Management Information Systems: Managing The Digital Firm -- Student Value Edition (16th Edition)
16th Edition
ISBN: 9780135191927
Author: Kenneth Laudon, Jane Laudon
Publisher: PEARSON
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Chapter 1, Problem 14CSQ
Program Plan Intro
Deutsche Bank:
- Deutsche Bank AG was founded in 1870, it has 2,425 branches worldwide.
- Deutsche offers different type of financial products and services, such as retail and commercial banking, foreign exchange, and services for mergers and acquisitions and so on.
- Deutsche bank is one the world’s top financial companies and largest bank in Germany.
- Deutsche bank also plays a major role in German economy.
- Deutsche bank has a derivatives worth $64 trillion, the value of derivatives is the world’s largest portfolio.
- The contract is used to derive its value from the performance of underlying entity is referred as derivatives.
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Please run and debug the following program and answer the questions.
(OnlineGDB)
#include <stdio.h>int main(void) {int a;char *s;int v0 = 4, v1 = 5, v2 = 6, v3 = 1, v4 = 2;printf("Exercise 1:\n====================\n");switch(v0) {case 0: printf("Hello October\n"); break;case 1: printf("Go Kean!\n"); break;case 2: printf("Academic Building Center \n"); break;case 3: printf("UNION \n"); break;case 4: printf("Go ");case 5: printf("Kean! \n");default: printf("Have a great semester! \n"); break;}for(a=5; a<v1; a++) {printf("Kean");}printf("\n");if (v2 == 6) {s = "Go";}else {s = "Hello";}if(v3 != v4) {printf("%s Kean!\n",s);} else {printf("%s Computer Science!\n",s);}return 0;}
Assume the following codes are added between line 36 (}) and line 38 (return 0;) v0>0 ? ++v1, ++v2 : --v3; Please give the values of v0, v1, v2, v3, and v4 after this line and explain the reason. You can test the program to verify your answer if you like.
Chapter 1 Solutions
Management Information Systems: Managing The Digital Firm -- Student Value Edition (16th Edition)
Ch. 1.1 - Prob. 1.1CQCh. 1.1 - Prob. 1.2CQCh. 1.1 - Prob. 1.3CQCh. 1.1 - Prob. 1.4CQCh. 1.2 - Prob. 2.1CQCh. 1.2 - Prob. 2.2CQCh. 1.2 - Prob. 2.3CQCh. 1.2 - Prob. 2.4CQCh. 1 - Prob. 1IQCh. 1 - Prob. 2IQ
Ch. 1 - Prob. 3IQCh. 1 - Prob. 4IQCh. 1 - Prob. 5IQCh. 1 - Prob. 1RQCh. 1 - Prob. 2RQCh. 1 - Prob. 3RQCh. 1 - Prob. 4DQCh. 1 - Prob. 5DQCh. 1 - Prob. 6DQCh. 1 - Prob. 7HMPCh. 1 - Prob. 8HMPCh. 1 - Prob. 10HMPCh. 1 - Prob. 11CTPCh. 1 - Prob. 12CSQCh. 1 - Prob. 13CSQCh. 1 - Prob. 14CSQCh. 1 - Prob. 15CSQCh. 1 - Prob. 16MLMCh. 1 - Prob. 17MLM
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