
Concept explainers
a.
Compute the differences of the sales between October 2015 and October 2014.
List the manufacturers for whom, the sales in 2015 increased as compared to 2014.
List the manufacturers for whom, the sales in 2015 decreased as compared to 2014.
a.

Answer to Problem 17CE
The differences of the sales between October 2015 and October 2014 are as follows:
Manufacturer | Through October 2015 | Through October 2014 | Difference |
General Motors Corp. | 2,562,840 | 2,434,707 | 128,133 |
Ford Motor Company | 2,178,587 | 2,065,612 | 112,975 |
Toyota Motor Sales USA Inc. | 2,071,446 | 1,975,368 | 96,078 |
Chrysler | 1,814,268 | 1,687,313 | 12,6955 |
American Honda Motor Co Inc. | 1,320,217 | 1,281,777 | 38,440 |
Nissan North America Inc. | 1,238,535 | 1,166,389 | 72,146 |
Hyundai Motor America | 638,195 | 607,539 | 30,656 |
Kia Motors America Inc. | 526,024 | 489,711 | 36,313 |
Subaru of America Inc. | 480,331 | 418,497 | 61,834 |
Volkswagen of America Inc. | 294,602 | 301,187 | –6,585 |
Mercedes-Benz | 301,915 | 281,728 | 20,187 |
BMW of North America Inc. | 279,395 | 267,193 | 12,202 |
Mazda Motor of America Inc. | 267,158 | 259,751 | 7,407 |
Audi of America Inc. | 165,103 | 146,133 | 18,970 |
Mitsubishi Motors N A, Inc. | 80,683 | 64,564 | 16,119 |
Volvo | 53,803 | 47,823 | 5,980 |
Land Rover ** | 55,602 | 42,067 | 13,535 |
Fiat | 35,576 | 39,226 | –3,650 |
Porsche Cars NA Inc. | 43,370 | 39,033 | 4,337 |
Jaguar * | 12,204 | 12,837 | –633 |
Tesla * | 17,350 | 15,500 | 1,850 |
Mini * | 49,061 | 44,488 | 4,573 |
Maserati * | 9,544 | 10,327 | –783 |
Smart * | 6,153 | 8,665 | –2,512 |
Bentley * | 1,917 | 2,268 | –351 |
Ferrari * | 1,903 | 1,739 | 164 |
Rolls Royce * | 701 | 682 | 19 |
Lamborghini * | 866 | 494 | 372 |
The manufacturers for whom, the sales in 2015 increased as compared to 2014 are as follows:
Manufacturer | Through October 2015 | Through October 2014 | Difference |
General Motors Corp. | 2,562,840 | 2,434,707 | 128,133 |
Ford Motor Company | 2,178,587 | 2,065,612 | 112,975 |
Toyota Motor Sales USA Inc. | 2,071,446 | 1,975,368 | 96,078 |
Chrysler | 1,814,268 | 1,687,313 | 12,6955 |
American Honda Motor Co Inc. | 1,320,217 | 1,281,777 | 38,440 |
Nissan North America Inc. | 1,238,535 | 1,166,389 | 72,146 |
Hyundai Motor America | 638,195 | 607,539 | 30,656 |
Kia Motors America Inc. | 526,024 | 489,711 | 36,313 |
Subaru of America Inc. | 480,331 | 418,497 | 61,834 |
Mercedes-Benz | 301,915 | 281,728 | 20,187 |
BMW of North America Inc. | 279,395 | 267,193 | 12,202 |
Mazda Motor of America Inc. | 267,158 | 259,751 | 7,407 |
Audi of America Inc. | 165,103 | 146,133 | 18,970 |
Mitsubishi Motors N A, Inc. | 80,683 | 64,564 | 16,119 |
Volvo | 53,803 | 47,823 | 5,980 |
Land Rover ** | 55,602 | 42,067 | 13,535 |
Porsche Cars NA Inc. | 43,370 | 39,033 | 4,337 |
Tesla * | 17,350 | 15,500 | 1,850 |
Mini * | 49,061 | 44,488 | 4,573 |
Ferrari * | 1,903 | 1,739 | 164 |
Rolls Royce * | 701 | 682 | 19 |
Lamborghini * | 866 | 494 | 372 |
The manufacturers for whom, the sales in 2015 decreased as compared to 2014 are as follows:
Manufacturer | Through October 2015 | Through October 2014 | Difference |
Volkswagen of America Inc. | 294,602 | 301,187 | –6,585 |
Fiat | 35,576 | 39,226 | –3,650 |
Jaguar * | 12,204 | 12,837 | –633 |
Maserati * | 9,544 | 10,327 | –783 |
Smart * | 6,153 | 8,665 | –2,512 |
Bentley * | 1,917 | 2,268 | –351 |
Explanation of Solution
Calculation:
The manufacturers for whom, data is missing for one or both the years are ignored.
