
Concept explainers
The random number generator to simulate 20 samples of 10 coins tosses and explains the comparison of simulations.

Answer to Problem 1DHGP
Solution: The 20 simulation of 10 coin tosses is obtained as:
H | H | T | T | T | H | H | H | H | H | T | T | H | H | T | T | H | T | H | T |
H | H | T | H | H | T | H | H | T | T | T | T | T | T | T | T | H | H | T | T |
T | H | H | T | T | H | T | T | H | T | H | T | T | T | H | H | T | H | H | T |
H | H | H | T | T | T | H | T | T | T | T | T | H | T | H | T | T | T | T | T |
H | H | T | T | T | H | H | T | H | H | T | H | H | H | T | T | T | H | H | T |
H | H | H | H | H | T | H | H | T | T | T | H | H | T | T | H | T | T | H | T |
H | T | H | T | H | H | T | T | T | H | H | T | H | T | H | H | T | T | T | T |
T | H | H | T | H | H | T | T | H | H | H | H | T | T | H | H | T | H | H | H |
H | T | H | H | H | H | H | H | T | H | H | T | T | T | T | H | T | T | T | H |
T | T | T | T | T | T | T | T | H | H | T | T | H | H | T | T | H | H | H | H |
It does not seem that any string of 10 heads. There are 4 strings of four heads. Only 4 strings have half heads and half tails.
Explanation of Solution
There are several ways to assign numbers to the two outcomes because coin is fair. Suppose, quarter is fair ‘0’ digit is assigned to the outcome heads (H) and ‘1’ digit to the outcome tails (T).
To simulate the outcomes of tossing a coin 10 times by using Excel as follows:
Select the cell that to use to generate the random number between 0 and 1 in Excel. Select cell A1.
Enter the formula =RANDBETWEEN(0,1) in cell A1.
This formula is then copied down from A1 to A10.
Copied these 10 cells in column B to T to obtain 20 simulations.
The 20 simulation of 10 coin tosses is obtained as:
0 | 0 | 1 | 1 | 1 | 0 | 0 | 0 | 0 | 0 | 1 | 1 | 0 | 0 | 1 | 1 | 0 | 1 | 0 | 1 |
0 | 0 | 1 | 0 | 0 | 1 | 0 | 0 | 1 | 1 | 1 | 1 | 1 | 1 | 1 | 1 | 0 | 0 | 1 | 1 |
1 | 0 | 0 | 1 | 1 | 0 | 1 | 1 | 0 | 1 | 0 | 1 | 1 | 1 | 0 | 0 | 1 | 0 | 0 | 1 |
0 | 0 | 0 | 1 | 1 | 1 | 0 | 1 | 1 | 1 | 1 | 1 | 0 | 1 | 0 | 1 | 1 | 1 | 1 | 1 |
0 | 0 | 1 | 1 | 1 | 0 | 0 | 1 | 0 | 0 | 1 | 0 | 0 | 0 | 1 | 1 | 1 | 0 | 0 | 1 |
0 | 0 | 0 | 0 | 0 | 1 | 0 | 0 | 1 | 1 | 1 | 0 | 0 | 1 | 1 | 0 | 1 | 1 | 0 | 1 |
0 | 1 | 0 | 1 | 0 | 0 | 1 | 1 | 1 | 0 | 0 | 1 | 0 | 1 | 0 | 0 | 1 | 1 | 1 | 1 |
1 | 0 | 0 | 1 | 0 | 0 | 1 | 1 | 0 | 0 | 0 | 0 | 1 | 1 | 0 | 0 | 1 | 0 | 0 | 0 |
0 | 1 | 0 | 0 | 0 | 0 | 0 | 0 | 1 | 0 | 0 | 1 | 1 | 1 | 1 | 0 | 1 | 1 | 1 | 0 |
1 | 1 | 1 | 1 | 1 | 1 | 1 | 1 | 0 | 0 | 1 | 1 | 0 | 0 | 1 | 1 | 0 | 0 | 0 | 0 |
The outcomes (H and T) associated with 20 samples as:
H | H | T | T | T | H | H | H | H | H | T | T | H | H | T | T | H | T | H | T |
H | H | T | H | H | T | H | H | T | T | T | T | T | T | T | T | H | H | T | T |
T | H | H | T | T | H | T | T | H | T | H | T | T | T | H | H | T | H | H | T |
H | H | H | T | T | T | H | T | T | T | T | T | H | T | H | T | T | T | T | T |
H | H | T | T | T | H | H | T | H | H | T | H | H | H | T | T | T | H | H | T |
H | H | H | H | H | T | H | H | T | T | T | H | H | T | T | H | T | T | H | T |
H | T | H | T | H | H | T | T | T | H | H | T | H | T | H | H | T | T | T | T |
