Stars and Galaxies (MindTap Course List)
10th Edition
ISBN: 9781337399944
Author: Michael A. Seeds
Publisher: Cengage Learning
expand_more
expand_more
format_list_bulleted
Concept explainers
Question
Chapter 1, Problem 14RQ
To determine
The importance of studying astronomy.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
I am trying to calculate the gravitational mass (in solar masses) I have the formula M= V^2 R / G (4.31 x 10^-6) The paperwork says our numbers should be big but I am coming up with .002 etc. What am I doing wrong?
Use Kepler's 3rd Law and the small angle approximation.
a) An object is located in the solar system at a distance from the Sun equal to 41 AU's . What is the objects orbital period?
b) An object seen in a telescope has an angular diameter equivalent to 41 (in units of arc seconds). What is its linear diameter if the object is 250 million km from you? Draw a labeled diagram of this situation.
I attempted to answer this question and I'm not sure what I am doing wrong. My formula says A.S. = 206265 (separation/distance from observer)
I know to convert to the same units, so I ended up with 80 Million Km being 8 x 10 ^ -6 LY
Could you please explain each step especially for the part that I got wrong for both A and B?
Chapter 1 Solutions
Stars and Galaxies (MindTap Course List)
Ch. 1 - Prob. 1RQCh. 1 - Prob. 2RQCh. 1 - Prob. 3RQCh. 1 - What is the difference between the Moon and a...Ch. 1 - Prob. 5RQCh. 1 - Why are light-years more convenient than miles,...Ch. 1 - Prob. 7RQCh. 1 - Prob. 8RQCh. 1 - Prob. 9RQCh. 1 - Prob. 10RQ
Ch. 1 - What are the largest known structures in the...Ch. 1 - Prob. 12RQCh. 1 - Prob. 13RQCh. 1 - Prob. 14RQCh. 1 - Prob. 15RQCh. 1 - Prob. 16RQCh. 1 - Prob. 1PCh. 1 - The equatorial diameter of the Moon is 3476...Ch. 1 - Prob. 3PCh. 1 - A typical galaxy is shown on the first page of the...Ch. 1 - Prob. 5PCh. 1 - Prob. 6PCh. 1 - Prob. 7PCh. 1 - Prob. 8PCh. 1 - If the speed of light is 3.0 105 km/s, how many...Ch. 1 - Prob. 10PCh. 1 - How long does it take light to cross the diameter...Ch. 1 - Prob. 12PCh. 1 - Prob. 13PCh. 1 - Prob. 1SPCh. 1 - Prob. 2SPCh. 1 - Prob. 3SPCh. 1 - Prob. 4SPCh. 1 - Prob. 1LLCh. 1 - Prob. 2LLCh. 1 - Prob. 3LLCh. 1 - Prob. 4LLCh. 1 - Prob. 5LLCh. 1 - Prob. 6LL
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- How Do We Know? Why is it important that a theory make testable predictions?arrow_forwardPerhaps the most fundamental problem in all of astronomy is the determination of distance to the various objects in the cosmos. Which of the following seems least reasonable regarding the various measurement techniques: Group of answer choices The Hubble Law relates the recessional speed of distant objects (measured with the Doppler Effect) to distance. Hubble law is most useful for determining the distance to nearby objects, while parallax is most useful for the more distant objects. We can determine the position of a star on the H-R diagram through spectral analysis and then figure out the distance by comparing absolute luminosity (from H-R diagram) to apparent brightness. The distance to nearby stars can be determined by measuring parallax. The distance to the planets in our solar can be determined by measuring the time for a radar signal to reach a planet, bounce off, and return.arrow_forwardPlease answer the following A) Suppose an object takes 1000 years to orbit the Sun. How many times farther from the Sun is it, when compared with Earth? B) Communications with the spacecraft Alpha using radio waves require 2000 years for the round trip (there and back). This implies that Alpha is how many light years away from Earth?arrow_forward
- Why write numbers in scientific notation Understanding physics will help you describe in great detail how the world works. However, the characteristics of the world span an enormous range of numbers. The mass of an electron is 0.000000000000000000000000000000911 kg (incredibly tiny!). The mass of the Sun is 1,989,000,000,000,000,000,000,000,000,000 kg (incredibly massive!). If you had to write, interpret, or use these numbers as written, you could very easily end up making a minor math error. Scientific notation was invented to easily express numbers that are too large or too small to be conveniently written in decimal form. The advantages of scientific notation are it 1) is compact, 2) helps articulate significant figures, and 3) works with numbers of any size. The traditional format for numbers written in scientific notation is m × 10 n is where m is a number between 1 and 10 and n is an integer (either positive or negative). For the examples above, the mass of an…arrow_forwardPart 3 1. The diameter of the Sun is 1,391,400 km. The diameter of the Moon is 3,474.8 km. Find the ratio, r= Dsa/Dsvan between the sizes. 2. From the point of view of an obs erver on Eanth (consider the Earth as a point-like object), during the eclipse, the Moon covers the Sun exactly. Sketch a picture to illustrate this fact. Use a nuler to get a straight line. Your drawing does not need to be in scale. 3. The Sun is 1 Astronomical Unit (AU) away from the Earth. Find the distance between the Earth and the Moon in AU's using the ratio of similar triangles. Show your work. DEM= AU. Convert this to kilometers. Use 1 AU = 149,600,000 km. DEM = km.arrow_forwardPlease solve this questionarrow_forward
