Heating Ventilating and Air Conditioning: Analysis and Design
Heating Ventilating and Air Conditioning: Analysis and Design
6th Edition
ISBN: 9780471470151
Author: Faye C. McQuiston, Jeffrey D. Spitler, Jerald D. Parker
Publisher: Wiley, John & Sons, Incorporated
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Textbook Question
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Chapter 1, Problem 1.1P

Convert the following quantities from English to SI units:

a. 98 Btu/(hr-ft-F)

b. 0.24 Btu/(lbm-F)

C. 0.04 Ibm/(ft-hr)

d. 1050 Btu/lbm

e. 1.0 ton (cooling)

f. 14.7 lbf/in.2

(a)

Expert Solution
Check Mark
To determine

To Convert: 98Btu/(hr-ft-F) from English to SI units.

Answer to Problem 1.1P

Thequantity in SI units is, 169.6W/m-k .

Explanation of Solution

Given:

The given quantity is,

  98Btu/(hr-ft-F)

Calculation:

Consider the given quantity.

  98Btu/(hr-ft-F)

Convert the quantity to SI units.

  98Btu/hr=0.2931W1ft=0.3048m1F=255.93K

The quantity in SI units is converted as,

  98Btu/(hr-ft-F)=98×1.7307W/m-k=169.6W/m-k

(b)

Expert Solution
Check Mark
To determine

To convert: 0.24Btu/(lbm-F) from English to SI units.

Answer to Problem 1.1P

The quantity in SI units is 1kJ/kg-°C .

Explanation of Solution

Given:

The given quantity is,

  0.24Btu/(lbm-F)

Calculation:

Consider the given quantity.

  0.24Btu/(lbm-F)

Convert the quantity to SI units.

  1Btu/lbm-F=4.1868kJ/kg-°C

The quantity in SI units is converted as,

  0.24Btu/(lbm-F)=0.24×4.1868kJ/kg-°C=1.004kJ/kg-°C1kJ/kg-°C

(c)

Expert Solution
Check Mark
To determine

To convert: 0.04lbm/(ft-hr) from English to SI units.

Answer to Problem 1.1P

The quantity in SI units is 16.5×106kg/m-s .

Explanation of Solution

Given:

The given quantity is,

  0.04lbm/(ft-hr)

Calculation:

Consider the given quantity.

  0.04lbm/(ft-hr)

Convert the quantity to SI units.

  1lbm=0.4536kg1ft=0.3048m

The quantity in SI units is converted as,

  0.04lbm/(ft-hr)=0.04×0.4536kg×10.3048m×3600s=16.5×106kg/m-s

(d)

Expert Solution
Check Mark
To determine

To convert: 1050Btu/lbm from English to SI units.

Answer to Problem 1.1P

The quantity in SI units is 2442.3J/g .

Explanation of Solution

Given:

The given quantity is,

  1050Btu/lbm

Calculation:

Consider the given quantity.

  1050Btu/lbm

Convert the quantity to SI units.

  1Btu/lbm=2.326J/g

The quantity in SI units is converted as,

  1050Btu/lbm=1050×2.326J/g=2442.3J/g

(e)

Expert Solution
Check Mark
To determine

To convert: 1.0ton(cooling) from English to SI units.

Answer to Problem 1.1P

The quantity in SI units is 3.517kW .

Explanation of Solution

Given:

The given quantity is,

  1.0ton(cooling)

Calculation:

Consider the given quantity.

  1.0ton(cooling)

Convert the quantity to SI units.

  1.0ton(cooling)=200Btu/min1Btu/min=0.017585kW

The quantity in SI units is converted as,

  1.0ton(cooling)=200Btu/min×0.017585kW=3.517kW

(f)

Expert Solution
Check Mark
To determine

To convert: 14.7lbf/in2 from English to SI units.

Answer to Problem 1.1P

The quantity in SI units is 101356.5N/m2 .

Explanation of Solution

Given:

The given quantity is,

  14.7lbf/in2

Calculation:

Consider the given quantity.

  14.7lbf/in2

Convert the quantity to SI units.

  1lbf/in2=1psi1psi=6895N/m2

The quantity in SI units is converted as,

  14.7lbf/in2=14.7×6895N/m2=101356.5N/m2

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