T | H | H | T | H | H | T | T | H | H | H | H | T | T | H | H | T | H | H | H |
H | T | H | H | H | H | H | H | T | H | H | T | T | T | T | H | T | T | T | H |
T | T | T | T | T | T | T | T | H | H | T | T | H | H | T | T | H | H | H | H |
The above random sample is obtained with replacement. There is no any string (sample) of 10 heads. There are 4 samples of 4 heads. These four samples are
There are 4 samples of 5 heads and 5 tails. These four samples are
Want to see more full solutions like this?
Chapter 1 Solutions
Student Solutions Manual for Brase/Brase's Understanding Basic Statistics, 7th
- This is the information about the actors who won the Best Actor Oscar: Best actors 44 41 62 52 41 34 34 52 41 37 38 34 32 40 43 56 41 39 49 57 35 30 39 41 44 41 38 42 52 51 49 35 47 31 47 37 57 42 45 42 44 62 43 42 48 49 56 38 60 30 40 42 36 76 39 53 45 36 62 43 51 32 42 54 52 37 38 32 45 60 46 40 36 47 29 43 a. What is the variable? What type? b. Construct an interval-frequency table, with columns containing: class mark, absolute frequency, relative frequency, cumulative frequency, cumulative relative frequency, and percentage frequency.arrow_forwardans c plsarrow_forwardCritically analyze the following graph and, based on statistical information, indicate the type of error it presents IN NO MORE THAN 3 LINES SCOTCEN POLL OF POLLS SHOULD SCOTLAND BE INDEPENDENT? NO 52% YES 58% LIVE CAW NAS & 28.30 HAS KILLED MORE THAN 2,600 IN WEST AFRICA, WORLD HEALTH ORG. BROOKEBCNNarrow_forward
- Critically analyze the following graph and, based on statistical information, indicate the type of error it presents IN NO MORE THAN 3 LINES PRESIDENTIAL PREFERENCES RODOLFO CARTER 3% (+2pts) EVELYN MATTHEI 22% (+6pts) With the exception of President Boric, could you tell me who you would like to be the next president of Chile? CAMILA VALLEJO 4% (+2pts) JOSÉ ANTONIO KAST 19% (+5pts) MICHELLE BACHELET 6% (+1pts)arrow_forwardCritically analyze the following graph and, based on statistical information, indicate the type of error it presents IN NO MORE THAN 3 LINES 13% APPROVE 4% DOESN'T KNOW DOESN'T RESPOND 5% NEITHER APPROVES NOR DISAPPROVES 78% DISAPPROVES SURVEY PRESIDENTIAL APPROVAL DROPS TO 13%arrow_forwardPlease help with this following question I'm not too sure if question (a) and (b) are correct and not sure how to calculate (c) The csv data is below "","New","Current" "1","67",66 "2","77",73 "3","76",73 "4","76",76 "5","77",79 "6","84",76 "7","71",78 "8","84",72 "9","73",76 "10","71",73 "11","72",77 "12","70",72 "13","75",72 "14","84",71 "15","77",73 "16","65",72 "17","69",73 "18","71",73 "19","79",71 "20","75",78 "21","76",69 "22","73",74 "23","76",71 "24","64",74 "25","81",78 "26","79",76 "27","70",77 "28","79",71 "29","84",73 "30","79",69 "31","69",72 "32","81",76 "33","77",70 "34","77",71 "35","71",69 "36","67",72 "37","70",76 "38","77",73 "39","82",73 "40","72",73arrow_forward
