General Chemistry
General Chemistry
7th Edition
ISBN: 9780073402758
Author: Chang, Raymond/ Goldsby
Publisher: McGraw-Hill College
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Chapter 1, Problem 1.38QP

(a)

Interpretation Introduction

Interpretation:

1.42lightyears has to be converted into miles.

Concept introduction:

Light year: The distance light can travel in one year it is approximately equal to 10 trillion kilometres or 6 trillion miles.

1mile=1609meterspeedoflight=3×108m/s

(a)

Expert Solution
Check Mark

Explanation of Solution

1.42lightyears can be converted into miles as follows,

1.42year×365days1year×24h1day×3600s1h×3.00×108m1s×1mile1609m=8.35×1012mile

Hence, 1.42lightyears can be converted into miles is 8.35×1012mile.

(b)

Interpretation Introduction

Interpretation:

32.4yd has to be converted into centimeters.

Concept introduction:

Yard is a length measurement.

It is equal to 3 feet.

1feet12inches1yard3feet1inch2.54cm1mile5280feet

(b)

Expert Solution
Check Mark

Explanation of Solution

32.4yd can be converted into centimeters as follows,

32.4yard×36inches1yard×2.54cm1inches=2.96×103cm

Hence, 32.4yd can be converted into centimeters is 2.96×103cm.

(c)

Interpretation Introduction

Interpretation:

3.0×1010cm/s has to be converted into ft/s.

Concept introduction:

1inch2.54cm1feet12inches

(c)

Expert Solution
Check Mark

Explanation of Solution

3.0×1010cm/s can be converted into ft/s.

3.0×1010cm1s×1inch2.54cm×1feet12inches=9.8×108feet/s

Hence, 3.0×1010cm/s can be converted into ft/s is 9.8×108feet/s.

(d)

Interpretation Introduction

Interpretation:

47.40F has to be converted into degree Celsius.

Concept introduction:

0C=(0F32)×50C90F

(d)

Expert Solution
Check Mark

Explanation of Solution

47.40F has to be converted into degree Celsius

Use,

0C=(0F32)×50C90F

0C=(47.40F32)×50C90F=8.50C

47.40F is equal to 8.50C

(e)

Interpretation Introduction

Interpretation:

273.150C has to be converted into degree Fahrenheit.

Concept introduction:

0F=90C50F×(0C)+(320F)

(e)

Expert Solution
Check Mark

Explanation of Solution

273.150C has to be converted into degree Fahrenheit.

Use,

0F=90C50F×(0C)+(320F)

0F=90C50F×(273.150C)+(320F)=459.670F

273.150C is equal to 459.670F

(f)

Interpretation Introduction

Interpretation:

71.2cm3 to cubic meter has to be converted.

Concept Introduction:

The procedure that is used to convert between units in solving problems is called dimensional analysis.

By definition, 1cm3=1×106m3

(f)

Expert Solution
Check Mark

Explanation of Solution

Let’s consider the conversion of centimeter to cubic meter,

71.2cm3=?m3

By definition, 1cm3=1×106m3

So 71.2cm3=71.2×106m3=71.2×105m3

Thus 71.2cm3 is equal to 71.2×105m3

(f)

Interpretation Introduction

Interpretation:

7.2m3 to liters has to be converted.

Concept Introduction:

The procedure that is used to convert between units in solving problems is called dimensional analysis.

By definition, 1m3=1×103Litre

(f)

Expert Solution
Check Mark

Explanation of Solution

Let’s consider the conversion of meter cubic to litre,

7.2m3=?L

By definition, 1m3=1×103Litre

So 7.2m3=7.2×103Litre=7200L

Thus 7.2m3 is equal to 7200L

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Chapter 1 Solutions

General Chemistry

Ch. 1.7 - Prob. 2PECh. 1.7 - Prob. 1RCCh. 1 - Prob. 1.1QPCh. 1 - Prob. 1.2QPCh. 1 - Prob. 1.3QPCh. 1 - Prob. 1.4QPCh. 1 - Prob. 1.5QPCh. 1 - Prob. 1.6QPCh. 1 - 1.7 Do these statements describe chemical or...Ch. 1 - 1.8 Does each of these describe a physical change...Ch. 1 - Prob. 1.9QPCh. 1 - Prob. 1.10QPCh. 1 - 1.11 Classify each of these substances as an...Ch. 1 - Prob. 1.12QPCh. 1 - Prob. 1.13QPCh. 1 - Prob. 1.14QPCh. 1 - Prob. 1.15QPCh. 1 - Prob. 1.16QPCh. 1 - Prob. 1.17QPCh. 1 - Prob. 1.18QPCh. 1 - Prob. 1.19QPCh. 1 - Prob. 1.20QPCh. 1 - Prob. 1.21QPCh. 1 - Prob. 1.22QPCh. 1 - Prob. 1.23QPCh. 1 - Prob. 1.24QPCh. 1 - Prob. 1.25QPCh. 1 - Prob. 1.26QPCh. 1 - Prob. 1.27QPCh. 1 - Prob. 1.28QPCh. 1 - Prob. 1.29QPCh. 1 - Prob. 1.30QPCh. 1 - Prob. 1.31QPCh. 1 - Prob. 1.32QPCh. 1 - 1.33 The price of gold on a certain day in 2009...Ch. 1 - Prob. 1.34QPCh. 1 - Prob. 1.35QPCh. 1 - Prob. 1.36QPCh. 1 - Prob. 1.37QPCh. 1 - Prob. 1.38QPCh. 1 - Prob. 1.39QPCh. 1 - Prob. 1.40QPCh. 1 - Prob. 1.41QPCh. 1 - Prob. 1.42QPCh. 1 - Prob. 1.43QPCh. 1 - Prob. 1.44QPCh. 1 - Prob. 1.45QPCh. 1 - Prob. 1.46QPCh. 1 - Prob. 1.47QPCh. 1 - Prob. 1.48QPCh. 1 - Prob. 1.49QPCh. 1 - Prob. 1.50QPCh. 1 - Prob. 1.51QPCh. 1 - Prob. 1.52QPCh. 1 - Prob. 1.53QPCh. 1 - Prob. 1.54QPCh. 1 - Prob. 1.55QPCh. 1 - Prob. 1.56QPCh. 1 - Prob. 1.57QPCh. 1 - Prob. 1.58QPCh. 1 - Prob. 1.59QPCh. 1 - Prob. 1.60QPCh. 1 - Prob. 1.61QPCh. 1 - Prob. 1.62QPCh. 1 - Prob. 1.63QPCh. 1 - Prob. 1.64QPCh. 1 - Prob. 1.65QPCh. 1 - 1.66 A sheet of aluminum (Al) foil has a total...Ch. 1 - Prob. 1.67QPCh. 1 - Prob. 1.68QPCh. 1 - Prob. 1.69QPCh. 1 - Prob. 1.70QPCh. 1 - Prob. 1.71QPCh. 1 - Prob. 1.73SPCh. 1 - Prob. 1.74SPCh. 1 - Prob. 1.75SPCh. 1 - Prob. 1.76SPCh. 1 - 1.77 A pycnometer is a device for measuring the...Ch. 1 - Prob. 1.78SPCh. 1 - Prob. 1.79SPCh. 1 - Prob. 1.80SPCh. 1 - Prob. 1.81SP
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