Chapter 1, Problem 1.134QP

(a)

Interpretation Introduction

Interpretation:

The distance in angstrom has to be converted to micrometers.

Concept Introduction:

Conversion-factor method is the one which can be used to convert one metric unit into another.  With this, any unit can be converted to another unit by means of ratio.  The ratio that is used to convert unit is known as conversion-factor.  For example, one kilogram can be converted into gram by multiplying with 1000.

Answer to Problem 1.134QP

The given distance in angstrom is converted to micrometers as $\text{1}\text{.27 }\text{×}{\text{10}}^{\text{-2}}\text{μm}$.

Explanation of Solution

Given distance in problem statement is $\text{127 Å}$.

Since, $\text{1}\text{Å}\text{=}{\text{10}}^{-10}\text{m}$ and $\text{1}\text{mg}\text{=}{\text{10}}^{\text{-3}}\text{g}$, we can use this to convert the above unit in micrograms,

$\text{127 Å × }\frac{{\text{10}}^{\text{-10}}\text{ m}}{\text{1 Å}}\text{ × }\frac{\text{1 μm}}{{\text{10}}^{\text{-6}}\text{ m}}\text{=}\text{1}\text{.27}\text{×}{\text{10}}^{\text{-2}}\text{μm}$

The given distance was converted into micrometers as shown above.

(b)

Interpretation Introduction

Interpretation:

The mass in kilogram has to be converted to micrograms.

Concept Introduction:

Conversion-factor method is the one which can be used to convert one metric unit into another.  With this, any unit can be converted to the another unit by means of ratio.  The ratio that is used to convert unit is known as conversion-factor.  For example, one kilogram can be converted into gram by multiplying with 1000.

Answer to Problem 1.134QP

The given mass in kilogram is converted to milligrams as $\text{2}\text{.10 }\text{×}{\text{10}}^7\text{mg}$.

Explanation of Solution

Given mass in problem statement is $\text{21}\text{.0 kg}$.

Since, $\text{1}\text{kg}\text{=}{\text{10}}^{\text{3}}\text{g}$ and $\text{1}\text{mg}\text{=}{\text{10}}^{\text{-3}}\text{g}$, we can use this to convert the above unit in milligrams,

$\text{21}\text{.0 kg × }\frac{{\text{10}}^{\text{3}}\text{ g}}{\text{1 kg}}\text{ × }\frac{\text{1 mg}}{{\text{10}}^{\text{-3}}\text{ g}}\text{=}2.10\text{×}{\text{10}}^7\text{mg}$

The given mass was converted into milligrams as shown above.

(c)

Interpretation Introduction

Interpretation:

The distance in centimeters has to be converted to millimeters.

Concept Introduction:

Conversion-factor method is the one which can be used to convert one metric unit into another.  With this, any unit can be converted to another unit by means of ratio.  The ratio that is used to convert unit is known as conversion-factor.  For example, one kilogram can be converted into gram by multiplying with 1000.

Answer to Problem 1.134QP

The given centimeters is converted to millimeters as $\text{10}\text{.9}\text{mm}$.

Explanation of Solution

Given distance in problem statement is $\text{1}\text{.09 cm}$.

Since, $\text{1}\text{cm}\text{=}{\text{10}}^{\text{-2}}\text{m}$ and $\text{1}\text{mm}\text{=}{\text{10}}^{\text{-3}}\text{m}$, we can use this to convert the above unit in millimeters,

$\text{1}\text{.09 cm × }\frac{{\text{10}}^{-2}\text{ m}}{\text{1 cm}}\text{ × }\frac{\text{1 mm}}{{\text{10}}^{\text{-3}}\text{ m}}\text{=}\text{10}\text{.9}\text{mm}$

The given distance was converted into millimeters as shown above.

(d)

Interpretation Introduction

Interpretation:

The time in nanoseconds has to be converted to microseconds.

Concept Introduction:

Conversion-factor method is the one which can be used to convert one metric unit into another.  With this, any unit can be converted to another unit by means of ratio.  The ratio that is used to convert unit is known as conversion-factor.  For example, one kilogram can be converted into gram by multiplying with 1000.

Answer to Problem 1.134QP

The given nanoseconds is converted to microseconds as $\text{4}{\text{.6 × 10}}^{\text{-3}}\text{ μs}$.

Explanation of Solution

Given time in problem statement is $\text{4}\text{.6 ns}$.

Since, $\text{1}\text{ns}\text{=}{\text{10}}^{\text{-9}}\text{s}$ and $\text{1}\text{μs}\text{=}{\text{10}}^{\text{-3}}\text{s}$, we can use this to convert the above unit in microseconds,

$\text{4}\text{.6 ns × }\frac{{\text{10}}^{\text{-9}}\text{ s}}{\text{1 ns}}\text{ × }\frac{\text{1 μs}}{{\text{10}}^{\text{-6}}\text{ μs}}\text{=}\text{4}{\text{.6 × 10}}^{\text{-3}}\text{ μs}$

The given time was converted into micrometers as shown above.