- Please help me answer the following question(c) A previous study found that 15% of nurses reported participating in mental health support programs.From the 96% found in (b) , can you conclude that proportion of nurses reported participating in mental health support programs p(current), has changed from the previous study?(Yes/No) because the confidence interval in (b) (captures/does not capture) 15%.(d) Refer to your answer in (b) : The Alberta Nurses Association expects that not more than 23 % of nurses will participate in the survey on mental health support programs. Given the result in part (b) can we conclude that this expectation is reasonable?(Yes/No) because the (upper bound/lower bound) of the 96% confidence interval is (less than/not less than/greater than) 23%. The Alberta Nursing Association conducts an annual survey to estimate the proportion of nurses who participate in mental health support programs. The most recent application of this survey involved a random sample of…arrow_forwardPlease help me solve this questionThis is what was in the csv file:"","Diabetic","Heart Disease""1",32644,30646"2",789,1670"3",12802,36274"4",2177,5011"5",1910,3300"6",3320,4256"7",61425,39053"8",19768,28635"9",19502,39546"10",5642,12182"11",107864,152098"12",29918,60433"13",2397,3550"14",41559,34705"15",49169,57948"16",72853,83100"17",2155,2873"18",140220,134517"19",28181,26212"20",18850,38637"21",69564,68582"22",13897,12613"23",6868,9138"24",9735,4767"25",12102,13447"26",36571,50010"27",44665,55141"28",26620,33970"29",25525,29766"30",14167,20206Q(b) From this, the relationship between these two variables is (non-existent/positive/negative) . I can categorize this relationship as being (strong/weak/moderate).Q(c) Drop down is (+/-)Q(d) Drop downs in order are __% of the (average/median/variation/standard deviation) in the (the number of people diagnosed with heart disease/the number of people diagnosed with diabetes)−variable can be explained by its (linear relationship/relationship)…arrow_forwardPlease help me answer the following question The drop down for question (e, f, and g) is (YES/NO) Based on the P-value above, the assumption of equal variances among the four machines (Is Met/Is Not Met) Based on the data, the average fill for machine 3 is (statistically lower than/statistically higher than/the same as/not statistically different than/statistically different than/Hard to say then when comparing to/Refuse to say when comparing to) machine 1.arrow_forward
- Business Discussarrow_forward1 for all k, and set o (ii) Let X1, X2, that P(Xkb) = x > 0. Xn be independent random variables with mean 0, suppose = and Var Xk. Then, for 0x) ≤2 exp-tx+121 Στ k=1arrow_forwardLemma 1.1 Suppose that g is a non-negative, non-decreasing function such that E g(X) 0. Then, E g(|X|) P(|X|> x) ≤ g(x)arrow_forward
- Algebra & Trigonometry with Analytic GeometryAlgebraISBN:9781133382119Author:SwokowskiPublisher:CengageHolt Mcdougal Larson Pre-algebra: Student Edition...AlgebraISBN:9780547587776Author:HOLT MCDOUGALPublisher:HOLT MCDOUGALCollege Algebra (MindTap Course List)AlgebraISBN:9781305652231Author:R. David Gustafson, Jeff HughesPublisher:Cengage Learning
- College AlgebraAlgebraISBN:9781305115545Author:James Stewart, Lothar Redlin, Saleem WatsonPublisher:Cengage LearningAlgebra and Trigonometry (MindTap Course List)AlgebraISBN:9781305071742Author:James Stewart, Lothar Redlin, Saleem WatsonPublisher:Cengage Learning




