Explanation Given: The mass of the person is 155 lb , the density of a human is 1.0 g/cm 3 , and the density of the fat is 0 .918 g/cm 3 . Since 1 lb = 453.59 g , convert the mass of the person into grams as follows: m = 155 lb ( 453.59 g 1 lb ) = 7.03 × 10 4 g Now, the volume of the person is calculated as follows: V = m d Here, m is the mass and d is the density. Substitute 7.03 × 10 4 g for m and 1.0 g/cm 3 for d : V = 7.03 × 10 4 g 1.0 g/cm 3 = 7.03 × 10 4 cm 3 Now, the height of the person is 4 ft . One feet is equal to 30.48 cm. Thus, h = 4 ft ( 30.48 cm 1 ft ) = 121.92 cm Now, the volume of the cylinder is as follows: V = π r 2 h Rearrange the equation: r 2 = V π h Substitute 121.92 cm for h and 7.03 × 10 4 cm 3 for V : r 2 = 7.03 × 10 4 cm 3 ( 3.14 ) ( 121.92 cm ) r = 7.03 × 10 4 cm 3 ( 3.14 ) ( 121.92 cm ) = 13.55 cm The person is modeled by a cylinder. Thus, the waist of the person is equal to the circumference of the circle. Thus, the waist is calculated as follows: w = 2 π r Substitute 13.55 cm for r : w 1 = 2 ( 3

Masteringchemistry with Pearson Etext -- Standalone Access Card -- For Chemistry

3rd Edition

ISBN: 9780321806383

Author: Nivaldo J. Tro

Publisher: PEARSON

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Chapter 1, Problem 139E

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Interpretation: The percentage increase in waist size is to be determined.

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Chapter 1, Problem 138E

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Masteringchemistry with Pearson Etext -- Standalone Access Card -- For Chemistry

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