Chapter 1, Problem 1.98QP

(a)

Interpretation Introduction

Interpretation:

Given $\text{5}\text{.0}\text{qt}$ has to be converted to gallons ($\text{gal}$).

Explanation of Solution

Given, $\text{5}\text{.0}\text{qt}$

  $\begin{array}{l}\text{1}\text{gal}\text{=}\text{4}\text{qt}\\ \text{=}\text{5}\text{.0}\text{qt}\text{×}\frac{\text{1}\text{gal}}{\text{4}\text{qt}}\\ \text{=}\text{1}\text{.25}\text{gal}\end{array}$

(b)

Interpretation Introduction

Interpretation:

Given $\text{5}\text{.0}\text{qt}$ has to be converted to pints ($\text{pt}$).

Explanation of Solution

Given, $\text{5}\text{.0}\text{qt}$

  $\begin{array}{l}\text{1}\text{qt}\text{=}\text{2}\text{pt}\\ \text{=}\text{5}\text{.0}\text{qt}\text{×}\frac{\text{2}\text{pt}}{\text{1}\text{qt}}\\ \text{=}\text{10}\text{.0}\text{pt}\end{array}$

(c)

Interpretation Introduction

Interpretation:

Given $\text{5}\text{.0}\text{qt}$ has to be converted to liters ($\text{L}$).

Explanation of Solution

Given, $\text{5}\text{.0}\text{qt}$

  $\begin{array}{l}\text{1}\text{qt}\text{=}\text{0}\text{.946}\text{L}\\ \text{=}\text{5}\text{.0}\text{qt}\text{×}\frac{\text{0}\text{.946}\text{L}}{\text{1}\text{qt}}\\ \text{=}\text{4}\text{.73}\text{L}\end{array}$

(d)

Interpretation Introduction

Interpretation:

Given $\text{5}\text{.0}\text{qt}$ has to be converted to milliliters ($\text{mL}$).

Explanation of Solution

Given, $\text{5}\text{.0}\text{qt}$

  $\begin{array}{l}\text{1}\text{qt}\text{=}\text{0}\text{.946}\text{L}\\ \text{=}\text{5}\text{.0}\text{qt}\text{×}\frac{\text{0}\text{.946}\text{L}}{\text{1}\text{qt}}\\ \text{=}\text{4}\text{.73}\text{L}\\ \text{1}\text{L}\text{=}{\text{10}}^{\text{3}}\text{mL}\\ \text{=}\text{4}\text{.73}\text{L}\text{×}\frac{{\text{10}}^{\text{3}}\text{mL}}{\text{1}\text{L}}\\ \text{=}\text{4730}\text{mL}\end{array}$

(e)

Interpretation Introduction

Interpretation:

Given $\text{5}\text{.0}\text{qt}$ has to be converted to microliters ($\text{μL}$).

Explanation of Solution

Given, $\text{5}\text{.0}\text{qt}$

  $\begin{array}{l}\text{1}\text{qt}\text{=}\text{0}\text{.946}\text{L}\\ \text{=}\text{5}\text{.0}\text{qt}\text{×}\frac{\text{0}\text{.946}\text{L}}{\text{1}\text{qt}}\\ \text{=}\text{4}\text{.73}\text{L}\\ \text{1}\text{L}\text{=}{\text{10}}^{\text{6}}\text{μL}\\ \text{=}\text{4}\text{.73}\text{L}\text{×}\frac{{\text{10}}^{\text{6}}\text{μL}}{\text{1}\text{L}}\\ \text{=}\text{4730000}\text{μL}\end{array}$