
ELECTRICAL WIRING:RESIDENTAL-6 PLANS
18th Edition
ISBN: 9781305098329
Author: MULLIN
Publisher: CENGAGE L
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Chapter 1, Problem 25R
a.
To determine
Whether the use of stepladder without fully locked is a safe practice or not.
b.
To determine
Who is responsible for ladder collapse fault.
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The MATLAB code is going well but the last part in bandpass, the legend that is supposed to tell the color of both lower and upper-frequency cutoff does not align with each other. As such I need help
My Matlab code:
% Define frequency range for the plot
f = logspace(1, 5, 500); % Frequency range from 10 Hz to 100 kHz
w = 2 * pi * f; % Angular frequency
% Parameters for the filters
R = 1e3; % Resistance in ohms (1 kΩ)
C = 1e-6; % Capacitance in farads (1 μF)
L = 0.1; % Inductance in henries (chosen for proper bandpass response)
% Compute cutoff frequencies
f_cutoff_RC = 1 / (2 * pi * R * C); % RC low-pass/high-pass cutoff
f_resonance = 1 / (2 * pi * sqrt(L * C)); % Resonant frequency of RLC
Q_factor = (1/R) * sqrt(L/C); % Quality factor of the circuit
% Band-pass filter cutoff frequencies
f_lower_cutoff = f_resonance / (sqrt(1 + 1/(4*Q_factor^2)) + 1/(2*Q_factor));
f_upper_cutoff = f_resonance / (sqrt(1 + 1/(4*Q_factor^2)) - 1/(2*Q_factor));
% Define Transfer Functions
H_low =…
1°
⑤
Aa
"Human-written solution required"
2. Using the characteristics of Fig. 6.11, determine ID for the following levels of VGs (with
VDS > VP):
a. VGs = 0V.
b. VGs=-1 V.
c. VGs -1.5 V.
d. VGS
-1.8 V.
e. VGS = -4 V.
f. VGs=-6V.
3. Using the results of problem 2 plot the transfer characteristics of ID vs. VGS-
4. a. Determine Vps for VGs = 0V and Ip = 6 mA using the characteristics of Fig. 6.11.
b. Using the results of part (a), calculate the resistance of the JFET for the region Ip = 0 to
6 mA for VGs =0V.
c. Determine Vps for VGS = -1 V and ID = 3 mA.
d. Using the results of part (c), calculate the resistance of the JFET for the region ID = 0 to
3 mA for VGs -1 V.
e. Determine Vps for VGs = -2 V and ID = 1.5 mA.
f. Using the results of part (e), calculate the resistance of the JFET for the region ID = 0 to
1.5 mA for VGS-2 V.
g. Defining the result of part (b) as ro, determine the resistance for VGs -1 V using
Eq. (6.1) and compare with the results of part (d).
h. Repeat part (g)…
①
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Chapter 1 Solutions
ELECTRICAL WIRING:RESIDENTAL-6 PLANS
Ch. 1 - Prob. 1RCh. 1 - Prob. 2RCh. 1 - Does the NEC provide minimum or maximum standards?...Ch. 1 - What do the letters UL signify?Ch. 1 - What section of the NEC states that all listed or...Ch. 1 - Prob. 6RCh. 1 - Prob. 7RCh. 1 - Does compliance with the NEC always result in an...Ch. 1 - Name two nationally recognized testing...Ch. 1 - Prob. 10R
Ch. 1 - Prob. 12RCh. 1 - A junction box on a piece of European equipment is...Ch. 1 - Prob. 14RCh. 1 - You will learn in Chapter 3 that residential...Ch. 1 - Prob. 16RCh. 1 - What can you do to reduce or eliminate the...Ch. 1 - What is the NEC definition of a qualified person?Ch. 1 - Are low-voltage systems totally safe? Explain.Ch. 1 - Prob. 21RCh. 1 - What do the letters PPE stand for?...Ch. 1 - Prob. 23RCh. 1 - Where might you obtain information about...Ch. 1 - Prob. 25R
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- 4. a. Determine VDs for VGS = 0 V and ID = 6 mA using the characteristics of Fig. 6.11. b. Using the results of part (a), calculate the resistance of the JFET for the region ID = 0 to 6 mA for VGS = 0 V. c. Determine VDs for VGS = -1 V and ID = 3 mA. d. Using the results of part (c), calculate the resistance of the JFET for the region ID = 0 to 3 mA for VGS = -1 V. e. Determine VDs for VGS = -2 V and ID = 1.5 mA. f. Using the results of part (e), calculate the resistance of the JFET for the region ID = 0 to 1.5 mA for VGS = -2 V. g. Defining the result of part (b) as ro, determine the resistance for VGS = -1 V using Eq. (6.1) and compare with the results of part (d). h. Repeat part (g) for VGS = -2 V using the same equation, and compare the results with part (f). i. Based on the results of parts (g) and (h), does Eq. (6.1) appear to be a valid approximation?arrow_forwardA. Using D flip-flops, design a logic circuit for the finite-state machine described by the state assigned table in Fig. 1. Present Next State State Output x=0 x=1 Y2Y1 Y2Y1 YY Z 00 00 01 0 01 10 11 888 00 10 0 00 10 1 00 10 1 Fig. 1arrow_forwardAthree phase a.c. distributor AB has: A B C The distance from A to B is 500 m. The distance from A to C is 800 m. The impedance of each section is (6+j 8) /km. The voltage at the far end is maintained at 250 volt. Find: sending voltage, sending current, supply power factor and 80A 60 A total voltage drop. 0.8 lag. P.f 0.6 lead. p.farrow_forward
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