Chapter 1, Problem 1.79AE

The molecule PYRIDINE, 6th electrons and is therefore aromatre and is Assigned the Following structure contering Since aromatk moleculoy undergo electrophilic anomatic substitution, Pyridine shodd undergo The Following reaction + HNO3 12504 a. write all of the possible Mononitration Products that could Result From this reaction 18. Bared upon the reaction mechanison determime which of these producty would be the major Product of the hegetion

a. Explain Why electron withdrawing groups tend to be meta-Directors. Your answer Should lyclude all apropriate. Resonance contributing Structures fo. Explain why -ll is an outho -tura drccton even though chlorine has a very High Electronegativity

9. Write Me product as well as the reaction Mechanism For each of the Following Vanctions +H₂504 4.50+ T C. +212 Fellz 237 b. Praw the potential energy Diagrams For each OF Mese Rauctions and account For any differences that appear in the two potential Puergy Diagrams which of here two reactions 19 Found to be Reversable, Rationalice your answer based upon the venation mechanisms and the potential energy diagrams.

9. Write Me product as well as the reaction Mechanism For each of the Following Veritious +H2504 4.50+ + 1/₂ Felly ◎+ 7 b. Praw he potential energy Diagrams For each OF Mese Ronctions and account for any differences that appeak in the two potential Puergy Diagrams

Draw the major product of this reaction. Ignore inorganic byproducts. Incorrect, 3 attempts remaining 1. excess Br2, NaOH 2. neutralizing workup Q

Given the electrode Pt | Ag | Ag+ (aq), describe it.

At 25°C, the reaction Zn2+ + 2e ⇄ Zn has a normal equilibrium potential versus the saturated calomel electrode of -1.0048 V. Determine the normal equilibrium potential of Zn versus the hydrogen electrode.Data: The calomel electrode potential is E° = 0.2420 V versus the normal hydrogen electrode.

Electrochemistry. State the difference between E and E0.

In an electrolytic cell, the positive pole is always assumed to be on the right side of the battery notation. Is that correct?