It is well known that wind makes the cold air feel much colder as a result of the wind-chill effect that is due to the increase in the convection heat transfer coefficient with increasing air velocity. The wind-chill effect is usually expressed in terms of the wind-chill temperature (WCT), which is the apparent temperature felt by exposed skin. For an outdoor air temperature of 0 o C, for example, the wind-chill temperature is − 5 o C with 20 km/h winds and − 9 o C with 60 km/h winds. That is, a person exposed to 0 o C windy air at 20 km/h will feel as cold as a person exposed to − 5 o C calm air (air motion under 5 km/h). For heat transfer purposes, a standing man can be modeled as a 30-cm-diameter, 170-cm-long vertical cylinder with both the top and bottom surfaces insulated and with the side surface at an average temperature of 34 o C . and For a convection heat transfer coefficient of 15 W/m 2. K, determine the rate of heat loss from this man by convection in still air at 20 o C . and What would your answer be if the convection heat transfer coefficient is increased to 30 W/m 2. K as a result of winds? What is the wind-chill temperature in this case?
It is well known that wind makes the cold air feel much colder as a result of the wind-chill effect that is due to the increase in the convection heat transfer coefficient with increasing air velocity. The wind-chill effect is usually expressed in terms of the wind-chill temperature (WCT), which is the apparent temperature felt by exposed skin. For an outdoor air temperature of 0 o C, for example, the wind-chill temperature is − 5 o C with 20 km/h winds and − 9 o C with 60 km/h winds. That is, a person exposed to 0 o C windy air at 20 km/h will feel as cold as a person exposed to − 5 o C calm air (air motion under 5 km/h). For heat transfer purposes, a standing man can be modeled as a 30-cm-diameter, 170-cm-long vertical cylinder with both the top and bottom surfaces insulated and with the side surface at an average temperature of 34 o C . and For a convection heat transfer coefficient of 15 W/m 2. K, determine the rate of heat loss from this man by convection in still air at 20 o C . and What would your answer be if the convection heat transfer coefficient is increased to 30 W/m 2. K as a result of winds? What is the wind-chill temperature in this case?
It is well known that wind makes the cold air feel much colder as a result of the wind-chill effect that is due to the increase in the convection heat transfer coefficient with increasing air velocity. The wind-chill effect is usually expressed in terms of the wind-chill temperature (WCT), which is the apparent temperature felt by exposed skin. For an outdoor air temperature of
0
o
C,
for example, the wind-chill temperature is
−
5
o
C
with 20 km/h winds and
−
9
o
C
with 60 km/h winds. That is, a person exposed to
0
o
C
windy air at 20 km/h will feel as cold as a person exposed to
−
5
o
C
calm air (air motion under 5 km/h).
For heat transfer purposes, a standing man can be modeled as a 30-cm-diameter, 170-cm-long vertical cylinder with both the top and bottom surfaces insulated and with the side surface at an average temperature of
34
o
C
.
and For a convection heat transfer coefficient of 15 W/m2. K, determine the rate of heat loss from this man by convection in still air at
20
o
C
.
and What would your answer be if the convection heat transfer coefficient is increased to 30 W/m2. K as a result of winds? What is the wind-chill temperature in this case?
3 kN
3 kN
1.8 kN/m
80 mm
B
300 mm
D
an
1.5 m-1.5 m--1.5 m-
PROBLEM 5.47
Using the method of Sec. 5.2, solve Prob. 5.16
PROBLEM 5.16 For the beam and loading shown, determine the
maximum normal stress due to bending on a transverse section at C.
300 mm
3 kN
3 kN
450 N-m
D
E
200 mm
300 mm
PROBLEM 5.12
Draw the shear and bending-moment diagrams for the beam and loading
shown, and determine the maximum absolute value (a) of the shear,
(b) of the bending moment.
CORRECT AND DETAILED SOLUTION WITH FBD ONLY. I WILL UPVOTE THANK YOU. CORRECT ANSWER IS ALREADY PROVIDED. I REALLY NEED FBD.
The cantilevered spandrel beam shown whose depth tapers from d1 to d2, has a constant width of 120mm. It carries a triangularly distributed end reaction.Given: d1 = 600 mm, d2 = 120 mm, L = 1 m, w = 100 kN/m1. Calculate the maximum flexural stress at the support, in kN-m.2. Determine the distance (m), from the free end, of the section with maximum flexural stress.3. Determine the maximum flexural stress in the beam, in MPa.ANSWERS: (1) 4.630 MPa; (2) 905.8688 m; (3) 4.65 MPa
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