Step-by-step procedure to calculate the differences of the sales between October 2015 and October 2014 using EXCEL is given below:
- Type the headings Manufacturer, Through October 2015, and Through October 2014, in cells A1, B1 and C1 respectively.
- Enter the manufacturers’ names in cells A2 to A29; the data for 2015 in cells B2 to B29; enter the data for 2014 in cells C2 to C29.
- Type the heading Difference in cell D1.
- Type the formula =B2-C2 in cell D2, and press Enter.
- Drag the cell till cell D29.
Thus, the differences are obtained using EXCEL.
The manufacturers with positive differences are the ones, for whom, the sales in 2015 increased as compared to 2014.
The manufacturers with negative differences are the ones, for whom, the sales in 2015 decreased as compared to 2014.
These can be identified from the list of differences obtained using software.
b.
Compute the percentage changes in sales between October 2015 and October 2014 and list them in an ascending order.
List the top 5 manufacturers in terms of percentage change.
List the bottom 5 manufacturers in terms of percentage change.
b.

Answer to Problem 17CE
The percentage changes in sales between October 2015 and October 2014 in an ascending order are as follows:
Manufacturer | Through October 2015 | Through October 2014 | Percentage change (%) |
Smart * | 6,153 | 8,665 | –28.99 |
Bentley * | 1,917 | 2,268 | –15.48 |
Fiat | 35,576 | 39,226 | –9.31 |
Maserati * | 9,544 | 10,327 | –7.58 |
Jaguar * | 12,204 | 12,837 | –4.93 |
Volkswagen of America Inc. | 2,94,602 | 3,01,187 | –2.19 |
Rolls Royce * | 701 | 682 | 2.79 |
Mazda Motor of America Inc. | 2,67,158 | 2,59,751 | 2.85 |
American Honda Motor Co Inc. | 1,320,217 | 1,281,777 | 3.00 |
BMW of North America Inc. | 279,395 | 267,193 | 4.57 |
Toyota Motor Sales USA Inc. | 2,071,446 | 1.975,368 | 4.86 |
Hyundai Motor America | 638,195 | 607,539 | 5.05 |
General Motors Corp. | 2,562,840 | 2,434,707 | 5.26 |
Ford Motor Company | 2,178,587 | 2,065,612 | 5.47 |
Nissan North America Inc. | 1,238,535 | 1,166,389 | 6.19 |
Mercedes-Benz | 301,915 | 281,728 | 7.17 |
Kia Motors America Inc. | 526,024 | 489,711 | 7.42 |
Chrysler | 1,814,268 | 1,687,313 | 7.52 |
Ferrari * | 1,903 | 1,739 | 9.43 |
Mini * | 49,061 | 44,488 | 10.28 |
Porsche Cars NA Inc. | 43,370 | 39,033 | 11.11 |
Tesla * | 17,350 | 15,500 | 11.94 |
Volvo | 53,803 | 47,823 | 12.50 |
Audi of America Inc. | 165,103 | 146,133 | 12.98 |
Subaru of America Inc. | 480,331 | 418,497 | 14.78 |
Mitsubishi Motors N A, Inc. | 80,683 | 64,564 | 24.97 |
Land Rover ** | 55,602 | 42,067 | 32.17 |
Lamborghini * | 866 | 494 | 75.30 |
The top 5 manufacturers in terms of percentage change are as follows:
Manufacturer | Through October 2015 | Through October 2014 | Percentage change (%) |
Lamborghini * | 866 | 494 | 75.30 |
Land Rover ** | 55,602 | 42,067 | 32.17 |
Mitsubishi Motors N A, Inc. | 80,683 | 64,564 | 24.97 |
