Chapter 1, Problem 1.1P

The floor of a heavy storage warehouse building is made of 6-in.-thick stone concrete. If the floor is a slab having a length of 15 ft and width of 10 ft, determine the resultant force caused by the dead load and the live load.

To determine

Resultant force due to dead load and live load.

Answer to Problem 1.1P

Resultant force = $\text{215 kN}$

Explanation of Solution

Given information:

Floor thickness $=6\text{ in = 0}\text{.15 m}$

Length of the floor $=15\text{ ft = 4}\text{.572 m}$

The width of the floor $=10\text{ ft = 3 m}$

A dead load of the floor is calculated by multiplying the unit weight of concrete with the dimensions of the slab and the Live load for heavy storage warehouse building is taken from the ASCE-7

Calculation:

Imposed load for a heavy storage warehouse $=250{\text{ lb/ft}}^2$

Live load for heavy storage warehouse = $250\times 10\times 15=37500\text{ lb}$

Minimum Design Dead load of stone concrete per inch $=12{\text{ lb/ft}}^2$

Dead load on the warehouse floor of 6 inches thick $=12\times \text{15}\times \text{10}\times 6=10800\text{ lb}$

Total load = Dead load + Live load $=10800+37500=48300\text{ lb}$

Resultant force $=48300\text{ lb = 214}\text{.85 kN}\sim \text{215 kN}$

Conclusion:

The resultant force thus obtained is $\text{215 kN}$