
Concept explainers
(a)
Interpretation: The given properties are to be categorized as physical and chemical properties of Hydrogen.
Concept introduction: The property that does not involve any change in chemical composition is called physical property of matter while the property that involves the change in chemical composition is called chemical property of matter.
To determine: If the low density of Hydrogen gas at room temperature in comparison to other gases is its physical or chemical property.
(b)
To determine: If the reaction of Hydrogen gas with Oxygen for the formation of water is its physical property or chemical property.
(c)
To determine: If boiling of Hydrogen gas at low temperature is its physical or chemical property.
(d)
To determine: If the non-conductivity of electricity by Hydrogen gas is its physical or chemical property.

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Chapter 1 Solutions
CHEMISTRY:SCI.IN CONTEXT (CL)-PACKAGE
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- From the following potentials, calculate the activity of Cl- in saturated KCl. E0 (calomel electrode)= 0.268 V E (calomel electrode, saturated KCl)= 0.241 Varrow_forwardCalculate the voltage of each of the following cells. a) Fe(s)/Fe2+ (1.55 x 10-2 M)//Cu2+ (6.55 x 10-3 M)/Cu(s) b) Pt, H2 (0.255 bar)/HCl (4.55 x 10-4 M), AgCl (sat'd)/Ag Fe2+ +2e- = Fe E0= -0.44 V Cu2+ + 2e- = Cu E0= 0.337 V Ag+ + e- = Ag E0= 0.799 V AgCl(s) + e- = Ag(s) + Cl- E0= 0.222 V 2H+ + 2e- = H2 E0= 0.000 Varrow_forwardA solution contains 0.097 M Ce3+, 1.55x10-3 M Ce4+, 1.55x10-3 M Mn2+, 0.097 M MnO4-, and 1.00 M HClO4 (F= 9.649 x 104 C/mol). a) Write a balanced net reaction that can occur between species in this solution. b) Calculate deltaG0 and K for the reaction. c) Calculate E and deltaG for the conditions given. Ce4+ + e- = Ce3+ E0= 1.70 V MnO4- + 8H+ + 5e- = Mn2+ + 4H2O E0= 1.507 Varrow_forward
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