Subaru of America Inc. | 480,331 | 418,497 | 14.78 |
Audi of America Inc. | 165,103 | 146,133 | 12.98 |
The bottom 5 manufacturers in terms of percentage change are as follows:
Manufacturer | Through October 2015 | Through October 2014 | Percentage change (%) |
Smart * | 6,153 | 8,665 | –28.99 |
Bentley * | 1,917 | 2,268 | –15.48 |
Fiat | 35,576 | 39,226 | –9.31 |
Maserati * | 9,544 | 10,327 | –7.58 |
Jaguar * | 12,204 | 12,837 | –4.93 |
Explanation of Solution
Calculation:
Step-by-step procedure to calculate the percentage changes of the sales between October 2015 and October 2014 and to sort the changes using EXCEL is given below:
- Type the heading Percentage change in cell E1.
- Type the formula =(D2/C2)*100 in cell E2, and press Enter.
- Drag the cell till cell E29.
- Select the values in cells E2 to E29 and choose Editing > Sort & Filter > Sort Smallest to Largest > Expand Selection > OK.
Thus, the sorted percentage changes are obtained using EXCEL.
The manufacturers with the top 5 and bottom 5 percentage changes can be identified from the list of percentage changes obtained using software.
c.
Draw a bar graph of the data in 2014 and 2015, sorted with respect to 2015 for the top 12 manufacturers.
Draw a bar graph of the percentage changes, sorted with respect to 2015 for the top 12 manufacturers.
c.

Answer to Problem 17CE
The bar graph of the data in 2014 and 2015, sorted with respect to 2015 for the top 12 manufacturers is as follows:
The bar graph of the percentage changes, sorted with respect to 2015 for the top 12 manufacturers is as follows:
Explanation of Solution
Calculation:
The data are already sorted with respect to 2015. The observations in rows 2 to 13, under columns A to E, correspond to the top 12 companies.
Step-by-step procedure to bar graph of the data in 2014 and 2015, sorted with respect to 2015 for the top 12 manufacturers using EXCEL is given below:
- Select cells A1 to C13.
- Choose Insert > Insert Column or Bar Chart > 2-D Column > Clustered Column.
Thus, the bar graph of the data in 2014 and 2015, sorted with respect to 2015 for the top 12 manufacturers is obtained using EXCEL.
Step-by-step procedure to bar graph of the percentage changes, sorted with respect to 2015 for the top 12 manufacturers using EXCEL is given below:
- Select cells A1 to A13, and E1 to E13.
- Choose Insert > Insert Column or Bar Chart > 2-D Column > Clustered Column.
Thus, the bar graph of the percentage changes, sorted with respect to 2015 for the top 12 manufacturers is obtained using EXCEL.
From the first bar graph, it can be observed that for most of the top 12 companies, the bars are higher for 2015 than for 2014, which indicates that the sales have increased from 2014 to 2015. However, for the 10th company in the list, the sales have slightly decreased in 2015, as compared to 2014, as suggested by the heights of the bars.
