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High School Math Calculus Advanced Placement Calculus Graphical Numerical Algebraic Sixth Edition High School Binding Copyright 2020

Solve the equations simultaneously by an algebraic method, either substitution or elimination. Write the conclusion.

Solve the equations simultaneously by an algebraic method, either substitution or elimination. Write the conclusion.

Solution Summary: The author explains that the system of equations is dependent and inconsistent. Elimination gives an equation that is always false.

Advanced Placement Calculus Graphical Numerical Algebraic Sixth Edition High School Binding Copyright 2020

Advanced Placement Calculus Graphical Numerical Algebraic Sixth Edition High School Binding Copyright 2020

6th Edition

ISBN: 9781418300203

Author: Prentice Hall

Publisher: Prentice Hall

See similar textbooks

Question

Chapter 0.1, Problem 53E

(a)

To determine

To find: Solve the equations simultaneously by an algebraic method, either substitution or elimination. Write the conclusion.

(a)

Expert Solution

Answer to Problem 53E

The system has no solution.it is an inconsistent system.

Explanation of Solution

Given information:

The given system of equation is 3x−5y=3,−9x+15y=8 .This system of equation is dependent and inconsistent.

Concept used: Elimination method to find the solution of system is used.

Calculation:

The given equations are:

3x−5y=3 ...(1)−9x+15y=8....2

Multiply equation (1) by 3 it gives:

9x−15y=9.....(3)

Now add equation 2 and (3)

−9x+9x+15y−15y=8+9 0+0=17 0=17

Elimination gives an equation that is always false. Hence the system has no solution.

Now check the condition of inconsistency that is if there is a system of equation

a1x+b1y=ca2x+b2y=c

Then the system is inconsistent and represent parallel line if:

a1a2=b1b2≠c1c2

Check this condition with the given system of equation it gives:

3−9=−515≠381−3=−13≠38

The system of equation satisfies the above condition of inconsistency hence the system has no solution.

(b)

To determine

To find: The solution of the equation of system by graph.

(b)

Expert Solution

Answer to Problem 53E

The system is consistent

Explanation of Solution

Given information:

The given system of equation is 3x−5y=3,−9x+15y=8 .This system of equation is dependent and inconsistent.

Calculation:

To draw the graph of the equation 3x−5y=3,−9x+15y=8 . Substitute different values of x to find the corresponding values of y .

The graph of the above equation is given below.

Advanced Placement Calculus Graphical Numerical Algebraic Sixth Edition High School Binding Copyright 2020, Chapter 0.1, Problem 53E

As it is clear from the graph that two lines are parallel hence there is no solution of this system of equation has no solution.

Chapter 0.1, Problem 52E

Chapter 0.1, Problem 54E

Chapter 0 Solutions

Advanced Placement Calculus Graphical Numerical Algebraic Sixth Edition High School Binding Copyright 2020

Ch. 0.1 - Prob. 1QR Ch. 0.1 - Prob. 2QR Ch. 0.1 - Prob. 3QR Ch. 0.1 - Prob. 4QR Ch. 0.1 - Prob. 5QR Ch. 0.1 - Prob. 6QR Ch. 0.1 - Prob. 7QR Ch. 0.1 - Prob. 8QR Ch. 0.1 - Prob. 9QR Ch. 0.1 - Prob. 10QR

Ch. 0.1 - Prob. 1E Ch. 0.1 - Prob. 2E Ch. 0.1 - Prob. 3E Ch. 0.1 - Prob. 4E Ch. 0.1 - Prob. 5E Ch. 0.1 - Prob. 6E Ch. 0.1 - Prob. 7E Ch. 0.1 - Prob. 8E Ch. 0.1 - Prob. 9E Ch. 0.1 - Prob. 10E Ch. 0.1 - Prob. 11E Ch. 0.1 - Prob. 12E Ch. 0.1 - Prob. 13E Ch. 0.1 - Prob. 14E Ch. 0.1 - Prob. 15E Ch. 0.1 - Prob. 16E Ch. 0.1 - Prob. 17E Ch. 0.1 - Prob. 18E Ch. 0.1 - Prob. 19E Ch. 0.1 - Prob. 20E Ch. 0.1 - Prob. 21E Ch. 0.1 - Prob. 22E Ch. 0.1 - Prob. 23E Ch. 0.1 - Prob. 24E Ch. 0.1 - Prob. 25E Ch. 0.1 - Prob. 26E Ch. 0.1 - Prob. 27E Ch. 0.1 - Prob. 28E Ch. 0.1 - Prob. 29E Ch. 0.1 - Prob. 30E Ch. 0.1 - Prob. 31E Ch. 0.1 - Prob. 32E Ch. 0.1 - Prob. 33E Ch. 0.1 - Prob. 34E Ch. 0.1 - Prob. 35E Ch. 0.1 - Prob. 36E Ch. 0.1 - Prob. 37E Ch. 0.1 - Prob. 38E Ch. 0.1 - Prob. 39E Ch. 0.1 - Prob. 40E Ch. 0.1 - Prob. 41E Ch. 0.1 - Prob. 42E Ch. 0.1 - Prob. 43E Ch. 0.1 - Prob. 44E Ch. 0.1 - Prob. 45E Ch. 0.1 - Prob. 46E Ch. 0.1 - Prob. 47E Ch. 0.1 - Prob. 48E Ch. 0.1 - Prob. 49E Ch. 0.1 - Prob. 50E Ch. 0.1 - 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Prob. 61E Ch. 0.6 - Prob. 62E Ch. 0.6 - Prob. 1QQ Ch. 0.6 - Prob. 2QQ Ch. 0.6 - Prob. 3QQ Ch. 0.6 - Prob. 4QQ Ch. 0 - Prob. 1RWDT Ch. 0 - Prob. 2RWDT Ch. 0 - Prob. 3RWDT Ch. 0 - Prob. 4RWDT Ch. 0 - Prob. 5RWDT Ch. 0 - Prob. 6RWDT Ch. 0 - Prob. 7RWDT Ch. 0 - Prob. 8RWDT Ch. 0 - Prob. 9RWDT Ch. 0 - Prob. 10RWDT Ch. 0 - Prob. 1RE Ch. 0 - Prob. 2RE Ch. 0 - Prob. 3RE Ch. 0 - Prob. 4RE Ch. 0 - Prob. 5RE Ch. 0 - Prob. 6RE Ch. 0 - Prob. 7RE Ch. 0 - Prob. 8RE Ch. 0 - Prob. 9RE Ch. 0 - Prob. 10RE Ch. 0 - Prob. 11RE Ch. 0 - Prob. 12RE Ch. 0 - Prob. 13RE Ch. 0 - Prob. 14RE Ch. 0 - Prob. 15RE Ch. 0 - Prob. 16RE Ch. 0 - Prob. 17RE Ch. 0 - Prob. 18RE Ch. 0 - Prob. 19RE Ch. 0 - Prob. 20RE Ch. 0 - Prob. 21RE Ch. 0 - Prob. 22RE Ch. 0 - Prob. 23RE Ch. 0 - Prob. 24RE Ch. 0 - Prob. 25RE Ch. 0 - Prob. 26RE Ch. 0 - Prob. 27RE Ch. 0 - Prob. 28RE Ch. 0 - Prob. 29RE Ch. 0 - Prob. 30RE Ch. 0 - Prob. 31RE Ch. 0 - Prob. 32RE Ch. 0 - Prob. 33RE Ch. 0 - Prob. 34RE Ch. 0 - Prob. 35RE Ch. 0 - Prob. 36RE Ch. 0 - Prob. 37RE Ch. 0 - 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