Inorganic Chemistry
Inorganic Chemistry
5th Edition
ISBN: 9781292134147
Author: Housecroft, Catherine E.
Publisher: Pearson,
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Chapter 1, Problem 1P

Chromium has four isotopes C 24 50 r , C 24 52 r , C 24 53 r and C 24 54 r . How many electrons, protons, and neutrons does each isotope possess?

Expert Solution & Answer
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Interpretation Introduction

Interpretation:

The number of electrons, protons, and neutrons present in the given isotopes of Chromium (C2450r, C2452r, C2453r and C2454r) are to be determined.

Concept Introduction:

Nuclides of the same element possess the same number of protons and electrons but may have different mass number.

Nuclides of a particular element that differ in the number of neutrons and their mass number are called isotopes.

Isotopes of given element have the same number of protons or atomic number but have different number of neutrons in each atom.

Atomic number (Z) = number of protons present in the nucleus of an atom of the element = number of electrons present in a neutral atom of the element

Mass number (A) = number of protons + number of neutrons

Answer to Problem 1P

Solution:

C2450r The number of electrons is 24, number of protons is 24 and number of neutrons is 26

C2452r The number of electrons is 24, number of protons is 24 and number of neutrons is 28

C2453r The number of electrons is 24, number of protons is 24 and number of neutrons is 29

C2454r The number of electrons is 24, number of protons is 24 and number of neutrons is 26

Explanation of Solution

For isotope C2450r

Atomic number = number of electrons = number of protons = 24

The number of neutrons = mass number – number of protons = 50-24 = 26

For isotope C2452r

Atomic number = number of electrons = number of protons = 24

The number of neutrons = mass number – number of protons = 52-24 = 28

For isotope C2453r

Atomic number = number of electrons = number of protons = 24

The number of neutrons = mass number – number of protons = 53-24 = 29

For isotope C2454r

Atomic number = number of electrons = number of protons = 24

The number of neutrons = mass number – number of protons = 54-24 = 30

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Chapter 1 Solutions

Inorganic Chemistry

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