Chapter 1, Problem 1.73P

(a)

Interpretation Introduction

Interpretation:

The volume needed to fill the pool to an average depth of $4.8\text{ ft}$ is to be determined.

Concept introduction:

Volume is a physical quantity and its SI unit is cubic meter $\left({\text{m}}^{\text{3}}\right)$. The other units of the volume are liter, milliliter, cubic decimeter, microliter.

The formula to calculate the volume of a cuboid is,

  $\text{Volume}=\left(\text{length}\right)\left(\text{width}\right)\left(\text{depth}\right)$        (1)

The conversion factor to convert $\text{ft}$ to $\text{in}$ is as follows:

  $1\text{ft}=12\text{in}$

The conversion factor to convert $\text{in}$ to $\text{cm}$ is as follows:

  $1\text{in}=2.54\text{cm}$

(b)

Interpretation Introduction

Interpretation:

The mass of water in the pool is to be calculated.

Concept introduction:

Density is defined as mass per unit volume. Mass and volume are physical quantities and the units of mass and volume are fundamental units. Density is the ratio of mass to the volume. The unit of volume is derived from the units of mass and volume. The SI unit of density is ${\text{kg/m}}^{\text{3}}$. The formula to calculate density is,

  $\text{Density}=\frac{\text{Mass}}{\text{Volume}}$        (2)