BNDL: ACP ORGANIC CHEMISTRY:CH EM 231(W/ACCESS CARD)
BNDL: ACP ORGANIC CHEMISTRY:CH EM 231(W/ACCESS CARD)
8th Edition
ISBN: 9781337687539
Author: Brown/Iverson/Anslyn/ Foote
Publisher: CENGAGE C
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Chapter 1, Problem 1.47P

(a)

Interpretation Introduction

Interpretation:

The eight alcohols have to be written with the molecular formula of C5H12O has to be drawn.

Concept introduction:

Isomer: A molecule having same molecular formula with different chemical formula is called isomer.

Functional group: They are certain substitutes in the organic molecules which are determine the characteristic reactions taking place in it.

Alcohol:

The compound contains hydroxyl (OH) group, which is bonded with tetrahedral carbon atom is called as an alcohol.

Example is given below,

BNDL: ACP ORGANIC CHEMISTRY:CH EM 231(W/ACCESS CARD), Chapter 1, Problem 1.47P , additional homework tip  1

(b)

Interpretation Introduction

Interpretation:

Eight aldehydeswith the molecular formula of C6H12O has to be drawn

Concept introduction:

Isomer: A molecule having same molecular formula with different chemical formula is called isomer.

Functional group: They are certain substitutes in the organic molecules which are determine the characteristic reactions taking place in it.

Carbonyl group:

A carbon atom is double-bonded to an oxygen atom (C=O) is called as carbonyl group which is one of the functional group.

If the carbonyl carbon is attached with two alkyl or aryl group is called as ketone, if the carbonyl carbon is attached with one hydrogen atom and one alkyl or aryl group is called as aldehyde.

BNDL: ACP ORGANIC CHEMISTRY:CH EM 231(W/ACCESS CARD), Chapter 1, Problem 1.47P , additional homework tip  2

(c)

Interpretation Introduction

Interpretation:

Six ketones have to be written with the molecular formula of C6H12O has to be drawn

Concept introduction:

Isomer: A molecule having same molecular formula with different chemical formula is called isomer.

Functional group: They are certain substitutes in the organic molecules which are determine the characteristic reactions taking place in it.

Carbonyl group:

A carbon atom is double-bonded to an oxygen atom (C=O) is called as carbonyl group which is one of the functional group.

If the carbonyl carbon is attached with two alkyl or aryl group is called as ketone, if the carbonyl carbon is attached with one hydrogen atom and one alkyl or aryl group is called as aldehyde.

BNDL: ACP ORGANIC CHEMISTRY:CH EM 231(W/ACCESS CARD), Chapter 1, Problem 1.47P , additional homework tip  3

(d)

Interpretation Introduction

Interpretation:

Eight carboxylic acid have to be written with the molecular formula of C6H12O2 has to be drawn

Concept introduction:

Isomer: A molecule having same molecular formula with different chemical formula is called isomer.

Functional group: They are certain substitutes in the organic molecules which are determine the characteristic reactions taking place in it.

Carboxylic acid:

A carbon atom is double-bonded to an oxygen atom (C=O) is called as carbonyl group which is one of the functional group.

If the carbonyl carbon is attached with hydroxyl group is called as carboxylic acid.

BNDL: ACP ORGANIC CHEMISTRY:CH EM 231(W/ACCESS CARD), Chapter 1, Problem 1.47P , additional homework tip  4

(e)

Interpretation Introduction

Interpretation:

Nine carboxylic estershave to be written with the molecular formula of C5H10O2 has to be drawn

Concept introduction:

Isomer: A molecule having same molecular formula with different chemical formula is called isomer.

Functional group: They are certain substitutes in the organic molecules which are determine the characteristic reactions taking place in it.

Carboxylic ester:

A carbon atom is double-bonded to an oxygen atom (C=O) is called as carbonyl group which is one of the functional group. If the carbonyl carbon is attached with hydroxyl group is called as carboxylic acid. Hydrogen atom is replaced with carbon atom in carboxylic acid is called as ester.