- As we discuss in class, the radius of the Earth is approximately 6370 km. Theradius of the Sun, on the other hand, is approximately 700,000 km. The Sun is located,on average, one astronomical unit (1 au) from the Earth. Imagine that you stand near Mansueto Library, at the corner of 57th and Ellis.Mansueto’s dome is 35 feet (10.7 meters) high. Let’s imagine we put a model of theSun inside the dome, such that it just fits — that is, the model Sun’s diameter is 35 feet The nearest star to the Solar System outside of the Sun is Proxima Centauri,which is approximately 4.2 light years away. Given the scale model outlined above,how far would a model Proxima Centauri be placed from you? Give your answer inmiles and kmarrow_forwardOn Earth, the parallax angle measured for the star Procyon is 0.29 arcseconds. If you were to measure Procyon's parallax angle from Venus, what would the parallax angle be? (Note: Earth's orbital radius is larger than Venus's orbital radius.) A. more than 0.29 arcseconds O B. 0.29 arcseconds O C. less than 0.29 arcseconds D. zero arcseconds (no parallax)arrow_forward1. A distant galaxy has an apparent magnitude of 10 and is 4,000 kpc away. What is its absolute magnitude? (Round your answer to at least one decimal place.) The difference in absolute magnitude between two objects viewed from the same distance is related to their fluxes by the flux-magnitude relation. FA/FB= 2.51(MB − MA) 2. How does the absolute magnitude of this galaxy compare to the Milky Way (M = −21)?arrow_forward
- Explain what is meant by the distance ladder in astronomy. Describe briefly how each “rung” of the distance ladder is calibrated so that a reliable measure of distance can be obtained using each of the methods. State clearly the range of distances that can be measured by each method that makes up the distance ladder.arrow_forwardWhite Dwarf Size II. The white dwarf, Sirius B, contains 0.98 solar mass, and its density is about 2 x 106 g/cm?. Find the radius of the white dwarf in km to three significant digits. (Hint: Density = mass/volume, and the volume of a 4 sphere is Tr.) 3 km Compare your answer with the radii of the planets listed in the Table A-10. Which planet is this white dwarf is closely equal to in size? I Table A-10 I Properties of the Planets ORBITAL PROPERTIES Semimajor Axis (a) Orbital Period (P) Average Orbital Velocity (km/s) Orbital Inclination Planet (AU) (106 km) (v) (days) Eccentricity to Ecliptic Mercury 0.387 57.9 0.241 88.0 47.9 0.206 7.0° Venus 0.723 108 0.615 224.7 35.0 0.007 3.4° Earth 1.00 150 1.00 365.3 29.8 0.017 Mars 1.52 228 1.88 687.0 24.1 0.093 1.8° Jupiter 5.20 779 11.9 4332 13.1 0.049 1.30 Saturn 9.58 1433 29.5 10,759 9.7 0.056 2.5° 30,799 60,190 Uranus 19.23 2877 84.3 6.8 0.044 0.8° Neptune * By definition. 30.10 4503 164.8 5.4 0.011 1.8° PHYSICAL PROPERTIES (Earth = e)…arrow_forward(If relevant) A clearly labeled diagram (or diagrams) clearly pertaining to your analysis with a coordinate system and relevant labels. Final answer with appropriate units and significant figures. A 2-3 sentence reflection on your answer. Does it make sense? Why or why not? What are some implications? Do not just summarize your solution procedure.arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Foundations of Astronomy (MindTap Course List)PhysicsISBN:9781337399920Author:Michael A. Seeds, Dana BackmanPublisher:Cengage Learning
Stars and Galaxies (MindTap Course List)PhysicsISBN:9781337399944Author:Michael A. SeedsPublisher:Cengage Learning
Stars and GalaxiesPhysicsISBN:9781305120785Author:Michael A. Seeds, Dana BackmanPublisher:Cengage Learning
Foundations of Astronomy (MindTap Course List)
Physics
ISBN:9781337399920
Author:Michael A. Seeds, Dana Backman
Publisher:Cengage Learning
Stars and Galaxies (MindTap Course List)
Physics
ISBN:9781337399944
Author:Michael A. Seeds
Publisher:Cengage Learning
Stars and Galaxies
Physics
ISBN:9781305120785
Author:Michael A. Seeds, Dana Backman
Publisher:Cengage Learning