Chapter 1, Problem 1.90ASP

Interpretation Introduction

Interpretation:

The volume ($mL$) should be calculated given required values of ethanol.

Concept Introduction:

Density: It is the mass of an object divided by its volume, moreover density often has unit of grams per cubic centimetre (c/gm³).

For example a gram is mass and cubic (cm) is a volume as 1 millilitre.

The density formula has $Density=\frac{Mass(g)}{Volume(mLorc{m}^3)}$

Specific gravity: The specific gravity of a substance is a simply the density of the substance divided by water at the same temperature. The specific gravity formula has given below.

$Specificgravity=\frac{Densityofsubs\tan ce(g/mL)}{Densityofwateratthesametemp.(g/mL)}$