BNDL: ACP ORGANIC CHEMISTRY:CH EM 231(W/ACCESS CARD), Chapter 1, Problem 1.47P , additional homework tip  5

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Chapter 1 Solutions

BNDL: ACP ORGANIC CHEMISTRY:CH EM 231(W/ACCESS CARD)

Ch. 1.3 - Prob. 1.11PCh. 1.3 - Prob. 1.12PCh. 1.4 - Predict all bond angles for these molecules. (a)...Ch. 1.5 - The geometry of carbon in diamond is tetrahedral,...Ch. 1.5 - Because of their spherical shape, C60 molecules...Ch. 1.5 - What best describes the CCC bond angles in C60? 1....Ch. 1.5 - Prob. 1.14PCh. 1.7 - Describe the bonding in these molecules in terms...Ch. 1.8 - Prob. 1.16PCh. 1.8 - Prob. 1.17PCh. 1.8 - Prob. 1.18PCh. 1.9 - Draw three contributing structures of the...Ch. 1.9 - What is the hybridization state of the circled...Ch. 1.9 - The molecule shown on the right in the example in...Ch. 1.9 - Prob. CQCh. 1.9 - The following structure is called imidazolium....Ch. 1 - Write the ground-state electron configuration for...Ch. 1 - Identify the atom that has each ground-state...Ch. 1 - Define valence shell and valence electron.Ch. 1 - How many electrons are in the valence shell of...Ch. 1 - Prob. 1.24PCh. 1 - Prob. 1.25PCh. 1 - Prob. 1.26PCh. 1 - Write Lewis structures for these compounds. Show...Ch. 1 - Write Lewis structures for these ions. Show all...Ch. 1 - Prob. 1.29PCh. 1 - Some of these structural formulas are incorrect...Ch. 1 - Following the rule that each atom of carbon,...Ch. 1 - Following are several Lewis structures showing all...Ch. 1 - Which statements are true about electronegativity?...Ch. 1 - Why does fluorine, the element in the upper right...Ch. 1 - Arrange the single covalent bonds within each set...Ch. 1 - Using the values of electronegativity given in...Ch. 1 - Prob. 1.37PCh. 1 - Use VSEPR to predict bond angles about each...Ch. 1 - Use VSEPR to predict bond angles about each atom...Ch. 1 - Use VSEPR to predict the geometry of these ions....Ch. 1 - Prob. 1.41PCh. 1 - Prob. 1.42PCh. 1 - What is the meaning of the term tertiary (3) when...Ch. 1 - What is the meaning of the term tertiary (3) when...Ch. 1 - Draw structural formulas for (a) The four primary...Ch. 1 - Draw structural formulas for the three tertiary...Ch. 1 - Prob. 1.47PCh. 1 - Identify the functional groups in each compound.Ch. 1 - Draw a three-dimensional representation for each...Ch. 1 - Tetrafluoroethylene, C2F4, is the starting...Ch. 1 - Which statements are true about resonance...Ch. 1 - Prob. 1.52PCh. 1 - Prob. 1.53PCh. 1 - Prob. 1.54PCh. 1 - Are the structures in each set valid contributing...Ch. 1 - State the orbital hybridization of each...Ch. 1 - Describe each highlighted bond in terms of the...Ch. 1 - Following is a structural formula of the...Ch. 1 - Draw a Lewis structure for methyl isocyanate,...Ch. 1 - What is the hybridization of the highlighted atoms...Ch. 1 - Using cartoon representations, draw a molecular...Ch. 1 - In what kind of orbitals do the lone-pair...Ch. 1 - Draw the delocalized molecular orbitals for the...Ch. 1 - Prob. 1.64APCh. 1 - Each compound contains both ions and covalent...Ch. 1 - Predict whether the carbon-metal bond in these...Ch. 1 - Prob. 1.67APCh. 1 - Phosphorus is immediately under nitrogen in the...Ch. 1 - Draw a Lewis structure for the azide ion, N3. (The...Ch. 1 - Cyanic acid, HOCN, and isocyanic acid, HNCO,...Ch. 1 - In Chapter 6, we study a group of organic cations...Ch. 1 - Many reactions involve a change in hybridization...Ch. 1 - Following is a structural formula of benzene,...Ch. 1 - Following are three contributing structures for...Ch. 1 - (a) Draw a Lewis structure for the ozone molecule,...Ch. 1 - The following two compounds are isomers; that is,...Ch. 1 - In future chapters, we will encounter...Ch. 1 - Prob. 1.78AP
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