From the second bar graph, it can be observed that the sales have increased by 4% to 6%, from 2014 to 2015, for most of the top 12 companies. However, aa few notable differences are also observed. The sales for the 5th company on the list have increased only by about 3%. The sales for the 10th company on the list has, in fact, reduced by about 2%. The ales of the 9th company on the list has increased by approximately 15%, which is quite high as compared to the others.
Want to see more full solutions like this?
Chapter 1 Solutions
Gen Combo Ll Statistical Techniques In Business And Economics; Connect Ac
- A normal distribution has a mean of 50 and a standard deviation of 4. Solve the following three parts? 1. Compute the probability of a value between 44.0 and 55.0. (The question requires finding probability value between 44 and 55. Solve it in 3 steps. In the first step, use the above formula and x = 44, calculate probability value. In the second step repeat the first step with the only difference that x=55. In the third step, subtract the answer of the first part from the answer of the second part.) 2. Compute the probability of a value greater than 55.0. Use the same formula, x=55 and subtract the answer from 1. 3. Compute the probability of a value between 52.0 and 55.0. (The question requires finding probability value between 52 and 55. Solve it in 3 steps. In the first step, use the above formula and x = 52, calculate probability value. In the second step repeat the first step with the only difference that x=55. In the third step, subtract the answer of the first part from the…arrow_forwardIf a uniform distribution is defined over the interval from 6 to 10, then answer the followings: What is the mean of this uniform distribution? Show that the probability of any value between 6 and 10 is equal to 1.0 Find the probability of a value more than 7. Find the probability of a value between 7 and 9. The closing price of Schnur Sporting Goods Inc. common stock is uniformly distributed between $20 and $30 per share. What is the probability that the stock price will be: More than $27? Less than or equal to $24? The April rainfall in Flagstaff, Arizona, follows a uniform distribution between 0.5 and 3.00 inches. What is the mean amount of rainfall for the month? What is the probability of less than an inch of rain for the month? What is the probability of exactly 1.00 inch of rain? What is the probability of more than 1.50 inches of rain for the month? The best way to solve this problem is begin by a step by step creating a chart. Clearly mark the range, identifying the…arrow_forwardClient 1 Weight before diet (pounds) Weight after diet (pounds) 128 120 2 131 123 3 140 141 4 178 170 5 121 118 6 136 136 7 118 121 8 136 127arrow_forward
- Client 1 Weight before diet (pounds) Weight after diet (pounds) 128 120 2 131 123 3 140 141 4 178 170 5 121 118 6 136 136 7 118 121 8 136 127 a) Determine the mean change in patient weight from before to after the diet (after – before). What is the 95% confidence interval of this mean difference?arrow_forwardIn order to find probability, you can use this formula in Microsoft Excel: The best way to understand and solve these problems is by first drawing a bell curve and marking key points such as x, the mean, and the areas of interest. Once marked on the bell curve, figure out what calculations are needed to find the area of interest. =NORM.DIST(x, Mean, Standard Dev., TRUE). When the question mentions “greater than” you may have to subtract your answer from 1. When the question mentions “between (two values)”, you need to do separate calculation for both values and then subtract their results to get the answer. 1. Compute the probability of a value between 44.0 and 55.0. (The question requires finding probability value between 44 and 55. Solve it in 3 steps. In the first step, use the above formula and x = 44, calculate probability value. In the second step repeat the first step with the only difference that x=55. In the third step, subtract the answer of the first part from the…arrow_forwardIf a uniform distribution is defined over the interval from 6 to 10, then answer the followings: What is the mean of this uniform distribution? Show that the probability of any value between 6 and 10 is equal to 1.0 Find the probability of a value more than 7. Find the probability of a value between 7 and 9. The closing price