ATKINS' PHYSICAL CHEMISTRY
11th Edition
ISBN: 9780190053956
Author: ATKINS
Publisher: Oxford University Press
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Chapter 1, Problem 1C.1DQ
Interpretation Introduction
Interpretation: The variation in compression factor with pressure and temperature has to be explained. The information revealed by compression factor about intermolecular interactions in real gases has to be stated.
Concept introduction: The compression factor is defined as the ratio of molar volume of a gas to the molar volume of a perfect gas. This is represented by the formula given below as,
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6. The formula of the product of the addition of HCN to benzaldehydeis ___.A. C8H7NO; B. C8H6NO; C. C14H11NO; D. C9H9NO; E. C9H8NO
Please include all steps. Thank you!
Predicting the qualitative acid-base properties of salts
Consider the following data on some weak acids and weak bases:
base
acid
K
K
a
name
formula
name
formula
nitrous acid
HNO2 4.5×10
hydroxylamine HONH2 1.1 × 10
8
hypochlorous acid
HCIO
8
3.0 × 10
methylamine CH3NH2 | 4.4 × 10¯
4
Use this data to rank the following solutions in order of increasing pH. In other words, select a '1' next to the solution that will have the lowest pH, a '2' next to
the solution that will have the next lowest pH, and so on.
0.1 M KCIO
solution
PH
choose one
0.1 M NaNO2
0.1 M CH3NH3Br
0.1 M NaBr
choose one ✓
choose one v
✓ choose one
1 (lowest)
☑
2
3
4 (highest)
For this Orgo problem, don't worry about question 3 below it. Please explain your thought process, all your steps, and also include how you would tackle a similar problem. Thank you!
Chapter 1 Solutions
ATKINS' PHYSICAL CHEMISTRY
Ch. 1 - Prob. 1A.1STCh. 1 - Prob. 1A.2STCh. 1 - Prob. 1B.1STCh. 1 - Prob. 1C.1STCh. 1 - Prob. 1A.1DQCh. 1 - Prob. 1A.1AECh. 1 - Prob. 1A.1BECh. 1 - Prob. 1A.2AECh. 1 - Prob. 1A.2BECh. 1 - Prob. 1A.3AE
Ch. 1 - Prob. 1A.3BECh. 1 - Prob. 1A.4AECh. 1 - Prob. 1A.4BECh. 1 - Prob. 1A.5AECh. 1 - Prob. 1A.5BECh. 1 - Prob. 1A.6AECh. 1 - Prob. 1A.6BECh. 1 - Prob. 1A.7AECh. 1 - Prob. 1A.7BECh. 1 - Prob. 1A.8AECh. 1 - Prob. 1A.8BECh. 1 - Prob. 1A.9AECh. 1 - Prob. 1A.9BECh. 1 - Prob. 1A.10AECh. 1 - Prob. 1A.10BECh. 1 - Prob. 1A.11AECh. 1 - Prob. 1A.11BECh. 1 - Prob. 1A.1PCh. 1 - Prob. 1A.2PCh. 1 - Prob. 1A.3PCh. 1 - Prob. 1A.4PCh. 1 - Prob. 1A.5PCh. 1 - Prob. 1A.6PCh. 1 - Prob. 1A.7PCh. 1 - Prob. 1A.8PCh. 1 - Prob. 1A.9PCh. 1 - Prob. 1A.10PCh. 1 - Prob. 1A.11PCh. 1 - Prob. 1A.12PCh. 1 - Prob. 1A.13PCh. 1 - Prob. 1A.14PCh. 1 - Prob. 1B.1DQCh. 1 - Prob. 1B.2DQCh. 1 - Prob. 1B.3DQCh. 1 - Prob. 1B.1AECh. 1 - Prob. 1B.1BECh. 1 - Prob. 1B.2AECh. 1 - Prob. 1B.2BECh. 1 - Prob. 1B.3AECh. 1 - Prob. 1B.3BECh. 1 - Prob. 1B.4AECh. 1 - Prob. 1B.4BECh. 1 - Prob. 1B.5AECh. 1 - Prob. 1B.5BECh. 1 - Prob. 1B.6AECh. 1 - Prob. 1B.6BECh. 1 - Prob. 1B.7AECh. 1 - Prob. 1B.7BECh. 1 - Prob. 1B.8AECh. 1 - Prob. 1B.8BECh. 1 - Prob. 1B.9AECh. 