Catalytic converters use nanoscale particles of precious metals such as platinum to change pollutants in carexhaust into less harmful gases. Calculate the following quantities for a spherical particle of platinum with a diameter of 5.0 nm. (a) Surface area in units of μ m 2 ( S A = 4 π r 2 ) (b) Volume in units of μ m 3 ( V = 4 3 π r 3 ) (c)Surface area to volume ratio in units of μ m − 1 (d)A 5.0 μ m diameterparticle has a surface area to volume ratioof 0.6 μ m − 1 . How many times larger is the surface area to volume ratio of the 5.0 nm particle than the 5.0 μ m particle?
Catalytic converters use nanoscale particles of precious metals such as platinum to change pollutants in carexhaust into less harmful gases. Calculate the following quantities for a spherical particle of platinum with a diameter of 5.0 nm. (a) Surface area in units of μ m 2 ( S A = 4 π r 2 ) (b) Volume in units of μ m 3 ( V = 4 3 π r 3 ) (c)Surface area to volume ratio in units of μ m − 1 (d)A 5.0 μ m diameterparticle has a surface area to volume ratioof 0.6 μ m − 1 . How many times larger is the surface area to volume ratio of the 5.0 nm particle than the 5.0 μ m particle?
Solution Summary: The author explains that nanotechnology is a field that studies the atoms and molecules on the nano-scale.
Catalytic converters use nanoscale particles of precious metals such as platinum to change pollutants in carexhaust into less harmful gases. Calculate the following quantities for a spherical particle of platinum with a diameter of 5.0 nm. (a) Surface area in units of
μ
m
2
(
S
A
=
4
π
r
2
)
(b) Volume in units of
μ
m
3
(
V
=
4
3
π
r
3
)
(c)Surface area to volume ratio in units of
μ
m
−
1
(d)A
5.0
μ
m
diameterparticle has a surface area to volume ratioof
0.6
μ
m
−
1
. How many times larger is the surface area to volume ratio of the 5.0 nm particle than the
5.0
μ
m
particle?
Predict the major products of this organic reaction:
HBr (1 equiv)
cold
?
Some important notes:
• Draw the major product, or products, of this reaction in the drawing area below.
• You can draw the products in any arrangement you like.
• Pay careful attention to the reaction conditions, and only include the major products.
• Be sure to use wedge and dash bonds when necessary, for example to distinguish between major products that are enantiomers.
• Note that there is only 1 equivalent of HBr reactant, so you need not consider the case of multiple additions.
Erase something
Explanation
Check
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Q14. Fill this chart: (please refer to ppt notes/browser to answer these questions)
What alcohol is also called wood alcohol?
What is the common name of ethanol?
Draw the structure of phenol and thiophene?
Are bigger chain alcohol like heptanol and octanol
are soluble or insoluble in water and explain it ?
Are ethers soluble or insoluble in water?
What suffix and prefix are used for alcohol while
naming alcohol and ether?
What the process called when we add water to any
alkene to make alcohol?
Q16. Draw the diagram of following aromatic compound (practice from previous module)
Aniline
Phenol
Benzoic acid
Methyl benzoate
Q17. a. Write the oxidation reactions for the 2 propanol.
b. Write the oxidation reaction of the ethanol.
Question 11 of 18 (1 point) Question Attempt: 3 of
How many signals do you expect in the 'H NMR spectrum for this molecule?
Br
Br
Write the answer below.
Also, in each of the drawing areas below is a copy of the molecule, with Hs shown. In each copy, one of the H atoms is colored red. Highlight in red all other H
atoms that would contribute to the same signal as the H already highlighted red.
Note for advanced students: In this question, any multiplet is counted as one signal.
Number of signals in the 'H NMR spectrum.
1
For the molecule in the top drawing area, highlight in red any other H atoms that will contribute to
the same signal as the H atom already highlighted red.
If no other H atoms will contribute, check the box at right.
No additional Hs to color in top
molecule
Check
For the molecule in the bottom drawing area, highlight in red any other H atoms that will contribute
to the same signal as the H atom already highlighted red.
If no other H atoms will contribute, check the box…
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