  z= 6.02×106z=6020000

Conclusion:

Thus, number 6.02× 106 in decimal notation is 6020000.0

To determine

(E)

The number 456× 103 in decimal notation.

Expert Solution
Check Mark

Answer to Problem 28QAP

The number 456× 103 in decimal notation is 456000.0

Explanation of Solution

Given data:

The given number is 456× 103

Formula used:

For decimal notation,

  z= m×10n

Calculation:

Decimal notation,

  z= 456×103z=456000.0 

Conclusion:

Thus, number 456× 103 in decimal notation is 456000.0

To determine

(F)

The number 22.4× 103 in decimal notation.

Expert Solution
Check Mark

Answer to Problem 28QAP

The number 22.4× 103 in decimal notation is 0.0224

Explanation of Solution

Given data:

The given number is 22.4× 103

Formula used:

For decimal notation,

  z= m10n

Calculation:

Decimal notation,

  z= 22.4103z=0.0224 

Conclusion:

Thus, number 22.4× 103 in decimal notation is 0.0224

To determine

(G)

The number 0.375× 104 in decimal notation.

Expert Solution
Check Mark

Answer to Problem 28QAP

The number 0.375× 104 in decimal notation is 0.0000375

Explanation of Solution

Given data:

The given number is 0.375× 104

Formula used:

For decimal notation,

  z= m10n

Calculation:

Decimal notation,

  z= 0.375104z=0.0000375

Conclusion:

Thus, number 0.375× 104 in decimal notation is 0.0000375

To determine

(H)

The number 138× 106 in decimal notation.

Expert Solution
Check Mark

Answer to Problem 28QAP

The number 138× 106 in decimal notation is 0.000138

Explanation of Solution

Given data:

The given number is 138× 106

Formula used:

For decimal notation,

  z= m10n

Calculation:

Decimal notation,

  z= 138106z=0.000138 

Conclusion:

Thus, number 138× 106 in decimal notation is 0.000138.

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