of Schnur Sporting Goods Inc. common stock is uniformly distributed between $20 and $30 per share. What is the probability that the stock price will be: More than $27? Less than or equal to $24? The April rainfall in Flagstaff, Arizona, follows a uniform distribution between 0.5 and 3.00 inches. What is the mean amount of rainfall for the month? What is the probability of less than an inch of rain for the month? What is the probability of exactly 1.00 inch of rain? What is the probability of more than 1.50 inches of rain for the month? The best way to solve this problem is begin by creating a chart. Clearly mark the range, identifying the lower and upper…arrow_forward
- Problem 1: The mean hourly pay of an American Airlines flight attendant is normally distributed with a mean of 40 per hour and a standard deviation of 3.00 per hour. What is the probability that the hourly pay of a randomly selected flight attendant is: Between the mean and $45 per hour? More than $45 per hour? Less than $32 per hour? Problem 2: The mean of a normal probability distribution is 400 pounds. The standard deviation is 10 pounds. What is the area between 415 pounds and the mean of 400 pounds? What is the area between the mean and 395 pounds? What is the probability of randomly selecting a value less than 395 pounds? Problem 3: In New York State, the mean salary for high school teachers in 2022 was 81,410 with a standard deviation of 9,500. Only Alaska’s mean salary was higher. Assume New York’s state salaries follow a normal distribution. What percent of New York State high school teachers earn between 70,000 and 75,000? What percent of New York State high school…arrow_forwardPls help asaparrow_forwardSolve the following LP problem using the Extreme Point Theorem: Subject to: Maximize Z-6+4y 2+y≤8 2x + y ≤10 2,y20 Solve it using the graphical method. Guidelines for preparation for the teacher's questions: Understand the basics of Linear Programming (LP) 1. Know how to formulate an LP model. 2. Be able to identify decision variables, objective functions, and constraints. Be comfortable with graphical solutions 3. Know how to plot feasible regions and find extreme points. 4. Understand how constraints affect the solution space. Understand the Extreme Point Theorem 5. Know why solutions always occur at extreme points. 6. Be able to explain how optimization changes with different constraints. Think about real-world implications 7. Consider how removing or modifying constraints affects the solution. 8. Be prepared to explain why LP problems are used in business, economics, and operations research.arrow_forward
- ged the variance for group 1) Different groups of male stalk-eyed flies were raised on different diets: a high nutrient corn diet vs. a low nutrient cotton wool diet. Investigators wanted to see if diet quality influenced eye-stalk length. They obtained the following data: d Diet Sample Mean Eye-stalk Length Variance in Eye-stalk d size, n (mm) Length (mm²) Corn (group 1) 21 2.05 0.0558 Cotton (group 2) 24 1.54 0.0812 =205-1.54-05T a) Construct a 95% confidence interval for the difference in mean eye-stalk length between the two diets (e.g., use group 1 - group 2).arrow_forwardAn article in Business Week discussed the large spread between the federal funds rate and the average credit card rate. The table below is a frequency distribution of the credit card rate charged by the top 100 issuers. Credit Card Rates Credit Card Rate Frequency 18% -23% 19 17% -17.9% 16 16% -16.9% 31 15% -15.9% 26 14% -14.9% Copy Data 8 Step 1 of 2: Calculate the average credit card rate charged by the top 100 issuers based on the frequency distribution. Round your answer to two decimal places.arrow_forwardPlease could you check my answersarrow_forward
- Algebra: Structure And Method, Book 1AlgebraISBN:9780395977224Author:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. ColePublisher:McDougal LittellElementary AlgebraAlgebraISBN:9780998625713Author:Lynn Marecek, MaryAnne Anthony-SmithPublisher:OpenStax - Rice University
- Intermediate AlgebraAlgebraISBN:9781285195728Author:Jerome E. Kaufmann, Karen L. SchwittersPublisher:Cengage LearningAlgebra for College StudentsAlgebraISBN:9781285195780Author:Jerome E. Kaufmann, Karen L. SchwittersPublisher:Cengage LearningGlencoe Algebra 1, Student Edition, 9780079039897...AlgebraISBN:9780079039897Author:CarterPublisher:McGraw Hill