1 - Prob. 1B.9BECh. 1 - Prob. 1B.1PCh. 1 - Prob. 1B.2PCh. 1 - Prob. 1B.3PCh. 1 - Prob. 1B.4PCh. 1 - Prob. 1B.5PCh. 1 - Prob. 1B.6PCh. 1 - Prob. 1B.7PCh. 1 - Prob. 1B.8PCh. 1 - Prob. 1B.9PCh. 1 - Prob. 1B.10PCh. 1 - Prob. 1B.11PCh. 1 - Prob. 1C.1DQCh. 1 - Prob. 1C.2DQCh. 1 - Prob. 1C.3DQCh. 1 - Prob. 1C.4DQCh. 1 - Prob. 1C.1AECh. 1 - Prob. 1C.1BECh. 1 - Prob. 1C.2AECh. 1 - Prob. 1C.2BECh. 1 - Prob. 1C.3AECh. 1 - Prob. 1C.3BECh. 1 - Prob. 1C.4AECh. 1 - Prob. 1C.4BECh. 1 - Prob. 1C.5AECh. 1 - Prob. 1C.5BECh. 1 - Prob. 1C.6AECh. 1 - Prob. 1C.6BECh. 1 - Prob. 1C.7AECh. 1 - Prob. 1C.7BECh. 1 - Prob. 1C.8AECh. 1 - Prob. 1C.8BECh. 1 - Prob. 1C.9AECh. 1 - Prob. 1C.9BECh. 1 - Prob. 1C.1PCh. 1 - Prob. 1C.2PCh. 1 - Prob. 1C.3PCh. 1 - Prob. 1C.4PCh. 1 - Prob. 1C.5PCh. 1 - Prob. 1C.6PCh. 1 - Prob. 1C.7PCh. 1 - Prob. 1C.8PCh. 1 - Prob. 1C.9PCh. 1 - Prob. 1C.10PCh. 1 - Prob. 1C.11PCh. 1 - Prob. 1C.12PCh. 1 - Prob. 1C.13PCh. 1 - Prob. 1C.14PCh. 1 - Prob. 1C.15PCh. 1 - Prob. 1C.16PCh. 1 - Prob. 1C.17PCh. 1 - Prob. 1C.18PCh. 1 - Prob. 1C.19PCh. 1 - Prob. 1C.20PCh. 1 - Prob. 1C.22PCh. 1 - Prob. 1C.23PCh. 1 - Prob. 1C.24PCh. 1 - Prob. 1.1IACh. 1 - Prob. 1.2IACh. 1 - Prob. 1.3IA
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- Using the general properties of equilibrium constants At a certain temperature, the equilibrium constant K for the following reaction is 0.84: H2(g) + 2(g) 2 HI(g) = Use this information to complete the following table. Suppose a 34. L reaction vessel is filled with 0.79 mol of HI. What can you say about the composition of the mixture in the vessel at equilibrium? There will be very little H2 and 12. ☐ x10 There will be very little HI. Neither of the above is true. What is the equilibrium constant for the following reaction? Be sure your answer has the correct number of significant digits. 2 HI(g) H₂(9)+12(9) K = What is the equilibrium constant for the following reaction? Be sure your answer has the correct number of significant digits. 2 H2(g)+212(9) 4 HI(g) K = ☐ ☑arrow_forwardPredicting the qualitative acid-base properties of salts Consider the following data on some weak acids and weak bases: base acid Κα Kb name formula name formula hydrocyanic acid - 10 HCN 4.9 × 10 pyridine C₂H₂N 1.7 × 10 9 acetic acid HCH3CO2 1.8 × 10 5 hydroxylamine HONH2 1.1 × 10¯ 8 Use this data to rank the following solutions in order of increasing pH. In other words, select a '1' next to the solution that will have the lowest pH, a '2' next to the solution that will have the next lowest pH, and so on. 0.1 M KCN solution pH choose one ✓ 0.1 M C5H5NHCI choose one ✓ 0.1 M NaCH3CO2 choose one ✓ 0.1 M HONH3Br ✓ choose one 1 (lowest) 2 3 4 (highest)arrow_forwardFor this question please solve the first question. Please explain your thought process, the steps you took, and how you would tackle a similar problem. Thank you for your help!arrow_forward
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