Traffic and Highway Engineering
Traffic and Highway Engineering
5th Edition
ISBN: 9781305156241
Author: Garber, Nicholas J.
Publisher: Cengage Learning
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Chapter 1, Problem 16P
To determine

The required tax in cents per gallon.

Expert Solution & Answer
Check Mark

Answer to Problem 16P

The total required tax in cents gallon to make additional $60 million revenue is 0.6417cent/gallon.

Explanation of Solution

Given:

The population is 17 million.

Ownership is 1.1 cars per person.

Average rate is 12,000mi/year.

Average fuel economy is 24mi/gal.

Additional revenue is $60millionperyear.

Calculations:

Write the expression to calculate the total number of cars.

  Totalcars=Population×Averageownershipcars ....... (I)

Substitute 17,000,000 for population and 1.1 for average ownership cars in Equation (I).

  Totalcars=17,000,000×1.1=18,700,000

Write the expression to calculate the number of miles driven each year.

  Numberofmilesdriveneachyear=Totalcars×Averagemiles ....... (II)

Substitute 18,700,000 for total cars and 12,000mi/year for average miles driven in each year in Equation (II).

  Totalaveragedrivenbyallcars=18,700,000×12,000mi/year=224,400×106mi/year

Write the expression to calculate the number of gallons consumed each year.

  Gallongasoline=TotalaveragedrivenbyallcarsAveragefueleconomy ....... (III)

Substitute 224,400×106mi/year for total average driven by all cars and 24mi/gallon average fuel economy in Equation (III).

  Gallonsofgasoline=224,400× 106mi/year24mi/gallon=9350×106gallon/year

Write the expression to calculate the total tax per gallon of gasoline.

  Totaltax=additionalfundperyearGallonsofgasoline ....... (IV)

Substitute 9350×106gallons/year for gallons of gasoline and $60×106/year for additional fund per year in Equation (IV).

  Totaltax=$60× 10 6/year9350× 106gallons/year=$0.006417/gallon=($0.006417/gallon× 100cent $1)=0.6417cent/gallon

Conclusion:

Therefore, the total required tax in cents gallon to make additional $60 million revenue is 0.6417cent/gallon.

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